/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 128 Seat Belt Use In 2009 , the Nati... [FREE SOLUTION] | 91Ó°ÊÓ

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Seat Belt Use In 2009 , the National Highway Traffic Safety Administration said that \(84 \%\) of drivers buckled their seat belts. Assume that this percentage is still accurate. If four drivers are randomly selected, what is the probability that they are all wearing their seat belts?

Short Answer

Expert verified
The probability that all four randomly selected drivers are wearing their seat belts is \((0.84)^4 = 0.4976\) or \(49.76\% \)

Step by step solution

01

Understand the scenario

A situation is presented where 84% (or 0.84 in decimal form) of drivers buckle up their seat belt. The task is to determine the probability that if four drivers are randomly selected, all of them are wearing their seat belts.
02

Identify individual events

In this case, each driver wearing a seat belt is an independent event. The events are independent because the result of one does not affect the result of the others.
03

Calculate overall probability

The probability of all independent events happening is the product of their individual probabilities. In this case, we can calculate this as \(0.84 \times 0.84 \times 0.84 \times 0.84 = (0.84)^4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
Understanding the concept of independent events is essential when trying to calculate the probability of multiple occurrences. Independent events are those where the outcome of one event does not affect the outcome of another. In simpler terms, the events have no bearing on each other. An easy-to-grasp analogy would be flipping a coin. Whether you get heads or tails on your first flip doesn't change the odds of getting heads or tails on the next flip.

When we look at our example involving seat belt use, we consider the act of each driver choosing to wear a seat belt as an independent event. The choice of one driver to buckle up does not influence the choice of another driver. Because of this independence, we multiply the probabilities of each event to find the overall likelihood that all events occur together. It's as if the universe 'forgets' and each event happens in its own bubble, unaffected by past occurrences.
Random Selection
Random selection is a principle applied when each member of a population has an equal chance of being chosen for a sample. It is a core concept in probability and statistics, ensuring that the sample represents the population fairly, minimizing bias. In the context of our example, random selection implies that any group of four drivers has the same chance of being picked as any other group, and they are chosen without any particular order or pattern.

Why is random selection important?

It guarantees that the results can be generalized to the larger population. If the four drivers were not chosen randomly, we could end up with a biased sample, for instance, choosing only drivers from a specific area that may have a higher or lower seat belt usage rate, which would skew our results.
Probability Calculation
Probability calculation is the process of determining the likelihood of a given event occurring. It ranges from 0 to 1, with 0 meaning the event will not occur, and 1 indicating certainty that the event will happen. In many cases, probability is expressed in percentages, as it is more intuitive to say there's an '84% chance'.

How to calculate the probability of multiple independent events?

In our seat belt usage scenario, the probability of each driver wearing a seat belt is 84%, or 0.84 when expressed as a decimal. To find the probability that all four drivers selected wear their seat belts, we multiply the probabilities of the individual events since they are independent:
  • Probability of all four wearing seat belts = Probability of first AND second AND third AND fourth
  • This equates to \(0.84 \times 0.84 \times 0.84 \times 0.84 = (0.84)^4\)
This method can be used whenever we are dealing with independent events, and it provides a way to calculate the overall probability by simply using multiplication.

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