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Thumbtacks When a certain type of thumbtack is tossed, the probability that it lands tip up is \(60 \%\). All possible outcomes when two thumbtacks are tossed are listed. U means the tip is up, and \(\mathrm{D}\) means the tip is down. \(\begin{array}{llll}\text { UU } & \text { UD } & \text { DU } & \text { DD }\end{array}\) a. What is the probability of getting two Ups? b. What is the probability of getting exactly one Up? c. What is the probability of getting at least one Up (one or more Ups)? d. What is the probability of getting at most one Up (one or fewer Ups)?

Short Answer

Expert verified
a. The probability of getting two Ups is 36%. b. The probability of getting exactly one Up is 48%. c. The probability of getting at least one Up is 84%. d. The probability of getting at most one Up is 64%.

Step by step solution

01

Probability of Two Ups

Since each toss is an independent event, the probability of tossing two Ups is the probability of one thumbtack landing tip up multiplied by the same probability for the other thumbtack. Given that the probability of landing tip up is 60% or 0.6, the probability of getting two Ups is \(0.6 \times 0.6 = 0.36\) or 36%.
02

Probability of Exactly One Up

There are two ways to get exactly one Up - the first thumbtack lands tip up and the second lands tip down (UD), or the first thumbtack lands tip down and the second lands tip up (DU). Each case has a probability of \(0.6 \times 0.4 = 0.24\) or 24%. To get the total probability of getting exactly one up, we add the probabilities of these two mutually exclusive events, resulting in \(0.24 + 0.24 = 0.48\) or 48%.
03

Probability of At Least One Up

Getting at least one Up includes three possibilities - two Ups (UU), first thumbtack Up second Down (UD), or first thumbtack Down second Up (DU). We calculated these probabilities in step 1 and step 2 as 36% and 48% respectively. Adding these gives us \(0.36 + 0.48 = 0.84\) or 84%.
04

Probability of At Most One Up

At most one Up includes three possibilities - no Ups (DD), first thumbtack Up second Down (UD), or first thumbtack Down second Up (DU). We calculated the possibility of getting one Up in step 2 as 48%. The probability of no Ups is the probability of one thumbtack landing tip down multiplied by the same probability for the other thumbtack, given as \(0.4 \times 0.4 = 0.16\) or 16%. Adding these gives us \(0.16 + 0.48 = 0.64\) or 64%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
When studying the behavior of thumbtacks tossed in the air, we encounter the concept of independent events. Independent events are those in which the outcome of one event does not affect the outcome of another. For example, tossing one thumbtack and then tossing a second one. The result of the first toss has no bearing on the result of the second toss. In probability calculations, this means we can multiply the probabilities of each event occurring separately to find the combined probability of both events occurring.

In our thumbtack problem, because each toss is independent, we could calculate the probability of getting two 'Ups' (UU) by multiplying the probability of the first thumbtack landing 'Up' by the probability of the second thumbtack landing 'Up'. If we assume the probability of landing 'Up' is 60% or 0.6 for each toss, then we get: \[\begin{equation}0.6 \times 0.6 = 0.36\end{equation}\]or 36%. This illustrates how understanding independence in probability allows us to perform straightforward calculations when examining the outcomes of multiple events.
Mutually Exclusive Events
Switching gears, let's consider the case when we are looking for the probability of getting exactly one 'Up' in our thumbtack problem. This introduces us to mutually exclusive events. Mutually exclusive events are those that cannot occur at the same time. In our scenario, for instance, getting a result of 'Up-Down' (UD) excludes the possibility of 'Down-Up' (DU) for the same single toss of two thumbtacks.

There are two distinct and mutually exclusive ways to get exactly one 'Up': either the first thumbtack land 'Up' and the second 'Down', or the first land 'Down' and the second 'Up'. The probability for each of these outcomes is calculated by multiplying the chance of 'Up' by the chance of 'Down': \[\begin{equation}0.6 \times 0.4 = 0.24\end{equation}\]or 24%. Since these events cannot happen simultaneously for a single pair of tosses, to find the total probability of getting exactly one 'Up', we add the probabilities of each event: \[\begin{equation}0.24 + 0.24 = 0.48\end{equation}\]or 48%. Understanding mutually exclusive events is crucial in separating scenarios and accurately summing their probabilities when needed.
Probability Calculations
Probability calculations form the backbone of quantitative data analysis in statistics, helping us quantify the likelihood of different events. In dealing with our thumbtack exercise, the probability calculations assist in determining the range of possible outcomes when thumbtacks are tossed. When we talk about the probability of getting 'at least one Up', we're looking at all possible combinations where one or both thumbtacks land 'Up' - which includes 'Up-Up' (UU), 'Up-Down' (UD), and 'Down-Up' (DU).

To calculate this, we sum the probabilities of each of these outcomes happening. From our earlier discussions, we know 'UU' has a probability of 36%, and 'UD' or 'DU' each has a probability of 24%. By adding these probabilities together, we deduce that getting 'at least one Up' has an overall probability of: \[\begin{equation}0.36 + 0.48 = 0.84\end{equation}\]or 84%. This also demonstrates the importance of understanding how to approach a problem and choose the correct method for the desired probability - whether it be multiplication for independent events, or addition for mutually exclusive or non-exclusive events. Probability calculations are essential for accurate predictions and informed decision-making in fields as diverse as science, economics, and daily life decision-making.

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Most popular questions from this chapter

Simulation: Six-Sided Die a. Explain how you could use a random number table to simulate rolling a fair six-sided die 20 times. Assume you wish to find the probability of rolling a 1 . Then report a line or two of the random number table (or numbers generated by a computer or calculator) and the values that were obtained from it. b. Report the empirical probability of rolling a 1 from part \(a\), and compare it with the theoretical probability of rolling a 1 .

California Recidivism In California, the recidivism rate for prisoners is \(67.5 \%\). That is, \(67.5 \%\) of those released from prison go back to prison within three years. This is one of the highest recidivism rates in the nation. a. Suppose two independent prisoners are released. What is the probability that they will both go back to prison within three years? b. What is the probability that neither will go back to prison within three years? c. Suppose two independent prisoners are released. What is the probability that one OR the other (or both) will go back to prison within three years?

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Empirical vs. Theoretical A person was trying to understand the probability of drawing a black card from a fair deck of cards. He drew a card 20 times, and in these 20 times, a black card was drawn 12 times. On the basis of this, he claims that the probability of drawing a black card from a fair deck of cards is \(60 \%\). Is this an example of empirical probability or theoretical probability? Explain.

Roll a Die Roll a fair six-sided die. a What is the probability that the die shows an odd number \(\mathrm{OR}\) a number greater than 5 on top? b. What is the probability that the die shows an odd number \(\mathrm{OR}\) a number greater than 4 on top?

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