/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 To determine if patrons are sati... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

To determine if patrons are satisfied with performance quality, a theater surveys patrons at an evening performance by placing a paper survey inside their programs. All patrons receive a program as they enter the theater. Completed surveys are placed in boxes at the theater exits. On the evening of the survey, 500 patrons saw the performance. One hundred surveys were completed, and \(70 \%\) of these surveys indicated dissatisfaction with the performance. Should the theater conclude that patrons were dissatisfied with performance quality? Explain.

Short Answer

Expert verified
No, the theatre shouldn't conclude that the majority of the patrons were dissatisfied. Based on the data given, only 14% of all patrons indicated dissatisfaction. However, since not all patrons completed the survey, this data might not accurately represent the views of all patrons.

Step by step solution

01

Understand the provided data

On the given night, there were 500 patrons, out of which 100 completed the survey. Out of these 100, 70% were dissatisfied.
02

Calculate the actual number of dissatisfied patrons who completed the survey

70 percent of the respondents from the total of 100 were dissatisfied, it's calculated as: \(0.70 * 100 = 70\) patrons.
03

Determine the dissatisfaction rate among all patrons

Now calculate the dissatisfaction rate among all patrons, not just those who filled out the survey. This is done by dividing the number of dissatisfied patrons who completed surveys (70) by the total number of patrons (500). So, it's \(70/500 = 0.14\) or \(14%\)
04

Draw conclusions

An initial conclusion might state that 70% of patrons were dissatisfied with the performance based solely on completed survey data. However, in accurate terms, considering all the patrons who watched the performance that night, only 14% have shown dissatisfaction. This representation may or may not be say the overall satisfaction of the entire audience, considering that not everyone filled out the survey.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume your class has 30 students and you want a random sample of 10 of them. Describe how to randomly select 10 people from your class using the random number table.

Suppose you attend a school that offers both traditional courses and online courses. You want to know the average age of all the students. You walk around campus asking those students that you meet how old they are. Would this result in an unbiased sample?

From Formula \(7.2\), an estimate for margin of error for a \(95 \%\) confidence interval is \(m=2 \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\) where \(\mathrm{n}\) is the required sample size and \(\hat{p}\) is the sample proportion. Since we do not know a value for \(\hat{p}\), we use a conservative estimate of \(0.50\) for \(\hat{p}\). Replace \(\hat{p}\) with \(0.50\) in the formula and simplify.

The Perry Preschool Project was created in the early 1960 s by David Weikart in Ypsilanti, Michigan. In this project, 123 African American children were randomly assigned to one of two groups: One group enrolled in the Perry Preschool, and one group did not enroll. Follow-up studies were done for decades. One research question was whether attendance at preschool had an effect on high school graduation. The table shows whether the students graduated from regular high school or not and includes girls only (Schweinhart et al. 2005). $$\begin{array}{lcc}\hline & \text { Preschool } & \text { No Preschool } \\\\\hline \text { HS Grad } & 21 & 8 \\ \text { No HS Grad } & 4 & 17\end{array}$$ a. Find the percentages that graduated for both groups, and compare them descriptively. Does this suggest that preschool was associated with a higher graduation rate? b. Which of the conditions fail so that we cannot use a confidence interval for the difference between proportions?

\(1,3,5,7\), and 9 are odd and 0,2 , 4,6, and 8 are even. Consider a 30 -digit line from a random number table. a. How many of the 30 digits would you expect to be odd on average? b. If you actually counted, would you get exactly the number you predicted in part a? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.