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A Washington Post Poll (March 18,2013 ) and a Pew Poll (March 17,2013 ) both claimed to ask a random sample of adults in the United States whether they supported or opposed gay marriage. In the Washington Post Poll, 581 supported and 360 opposed gay marriage. In the Pew Poll, 735 supported and 660 opposed gay marriage. a. Find the percentages sapporting gay marriage in these two polls and compare them. b. Test the hypothesis that the population proportions are not equal at the \(0.05\) significance level. c. Using methods learned in Chapter 7, find a \(95 \%\) confidence interval for the difference between the two percentages, and interpret it. Does it capture \(0 ?\) What does that show?

Short Answer

Expert verified
Part a involves proportional calculation, part b involves hypothesis testing where we reject or fail to reject the null hypothesis depending upon p-value, and part c involves calculation of a confidence interval. The interpretation of whether it captures \(0\) gives us the inference about the significance of difference in proportions of population.

Step by step solution

01

Calculate the Proportions

Calculate the proportion of people supporting gay marriage in each poll: \n For the Washington Post Poll, divide 581 by the total number of participants (581 + 360). Similarly, for the Pew Poll, divide 735 by the total number (735 + 660). Multiply each ratio by 100 to convert it into a percentage.
02

Hypothesis Testing

Test the hypothesis that the population proportions are not equal. The null hypothesis (\(H_0\)) is that the two proportions are equal, and the alternative hypothesis (\(H_1\)) is that they are not equal. Compute the combined proportion (number of successes divided by total) from both samples, then find the standard error using the formula \( \sqrt{p (1 - p) [ (1/n1) + (1/n2) ]}\). Calculate Z score, which is the difference between the two proportions divided by the standard error. Use this Z score to find the p-value in a standard normal Z distribution. If the p-value is less than 0.05, reject the null hypothesis.
03

Confidence Interval Calculation

The 95% confidence interval for the difference in proportions is given by \((p1 - p2) \pm z* \sqrt{ p1(1 - p1)/n1 + p2(1 - p2)/n2 }\), where \(p1\) and \(p2\) are the sample proportions, \(n1\) and \(n2\) are the sample sizes, and \(z*\) is the critical value for a 95% confidence interval, which is approximately 1.96. Resulting interval interprets the difference between the two proportions.
04

Interpretation

The result captures \(0\) if the confidence interval for the difference contains \(0\), which means there is no statistically significant difference between the two proportions. If the interval does not capture \(0\), this would mean that the difference between the two population proportions is significant at the 5% level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion Comparison
Understanding the basics of population proportion comparison is essential when analyzing poll results—or any data where you're comparing two or more groups. Proportion comparison involves calculating the ratio of individuals with a certain characteristic in each group and then determining if these ratios significantly differ from one another.
For example, in two polls measuring support for a social issue, such as gay marriage, we calculate the percentages of respondents who support the issue in each poll. If these percentages are significantly different, this might suggest variations in opinion across the groups surveyed. The initial step in this process, as seen in the exercise, requires calculating the proportion of supporters in each poll, which sets the stage for further statistical testing.
By comparing these proportions, we can start to understand the public sentiment and whether there is a noticeable difference between the samples taken from the population. This comparison is the cornerstone of hypothesis testing regarding population proportions and guides us towards more complex statistical analysis.
Confidence Interval Calculation
The confidence interval is a range of values that is likely to contain the true population parameter, such as a population proportion. It offers an estimated range based on sample statistics and is pivotal for interpreting poll results or any other sort of statistical estimate.
To construct a confidence interval for the difference between two population proportions—just like the situation we have with the two polls—we use the formula
\[\begin{equation}(p1 - p2) \pm z* \sqrt{\frac{p1(1 - p1)}{n1} + \frac{p2(1 - p2)}{n2}}\end{equation}\]
where
  • \[\begin{equation}p1\text{ and }p2\text{ are the sample proportions,}\end{equation}\]
  • \[\begin{equation}n1\text{ and }n2\text{ are the sample sizes, and}\end{equation}\]
  • \[\begin{equation}z* \text{ is the z-value that corresponds to the desired level of confidence.}\end{equation}\]
This interval helps us gauge the precision of our estimates and is essential for making informed inferences about a population.
Z score and p-value
The Z score is a measure that describes a value's relationship to the mean of a group of values, expressed in terms of standard deviations. When we perform hypothesis testing, we use the Z score to determine how extreme our sample statistic is if we assume that the null hypothesis is true. A high absolute value of a Z score may suggest that the observed data is unlikely to have occurred by random chance.
In the context of comparing two population proportions, the Z score helps us assess the significance of the difference between those proportions. After the Z score is calculated using the standard error and the difference in sample proportions, we look up the corresponding p-value. This p-value tells us the probability of observing our sample data—or something more extreme—if the null hypothesis (that the population proportions are equal) is true. If the p-value is less than a predetermined significance level, typically 0.05, we reject the null hypothesis, indicating that the evidence is strong enough to conclude a significant difference between population proportions.
Significance Level
When interpreting statistical tests, the significance level is a threshold of probability below which we reject the null hypothesis. Commonly denoted as
\[\begin{equation}\alpha\end{equation}\]
, the significance level is effectively the risk we're willing to take of making a Type I error—rejecting a true null hypothesis. In many social sciences, including the analysis of poll data, a 0.05 (5%) significance level is standard, meaning there's a 5% risk of concluding that there's a difference between populations when there is none.
Choosing a significance level is a balance between making sure we have enough evidence to claim a finding and the risk of making an incorrect conclusion. This level aids in decision-making and helps maintain the scientific rigor by providing a benchmark for the evidence needed to accept an alternative hypothesis over the null.

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Most popular questions from this chapter

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