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A USA Today/CNN/Gallup poll for the presidential campaign sampled 491 potential voters in June (USA Today, June 9, 2000). A primary purpose of the poll was to obtain an estimate of the proportion of potential voters who favor each candidate. Assume a planning value of \(p^{*}=.50\) and a \(95 \%\) confidence level. a. For \(p^{*}=.50,\) what was the planned margin of error for the June poll? b. Closer to the November election, better precision and smaller margins of error are desired. Assume the following margins of error are requested for surveys to be conducted during the presidential campaign. Compute the recommended sample size for each survey

Short Answer

Expert verified
The planned margin of error was 4.41%. To achieve better precision, at least 1067 participants are needed for a 3% margin of error.

Step by step solution

01

Understand the Margin of Error Formula

The margin of error for a proportion is given by the formula \( ME = z \sqrt{\frac{p^*(1-p^*)}{n}} \). For a \( 95\% \) confidence level, the z-score (z) is approximately 1.96.
02

Substitute Known Values to Find Planned Margin of Error

In this case, \( p^* = 0.50 \) and \( n = 491 \). Substitute these values into the margin of error formula: \( ME = 1.96 \sqrt{\frac{0.50 \times (1-0.50)}{491}} \).
03

Calculate the Margin of Error

Calculate \( ME = 1.96 \sqrt{\frac{0.25}{491}} \). Simplify inside the square root first: \( \sqrt{\frac{0.25}{491}} \), which equals approximately 0.0225. Thus, \( ME \approx 1.96 \times 0.0225 = 0.0441 \). The planned margin of error for the June poll is approximately 4.41%.
04

Determine the Sample Size for Desired Margin of Error

Use the formula for sample size \( n = \left(\frac{z^2 \times p^* \times (1-p^*)}{E^2}\right) \), where \( E \) is the desired margin of error.
05

Compute Sample Size for Each Desired Margin of Error

For example, to achieve a margin of error of 0.03 (3%), substitute \( E = 0.03 \): \( n = \left(\frac{1.96^2 \times 0.50 \times 0.50}{0.03^2}\right) \). Simplify to get \( n = \left(\frac{3.8416 \times 0.25}{0.0009}\right) \approx \frac{0.9604}{0.0009} \approx 1067 \). Thus, a sample size of 1067 is required.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Confidence Intervals
Confidence intervals offer a range in which we expect the true value of a statistic to fall, with a certain level of confidence. This means that if we were to take multiple samples and construct confidence intervals for each, a certain percentage of these intervals would contain the true population parameter. For example, a 95% confidence interval means that 95 out of 100 such intervals would include the true value.
Confidence intervals are crucial in statistics because they give context to sample estimates, offering insight into the precision of the estimate:
  • Central Estimate: This is the most likely value from the sample data, for example, the proportion of voters favoring a candidate.
  • Confidence Level: Indicates how confident we are that the interval contains the true parameter, typically represented as 90%, 95%, or 99%.
  • Range: The span of values within which the true parameter lies, given a specific confidence level.
Calculating a confidence interval involves the estimate (like a sample proportion) and its margin of error. Together, these give voters and policymakers a window into how public opinion may vary from the sample's snapshot.
Calculating Sample Size
Determining the appropriate sample size is crucial to achieving the desired level of precision in any estimation. The sample size calculation is tied directly to the desired margin of error, confidence level, and a planning value for the proportion.
To determine this, follow these basic steps:
  • Planning Value: Often denoted as \( p^* \), it's typically a guessed proportion, like 0.50, used to maximize the sample size.
  • Desired Margin of Error \( (E) \): Indicates the level of precision required; smaller margins require larger sample sizes.
  • Use the Formula: \( n = \left(\frac{z^2 \times p^* \times (1-p^*)}{E^2}\right) \). This equation helps compute the number of observations needed.
For example, adjusting the margin of error from 4% to 3% increases the sample size due to the higher precision requirement. This formula ensures researchers collect enough data to make meaningful, statistically supported conclusions.
Understanding the Margin of Error
The margin of error is a statistic that reflects the amount of random sampling error in a survey's results. It essentially reflects how much we expect our projections to vary from the actual results if we sampled the same population over and over again without changing the methodology. The margin of error depends on several factors:
  • Confidence Level: A higher confidence level, such as 99%, results in a larger margin of error because it requires a wider net to be sure the true parameter is captured.
  • Sample Size: Larger samples provide more precise estimates and thus have smaller margins of error. This is due to the diminished effect of random variability in larger groups of data.
  • Proportion Estimate \( (p^*) \): The margin of error is largest when the proportion is around 0.5, as this is where the variability is highest.
In the poll example, a 4.41% margin of error means the true proportion of voters may vary by this amount from the sample result. Understanding and accounting for this uncertainty help portray the precision of survey results clearly and accurately.

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