/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 When two dice are rolled, is the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When two dice are rolled, is the event "the first die shows a 1 on top" independent of the event "the second die shows a 1 on top"?

Short Answer

Expert verified
Yes, the event 'the first die shows a 1 on top' is independent of the event 'the second die shows a 1 on top'.

Step by step solution

01

Define the Events and Their Probabilities

First, define Event A as 'the first die shows a 1 on top' and Event B as 'the second die shows a 1 on top'. The probability of rolling a 1 on a fair, six-sided die is \(\frac{1}{6}\), so \(P(A) = \frac{1}{6}\) and \(P(B) = \frac{1}{6}\).
02

Calculate the Joint Probability

Next, calculate the joint probability of the two events occurring together, denoted as \(P(A \cap B)\). Since the two dice rolls are independent of each other, the joint probability can be calculated as the product of the individual probabilities, i.e., \(P(A \cap B) = P(A) * P(B) = \frac{1}{6} * \frac{1}{6} = \frac{1}{36}\).
03

Check for Independence

Finally, check if the two events are independent. If the two events are indeed independent, the probability of both events occurring simultaneously is equal to the product of their individual probabilities, i.e., \(P(A \cap B) = P(A) * P(B)\). Since \(\frac{1}{36} = \frac{1}{6} * \frac{1}{6}\), the two events are independent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose all the days of the week are equally likely as birthdays. Alicia and David are two randomly selected, unrelated people. a. What is the probability that they were both born on Monday? b. What is the probability that Alicia OR David was born on Monday?

Probability For each of the values, state whether the number could be the probability of an event. Give a reason for your answers. a. \(99 \%\) b. \(0.9\) c. \(9.9\) d. \(0.0099\) e. \(-0.90\)

There are four suits: clubs ( ), diamonds ( ), hearts ( ), and spades ( ), and the following cards appear in each suit: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king. The jack, queen, and king are called face cards because they have a drawing of a face on them. Diamonds and hearts are red, and clubs and spades are black. If you draw 1 card randomly from a standard 52 -card playing deck, what is the probability that it will be the following: a. A heart b. A red card c. An ace d. A face card (jack, queen, or king) e. A three

The sample space shows all possible sequences of child gender for a family with 3 children. The table is organized by the number of girls in the family. $$ \begin{array}{llll} \hline \text { 0 Girls } & \text { 1 Girl } & \text { 2 Girls } & \text { 3 Girls } \\ \hline \text { BBB } & \text { GBB } & \text { BGG } & \text { GGG } \\ \hline & \text { BGB } & \text { GBG } & \\ \hline & \text { BBG } & \text { GGB } & \end{array} $$ a. How many outcomes are in the sample space? b. If we assume all outcomes in the sample space are equally likely, find the probability of having the following numbers of girls in a family of 3 children: i. all 3 girls ii. no girls iii. exactly 2 girls

A jury is supposed to represent the population. We wish to perform a simulation to determine an empirical probability that a jury of 12 people has 5 or fewer women. Assume that about \(50 \%\) of the population is female, so the probability that a person who is chosen for the jury is a woman is \(50 \%\). Using a random number table, we decide that each digit will represent a juror. The digits 0 through 5 , we decide, will represent a female chosen, and 6 through 9 will represent a male. Why this is a bad choice for this simulation?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.