/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 For each of the following, state... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For each of the following, state whether a one-proportion \(z\) -test or a two- proportion \(z\) -test would be appropriate, and name the population(s). a. A polling agency takes a random sample of voters in California to determine if a ballot proposition will pass. b. A researcher asks a random sample of residents from coastal states and a random sample of residents of non-coastal states whether they favor increased offshore oil drilling. The researcher wants to determine if there is a difference in the proportion of residents who support off-shore drilling in the two regions.

Short Answer

Expert verified
Scenario A: Appropriate test-One-proportion z-test, Population-Voters in California. Scenario B: Appropriate test-Two-proportion z-test, Populations-Residents from coastal states and residents from non-coastal states.

Step by step solution

01

Identify the Test and Population for Scenario A

In the first scenario, a polling agency is observing a single population (voters in California), thus the appropriate statistical test would be a one-proportion z-test. The population consists of voters in California.
02

Identify the Test and Population for Scenario B

In the second scenario, a researcher is observing two populations (residents from coastal states and residents from non-coastal states) and comparing their proportions on the same characteristic, thus the appropriate statistical test would be a two-proportion z-test. The populations consist of residents from coastal states and residents from non-coastal states.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-Proportion Z-Test
The one-proportion z-test is a tool statisticians use to determine if an observed proportion is significantly different from a known or hypothesized proportion. For instance, a polling agency might want to understand if the proportion of voters in favor of a ballot proposition in California differs from the proportion they expected.

Using sample data, the test calculates a z-score which indicates how many standard deviations the observed proportion is from the expected proportion. If the z-score falls outside the range of typical values—typically judged by a confidence level, like 95% or 99%—the difference is considered statistically significant.

This test requires the assumption that the sample is adequately large and drawn randomly, which helps ensure the results are reliable and can be generalized to the entire population of interest.
Two-Proportion Z-Test
When a study involves comparing proportions from two different populations, the two-proportion z-test steps onto the scene. It assesses whether the difference in proportions is statistically significant. Taking the scenario provided, a researcher could use this method to compare the support for offshore oil drilling between coastal and non-coastal residents.

The calculation process involves determining the standard error of the difference in proportions and subsequently computing a z-score. The larger this z-score, the more likely it is that any difference observed is not due to random chance but rather is an actual distinction between the two groups.

It's crucial with the two-proportion z-test, as with the one-proportion version, to use large enough and random samples for the comparison to have meaning and applicability to the broader populations.
Statistical Hypothesis Testing
At the heart of both one-proportion and two-proportion z-tests lies the concept of statistical hypothesis testing. This method allows researchers to make inferences about a population based on sample data. The process involves setting up two opposing hypotheses: the null hypothesis, which generally suggests that there is no effect or no difference; and the alternative hypothesis, indicating the presence of an effect or a difference.

After determining the appropriate test and calculating test statistics (like a z-score), researchers then consult a probability distribution to decide whether to reject the null hypothesis in favor of the alternative. The final step involves interpreting these results in the context of the research question to draw meaningful conclusions.

Hypothesis testing serves as a cornerstone of many scientific endeavors, providing a structured approach to decision-making with data.
Population Comparison
In research that encompasses population comparison, the aim is to understand how different populations stack up against each other regarding specific characteristics. The statistical tests chosen—whether one-proportion or two-proportion z-tests—serve as powerful tools for these comparisons.

Accurate comparisons rely on clear definitions of populations, like 'California voters' or 'coastal vs non-coastal residents', and ensuring that sampling biases are minimized. These comparisons can highlight significant differences, trends, and insights that are invaluable in fields such as public health, market research, and policy development.

Ultimately, whether dealing with one proportion or two, the comparison is about understanding the story the data tells us about the populations we are interested in.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A college chemistry instructor thinks the use of embedded tutors (tutors who work with students during regular class meeting times) will improve the success rate in introductory chemistry courses. The passing rate for introductory chemistry is \(62 \%\). The instructor will use embedded tutors in all sections of introductory chemistry and record the percentage of students passing the course. State the null and alternative hypotheses in words and in symbols. Use the symbol \(p\) to represent the passing rate for all introductory chemistry courses that use embedded tutors.

Suppose you are testing someone to see whether she or he can tell Coke from Pepsi, and you are using 20 trials, half with Coke and half with Pepsi. The null hypothesis is that the person is guessing. a. About how many should you expect the person to get right under the null hypothesis that the person is guessing? b. Suppose person A gets 13 right out of 20 , and person B gets 18 right out of 20 . Which will have a smaller \(\mathrm{p}\) -value, and why?

In a 2018 study reported in The Lancet, Molina et al. reported on a study for treatment of patients with HIV-1. The study was a randomized, controlled, double-blind study that compared the effectiveness of ritonavir-boosted darunavir (rbd), the drug currently used to treat HIV-1, with dorovirine, a newly developed drug. Of the 382 subjects taking ritonavir-boosted darunavir, 306 achieved a positive result. Of the 382 subjects taking dorovirine, 321 achieved a positive outcome. See page 430 for guidance. a. Find the sample percentage of subjects who achieved a positive outcome in each group. b. Perform a hypothesis test to test whether the proportion of patients who achieve a positive outcome with the current treatment (ritonavir-boosted darunavir) is different from the proportion of patients who achieve a positive outcome with the new treatment (dorovirine). Use a significance level of \(0.01\). Based on this study, do you think dorovirine might be a more effective treatment option for HIV-1 than ritonavir-boosted darunavir? Why or why not?

Suppose you are testing someone to see whether he or she can tell butter from margarine when it is spread on toast. You use many bite-sized pieces selected randomly, half from buttered toast and half from toast with margarine. The taster is blindfolded. The null hypothesis is that the taster is just guessing and should get about half right. When you reject the null hypothesis when it is actually true, that is often called the first kind of error. The second kind of error is when the null is false and you fail to reject. Report the first kind of error and the second kind of error.

A Gallup poll asked college students in 2016 and again in 2017 whether they believed the First Amendment guarantee of freedom of religion was secure or threatened in the country today. In 2016,2089 out of 3072 students surveyed said that freedom of religion was secure or very secure. In 2017,1929 out of 3014 students felt this way. a. Determine whether the proportion of college students who believe that freedom of religion is secure or very secure in this country has changed from \(2016 .\) Use a significance level of \(0.05\). b. Use the sample data to construct a \(95 \%\) confidence interval for the difference in the proportions of college students in 2016 and 2017 who felt freedom of religion was secure or very secure. How does your confidence interval support your hypothesis test conclusion?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.