/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 About \(30 \%\) of the populatio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

About \(30 \%\) of the population in Silicon Valley, a region in California, are between the ages of 40 and 65, according to the U.S. Census. However, only \(2 \%\) of the 2100 employees at a laid-off man's former Silicon Valley company are between the ages of 40 and \(65 .\) Lawyers might argue that if the company hired people regardless of their age, the distribution of ages would be the same as though they had hired people at random from the surrounding population. Check whether the conditions for using the one-proportion z-test are met.

Short Answer

Expert verified
Yes, the conditions for the one-proportion z-test are met because the sample size is large enough and we are assuming that the sample is randomly selected.

Step by step solution

01

Verify the Sampling Method

The first condition is that the sample should be randomly selected. In this problem, it is not clearly stated if the employees at the company were randomly selected or not from the population. However, the problem does mention that lawyers could argue that the company hired people as if it was random. For the sake of this problem, it will be assumed that this first condition is met.
02

Check the Sample Size

The second condition is that the sample size needs to be sufficiently large. It's generally accepted that a sample size is large enough for a one-proportion z-test if both \(n*p\) and \(n*(1-p)\) are greater than or equal to 10, where 'n' is the sample size and 'p' is the population proportion. In this case, \(n = 2100\) (the number of employees at the company) and \(p = 0.30\) (the proportion of population in Silicon Valley between the ages of 40 and 65). Calculating, \(n*p = 2100*0.30 = 630\) and \(n*(1-p) = 2100*0.70 = 1470\). Both values are greater than 10, so the sample size is large enough.
03

Conclusion

Based on the information given and assumptions made, it can be concluded that the conditions for conducting a one-proportion z-test are satisfied in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Method
Understanding the sampling method is essential when conducting a one-proportion z-test, as it's the first step in ensuring that the statistical analysis will be valid. The idea behind sampling methods is to select a subset of individuals from a population to infer conclusions about the entire population. The most reliable form of sampling for statistical tests is random sampling, where each member of the target population has an equal chance of being included in the sample.

In our example related to Silicon Valley employees, while the exercise scenario doesn't explicitly confirm the use of random sampling, it suggests that the lawyers assume a random-like selection process in the hiring practice. For our purposes, we presume random sampling to proceed with the analysis. It's crucial in real-world scenarios to establish the sampling method clearly, as deviations from randomness can introduce bias, undermining the validity of the conclusions drawn.
Sample Size in Statistics
Sample size plays a pivotal role in the accuracy and reliability of statistical tests, including the one-proportion z-test. The core principle is that the greater the sample size, the more it captures the characteristics of the population, translating to more precise estimates of population parameters.

To determine if a sample size is adequate for a one-proportion z-test, we typically use the rule of thumb that both the expected number of successes, given by the formula \(n \times p\), and the expected number of failures, \(n \times (1 - p)\), should be at least 10. In the exercise, with \(n = 2100\) employees and \(p = 0.30\) as the proportion of the population aged between 40 and 65, we calculated \(n \times p = 630\) and \(n \times (1 - p) = 1470\), satisfying this condition. This large sample size ensures that the test result will not be due to sampling variability and provides us with a firm ground to perform hypothesis testing.
Hypothesis Testing
Hypothesis testing is a structured process statisticians use to determine whether there is enough evidence in a sample of data to conclude that a certain condition holds true for the entire population. In the context of one-proportion z-test, hypothesis testing is applied to compare the sample proportion to a known proportion from the population to ascertain if there is a significant difference.

The process involves stating a null hypothesis, which typically asserts no effect or no difference, and an alternative hypothesis, which suggests the opposite. After calculating the test statistic from the sample data, we compare it to a critical value from the standard normal distribution. If the test statistic falls beyond this critical value, the null hypothesis is rejected, and we infer that the observed sample proportion is significantly different from the population proportion.

In our Silicon Valley study, this process would help determine whether the proportion of employees aged between 40 and 65 at the company indeed deviates from the regional average, potentially revealing an age bias in their hiring practices.

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Most popular questions from this chapter

Some experts believe that \(20 \%\) of all freshwater fish in the United States have such high levels of mercury that they are dangerous to eat. Suppose a fish market has 250 fish tested, and 60 of them have dangerous levels of mercury. Test the hypothesis that this sample is not from a population with \(20 \%\) dangerous fish. Use a significance level of \(0.05\). Comment on your conclusion: Are you saying that the percentage of dangerous fish is definitely \(20 \%\) ? Explain.

When comparing two sample proportions with a two-sided alternative hypothesis, all other factors being equal, will you get a smaller p-value with a larger sample size or a smaller sample size? Explain.

A true/false test has 50 questions. Suppose a passing grade is 35 or more correct answers. Test the claim that a student knows more than half of the answers and is not just guessing. Assume the student gets 35 answers correct out of \(50 .\) Use a significance level of \(0.05 .\) Steps 1 and 2 of a hypothesis test procedure are given. Show steps 3 and 4, and be sure to write a clear conclusion. Step $$\text { 1: } \begin{aligned}&\mathrm{H}_{0}: p=0.50 \\\&\mathrm{H}_{\mathrm{a}}: p>0.50\end{aligned}$$ Step 2: Choose the one-proportion \(z\) -test. Sample size is large enough, because \(n p_{0}\) is \(50(0.5)=25\) and \(n\left(1-p_{0}\right)=50(0.50)=25\), and both are more than \(10 .\) Assume the sample is random and \(\alpha=0.05\).

The National Association for Law Placement estimated that \(86.7 \%\) of law school graduates in 2015 found employment. An economist thinks the current employment rate for law school graduates is different from the 2015 rate. Pick the correct pair of hypotheses the economist could use to test this claim. \(\begin{aligned} \text { i. } \mathrm{H}_{0}: p \neq 0.867 & \text { ii. } \mathrm{H}_{0}: p &=0.867 \\ \mathrm{H}_{\mathrm{a}}: p=0.867 & \mathrm{H}_{\mathrm{a}}: p &>0.867 \\ \text { iii. } \mathrm{H}_{0}: p=0.867 & \text { iv. } \mathrm{H}_{0}: p &=0.867 \\ \mathrm{H}_{\mathrm{a}}: p<0.867 & \mathrm{H}_{\mathrm{a}}: p & \neq 0.867 \end{aligned}\)

A hospital readmission is an episode when a patient who has been discharged from a hospital is readmitted again within a certain period. Nationally the readmission rate for patients with pneumonia is \(17 \% .\) A hospital was interested in knowing whether their readmission rate for pneumonia was less than the national percentage. They found 11 patients out of 70 treated for pneumonia in a two-month period were readmitted. a. What is \(\hat{p}\), the sample proportion of readmission? b. Write the null and alternative hypotheses. c. Find the value of the test statistic and explain it in context. d. The p-value associated with this test statistic is \(0.39 .\) Explain the meaning of the \(\mathrm{p}\) -value in this context. Based on this result, does the \(\mathrm{p}\) -value indicate the null hypothesis should be doubted?

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