/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 Standard anticoagulant therapy (... [FREE SOLUTION] | 91Ó°ÊÓ

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Standard anticoagulant therapy (to prevent blood clots) requires frequent laboratory monitoring to prevent internal bleeding. A new procedure using rivaroxaban (riva) was tested because it does not require frequent monitoring. A randomized trial (Einstein-PE Investigators 2012 ) was carried out, with standard therapy being randomly assigned to half of 4832 patients and riva randomly assigned to the other half. A bad result was recurrence of a blood clot in a vein. Fifty of the 2416 patients on standard therapy had a bad outcome, and 44 of the 2416 patients on riva had a bad outcome. a. Test the hypothesis that the proportions of bad results are different for riva and standard therapy patients. Use a significance level of \(0.05\), and show all four steps. b. Using methods leamed in Chapter 7 , estimate the difference between the two population proportions using a \(95 \%\) confidence interval, and comment on how it can be used to evaluate the null hypothesis in part a.

Short Answer

Expert verified
The answer to this question depends on the calculated p-value and confidence interval. If the p-value is less than the significance level, then there is evidence against the null hypothesis. If zero does not fall within the calculated confidence interval, the null hypothesis can be rejected. The calculated values are unknown without the actual calculations.

Step by step solution

01

State the null and alternative hypotheses.

The null hypothesis \(H_0\) is that the proportions of bad results are the same for riva and standard therapy patients (\(p_1 = p_2\)). The alternative hypothesis (\(H_a\)) is that the proportions are different (\(p_1 \neq p_2\)).
02

Perform the Z-test for two proportions.

First, calculate the pooled proportion, \(\hat{p}\), using \(\hat{p} = \frac{x_1 + x_2}{n_1 + n_2}\), where \(x_1\) and \(x_2\) are the number of bad outcomes for standard therapy and riva respectively and \(n_1\) and \(n_2\) are the total number of patients in each group. Then, calculate the test statistic, \(Z = \frac{\hat{p_1}- \hat{p_2}}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_1} +\frac{1}{n_2})}}\), where \(\hat{p_1}\) and \(\hat{p_2}\) are the sample proportions for standard therapy and riva respectively. Lastly, find the corresponding p-value for the calculated Z score.
03

Draw conclusions on the hypothesis test.

Compare the p-value with the significance level of \(0.05\). If the p-value is less than \(0.05\), reject the null hypothesis. If the p-value is greater than \(0.05\), do not reject the null hypothesis.
04

Calculate the confidence interval for the difference in proportions.

The confidence interval for the difference in proportions is given by \((\hat{p_1}-\hat{p_2})\pm Z_{1-\alpha/2}\sqrt{\frac{\hat{p_1}(1-\hat{p_1})}{n_1} +\frac{\hat{p_2}(1-\hat{p_2})}{n_2}}\), where \(Z_{1- \alpha/2}\) is the z-score that cuts off the top \(\alpha/2\) area in the standard normal distribution for a \((1-\alpha)100\%\) confidence level. Calculate this interval using the sample proportions and the number of patients in each group.
05

Evaluate the null hypothesis using the confidence interval.

Check if zero falls within the calculated confidence interval. If zero is not in the interval, it contradicts the assumption under the null hypothesis that the difference in proportions is zero. Thus, the null hypothesis can be rejected in favor of the alternative. If zero is within the interval, no conclusion can be drawn, i.e., the evidence is not enough to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis serves as a starting assumption that there is no effect or difference between groups or variables being studied. This is what researchers aim to test against.
In the context of the provided exercise, the null hypothesis (\( H_0 \)) suggests that the proportion of bad outcomes (i.e., recurrence of a blood clot in a vein) among patients using standard therapy is the same as the proportion among those using the new rivaroxaban therapy.
Formally, this can be represented as \( p_1 = p_2 \), where \( p_1 \) and \( p_2 \) are the population proportions of adverse results in the standard and rivaroxaban groups, respectively. By creating a null hypothesis, researchers set a baseline that allows them to use statistical methods to determine if there is sufficient evidence to indicate a difference between the groups.
Alternative Hypothesis
Contrary to the null hypothesis, the alternative hypothesis proposes there is a difference between the groups being studied. It is formulated when researchers suspect that certain factors do not behave similarly for the groups.
In the exercise, the alternative hypothesis (\( H_a \)) posits that the proportions of adverse outcomes are different between the standard therapy and rivaroxaban groups.
This is expressed as \( p_1 eq p_2 \).
The alternative hypothesis is an essential part of hypothesis testing as it opens up an avenue for exploring new and significant findings. By comparing the null and alternative hypotheses, we can determine whether to reject the null hypothesis based on the statistical evidence.
Z-test for Two Proportions
The Z-test for two proportions is a statistical method used to compare the proportions of two independent groups and determine if they are significantly different from each other. This test is especially useful when dealing with large samples.
To perform a Z-test for two proportions, the first step is to calculate the pooled proportion, \( \hat{p} \), which is the combined proportion of adverse outcomes from both the standard therapy and rivaroxaban groups. This is computed using the formula: \[ \hat{p} = \frac{x_1 + x_2}{n_1 + n_2} \] where \( x_1 \) and \( x_2 \) are the number of adverse outcomes, and \( n_1 \) and \( n_2 \) are the total number of patients in each group.
Next, calculate the test statistic represented by the Z value: \[ Z = \frac{\hat{p_1} - \hat{p_2}}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_1} + \frac{1}{n_2})}} \] where \( \hat{p_1} \) and \( \hat{p_2} \) are the sample proportions for the standard and rivaroxaban therapy groups. The Z-test helps in determining whether to reject the null hypothesis by comparing the calculated Z-score with a critical value corresponding to the chosen significance level.
Confidence Interval
A confidence interval provides a range of values which estimates the difference in population proportions, giving insight into where the true difference lies.
In this exercise, a 95% confidence interval is computed for the difference in proportions of bad outcomes between the two therapies. The confidence interval is calculated using: \[ (\hat{p_1} - \hat{p_2}) \pm Z_{1-\alpha/2} \sqrt{\frac{\hat{p_1}(1-\hat{p_1})}{n_1} +\frac{\hat{p_2}(1-\hat{p_2})}{n_2}} \] where \( Z_{1- \alpha/2} \) corresponds to the Z-score that cuts off the top \( \alpha/2 \) area in the standard normal distribution for a 95% confidence level.
This interval provides a range within which the difference between the two population proportions is likely to lie, with a certain level of confidence. If the confidence interval does not contain zero, it implies that there is a statistically significant difference between the groups, allowing us to reject the null hypothesis and accept the alternative hypothesis.

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Most popular questions from this chapter

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