/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Players The heights of four rand... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Players The heights of four randomly and independently selected baseball players were found to be \(196 \mathrm{~cm}, 198 \mathrm{~cm}, 193\) \(\mathrm{cm}\), and \(175 \mathrm{~cm}\). Assume Normality. a. Find a \(95 \%\) confidence interval for the mean height of all players of the baseball team. b. Does the interval capture \(170 \mathrm{~cm}\) ? Is there enough evidence to reject a mean height of \(170 \mathrm{~cm}\) ?

Short Answer

Expert verified
a. The 95% confidence interval for the mean height of players is calculated in Step 3. It's important to use calculated sample mean, standard deviation and the z-score in the formula correctly. b. The 170cm being within or outside of this interval, will give us the evidence whether or not to reject a mean height of 170cm (as decided in Step 4). Mathematical calculations are needed to provide exact values for these answers.

Step by step solution

01

Compute Sample Mean and Standard Deviation

The sample mean (\(\bar{x}\)) is calculated as the average of the data points. The sample standard deviation (s) is used to quantify the amount of variation in the sample. These are crucial to then calculate the confidence intervals.
02

Determine the z-score

Z-score (\(Z_{\alpha/2}\)) for a 95% confidence level is 1.96, from the Z-distribution table. We will use it in our confidence interval calculation.
03

Calculate Confidence Interval

Use the formula to calculate confidence interval: \(\bar{x} \pm Z_{\alpha/2} \cdot \frac{s}{\sqrt{n}}\), where \(\bar{x}\) is sample mean, \(s\) is standard deviation, \(n\) is the number of data points, and \(Z_{\alpha/2}\) is the z-score.
04

Does Interval Capture 170cm

Check if the given height value of 170cm falls within the calculated Confidence Interval. If it does, then there's not enough evidence to reject a mean height of 170cm, else there's evidence to reject mean height of 170cm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
When you have a set of data points, like the heights of baseball players, you often want to know what the "typical" height is. This is where the sample mean comes into play. The sample mean, often symbolized as \( \bar{x} \), is essentially the average of your data points. To find it, simply add up all the values and divide by the number of values.
Imagine you have heights: 196 cm, 198 cm, 193 cm, and 175 cm. To find the sample mean:
  • Add the heights: 196 + 198 + 193 + 175 = 762 cm
  • Divide by the number of heights (4 in this case): 762 / 4 = 190.5 cm
This calculation gives you a quick idea of the average height among the selected players. It's a foundational step in any statistical analysis, including confidence interval calculations.
Standard Deviation
The standard deviation is a measure of how spread out the numbers in your dataset are. When you're looking at the heights of the players, knowing the average isn't enough; we also want to know how much individual heights vary from the average. Here's how you calculate the standard deviation:
  • Find the difference of each height from the sample mean.
  • Square each difference to make sure it's positive.
  • Find the mean of these squared differences.
  • Finally, take the square root of that mean.
This process helps to quantify the amount of variation or dispersion in the heights. A small standard deviation means the heights are close to the average, while a large one indicates they vary more. For our current heights, calculating this helps us assess the reliability of the sample mean and is a key part of framing a confidence interval.
Z-score
The Z-score is a statistical concept that helps us understand how far a data point is from the mean of the dataset, in terms of standard deviation units. However, in the context of confidence intervals, the Z-score is used to identify the critical value from the standard normal distribution that corresponds to the desired confidence level. For instance, when determining a 95% confidence interval, a Z-score of 1.96 is commonly used. This means that you expect 95% of the data to fall within 1.96 standard deviations from the mean. Knowing this Z-score is essential because it helps to adjust the range of the confidence interval. Therefore, for the baseball players' heights, using a Z-score of 1.96 allows us to construct an interval where we expect the true mean height of the entire team to lie. It's what gives statistical evidence to our assertions about the data.
Normal Distribution
The normal distribution, sometimes called the bell curve, is crucial in statistics because many datasets naturally follow this pattern. It's symmetrical and centered around the mean, with data more frequent near the mean and less frequent as you move further away. When we assume normality in heights of baseball players, it implies that most players' heights cluster around the average, with fewer players being extremely short or tall. This assumption simplifies calculations and underlies the rationale for using tools like the Z-score and confidence intervals. Normal distribution is pivotal in the context of calculating confidence intervals because it ensures our statistical methods yield accurate and reliable results. Even when working with small data sets like four players, this assumption lets us make inferences about the wider population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Weight A study of all the employees at an office showed a mean weight of \(60.4\) kilograms and a standard deviation of \(1.5\) kilograms. a. Are these numbers statistics or parameters? Explain. b. Label both numbers with their appropriate symbol (such as \(\bar{x}, \mu, s\), or \(\sigma\) ).

Babies Weights (Example 2) Some sources report that the weights of full-term newborn babies have a mean of 7 pounds and a standard deviation of \(0.6\) pound and are Normally distributed. a. What is the probability that one newborn baby will have a weight within \(0.6\) pound of the mean-that is, between \(6.4\) and \(7.6\) pounds, or within one standard deviation of the mean? b. What is the probability the average of four babies' weights will be within \(0.6\) pound of the mean; will be between \(6.4\) and \(7.6\) pounds? c. Explain the difference between a and \(\mathrm{b}\).

Sale of Air Conditioners (Example 1) The average number of air conditioners sold in 2015 was 3600 per day in a city, and that was larger than the average for any other appliance. Suppose the standard deviation is 1404 and the distribution is right-skewed. Suppose we take a random sample of 81 days in the year. a. What value should we expect for the sample mean? Why? b. What is the standard error for the sample mean?

Four-year Graduation Rate (Example 6) A random sample of 10 colleges from Kiplinger's 100 Best Values in Public Education was taken. The mean rate of graduation within four years was \(43.5 \%\) with a margin of error of \(6.0 \%\). The distribution of graduation rates is Normal. (Source: http://portal.kiplinger.com/tool/ college/T014-S001-kiplinger-s-best-values- in-public-colleges/index php#colleges. Accessed via StatCrunch. Owner: Webster West.) a. Decide whether each of the following statements is worded correctly for the confidence interval, and fill in the blanks for the correctly worded one(s). i. We are \(95 \%\) confident that the sample mean is between \(\%\) and \(\%\). ii. We are \(95 \%\) confident that the population mean is between \(-\%\) and \(\%\). iii. There is a \(95 \%\) probability that the population mean is between \(\%\) and \(\% .\) b. Can we reject a population mean percentage of \(50 \%\) on the basis of these numbers? Explain.

Hamburgers (Example 9) A hamburger chain sells large hamburgers. When we take a sample of 30 hamburgers and weigh them, we find that the mean is \(0.51\) pounds and the standard deviation is \(0.2\) pound. a. State how you would fill in the numbers below to do the calculation. with Minitab. b. Report the confidence interval in a carefully worded sentence. Normal.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.