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Mrs. Diaz has two children: a 3-yearold boy 43 inches tall and a 10 -year-old girl 57 inches tall. Threeyear-old boys have a mean height of 38 inches and a standard deviation of 2 inches, and 10 -year-old girls have a mean height of \(54.5\) inches and a standard deviation of \(2.5\) inches. Assume the distributions of boys' and girls' heights are unimodal and symmetric. Which of Mrs. Diaz's children is more unusually tall for his or her age and gender? Explain, showing any calculations you perform. (Source: www.kidsgrowth.com)

Short Answer

Expert verified
The Z-score for Mrs. Diaz’s son is 2.5 and the Z-score for Mrs. Diaz’s daughter is 1. The son's Z-score is higher than the daughter's, indicating that he is more unusually tall for his age and gender than his sister.

Step by step solution

01

Compute the Z-Score for Mrs. Diaz’s son

The z-score formula, \(Z = \frac{x - µ}{σ}\), is used where: \(x\) is the raw score, \(µ\) is the population mean, and \(σ\) is the standard deviation. Substituting the given values (43 inches is the son's height, 38 inches is the mean height, and 2 inches is the standard deviation), we get \(Z_{son} = \frac{43 - 38}{2}.\)
02

Compute the Z-Score for Mrs. Diaz’s daughter

The same formula as above is applied: \(Z = \frac{x - µ}{σ}\) where \(x\) is the raw score, \(µ\) is the population mean, and \(σ\) is the standard deviation. The given values are substituted (57 inches is the daughter's height, 54.5 inches is the mean height, and 2.5 inches is the standard deviation), resulting in \(Z_{daughter} = \frac{57 - 54.5}{2.5}.\)
03

Compare the Z-Scores

The Z-scores of Mrs Diaz's son and daughter are compared. The child with the higher Z-score is considered more unusually tall for their age and gender.

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