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Speaking to a group of analysts in January \(2006,\) a brokerage firm executive claimed that at least \(70 \%\) of investors are currently confident of meeting their investment objectives. A UBS Investor Optimism Survey, conducted over the period January 2 to January \(15,\) found that \(67 \%\) of investors were confident of meeting their investment objectives (CNBC, January \(20,2006)\) a. Formulate the hypotheses that can be used to test the validity of the brokerage firm executive's claim. b. Assume the UBS Investor Optimism Survey collected information from 300 investors. What is the \(p\) -value for the hypothesis test? c. At \(\alpha=.05,\) should the executive's claim be rejected?

Short Answer

Expert verified
The executive's claim should not be rejected, as the p-value (0.1285) is greater than 0.05.

Step by step solution

01

Formulate Hypotheses

To test the claim that at least 70% of investors are confident, we set up the null and alternative hypotheses. The null hypothesis is \(H_0: p \geq 0.70\), and the alternative hypothesis is \(H_a: p < 0.70\). This tests if the proportion of confident investors is less than 70%.
02

Identify Sample Statistics

We have a sample proportion \( \hat{p} = 0.67 \) (67% of 300 investors) and a sample size of \( n = 300 \). We'll use this information to perform the hypothesis test.
03

Calculate the Test Statistic

The test statistic for a proportion is calculated using the formula \( z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}} \), where \( p_0 = 0.70 \). Substituting the values: \( z = \frac{0.67 - 0.70}{\sqrt{\frac{0.70 \times 0.30}{300}}} = \frac{-0.03}{0.02646} \approx -1.134\).
04

Find the p-value

Using a standard normal distribution table, we find the p-value associated with \( z = -1.134 \). The p-value is approximately 0.1285, indicating the probability of observing a sample proportion as extreme as 0.67 or less, assuming the null hypothesis is true.
05

Decision at \( \alpha = 0.05 \)

Compare the p-value (0.1285) to the alpha level (0.05). Since 0.1285 > 0.05, we fail to reject the null hypothesis. There is not enough evidence to reject the executive's claim that at least 70% of investors are confident.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
In hypothesis testing, setting up the null and alternative hypotheses is a fundamental step. The null hypothesis, often denoted as \( H_0 \), represents a baseline or status quo assumption that we aim to test against. In this scenario, we are examining the claim that at least 70% of investors are confident in meeting their investment objectives. Thus, the null hypothesis is set as \( H_0: p \geq 0.70 \), where \( p \) is the true proportion of confident investors. The alternative hypothesis, denoted as \( H_a \), contains the opposite claim to the null hypothesis and reflects the assertion we want to test for evidence. Here, it is expressed as \( H_a: p < 0.70 \), indicating we are testing whether the actual proportion is less than 70%. A good way to remember this: the null hypothesis often contains an equality or inequality (\( \geq \), \( = \), or \( \leq \)), while the alternative hypothesis reflects a deviation, representing the potential for change or difference.
p-value Interpretation
The p-value is a crucial component in hypothesis testing. It quantifies the strength of the evidence against the null hypothesis. Technically, the p-value is the probability of observing a sample statistic as extreme as the one you have, assuming that the null hypothesis is true. In our example problem, after computing the test statistic using the sample data, we find a p-value of approximately 0.1285. This means there is a 12.85% probability of observing a sample with a proportion of 67% confident investors, or even less, if indeed 70% of investors are confident. When interpreting p-values:
  • A small p-value (usually ≤ 0.05) indicates strong evidence against the null hypothesis, prompting its rejection.
  • A large p-value (> 0.05) indicates weaker evidence against the null hypothesis, which makes it more reasonable to keep it as is.
In this case, the p-value of 0.1285 is greater than 0.05, providing insufficient evidence to reject the null hypothesis.
Significance Level
The significance level, denoted as \( \alpha \), is the threshold chosen by the researcher to determine when to reject the null hypothesis. It represents the probability of committing a Type I error, which is incorrectly rejecting a true null hypothesis.In many social science research scenarios, the significance level is conventionally set at 0.05 (or 5%). This implies that the researcher is willing to accept a 5% chance of wrongly rejecting the null hypothesis. Applying this to the example problem, the significance level \( \alpha = 0.05 \) sets the decision boundary. Since our computed p-value of 0.1285 is greater than 0.05, we do not reject the null hypothesis. Consider the significance level as a benchmark that helps decide the strength of evidence required in order to believe that an effect exists. While 0.05 is standard, researchers might choose a more stringent level like 0.01 or a more lenient 0.10 based on the context and repercussions of errors.

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Most popular questions from this chapter

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