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Roper ASW conducted a survey to learn about American adults' attitudes toward money and happiness (Money, October 2003 ). Fifty-six percent of the respondents said they balance their checkbook at least once a month. a. Suppose a sample of 400 American adults were taken. Show the sampling distribution of the proportion of adults who balance their checkbook at least once a month. b. What is the probability that the sample proportion will be within ±.02 of the population proportion? c. What is the probability that the sample proportion will be within ±.04 of the population proportion?

Short Answer

Expert verified
P(within ±0.02) = 0.5788, P(within ±0.04) = 0.8907.

Step by step solution

01

Understand the Problem

We are given that 56% of American adults balance their checkbook at least once a month. We need to analyze a sample of 400 adults and explore the distribution of this sample proportion. We then need to find probabilities of the sample proportion being within ±0.02 and ±0.04 of the population proportion.
02

Define and Calculate the Parameters

The population proportion, \( p \), is 0.56. The sample size, \( n \), is 400. The sample proportion \( \hat{p} \) will be normally distributed with mean \( \mu_{\hat{p}} = p = 0.56 \) and standard deviation \( \sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.56 \times 0.44}{400}} \). Calculate \( \sigma_{\hat{p}} \) for further use.
03

Calculate the Standard Deviation of the Sample Proportion

Calculate \( \sigma_{\hat{p}} \):\[ \sigma_{\hat{p}} = \sqrt{\frac{0.56 \times 0.44}{400}} \approx 0.0248 \]
04

Find Probability Within ±0.02

Use the normal distribution to find the probability that \( \hat{p} \) is within ±0.02 of \( p \). This corresponds to \( 0.54 \leq \hat{p} \leq 0.58 \). Find the Z-scores for \( \hat{p} = 0.54 \) and \( \hat{p} = 0.58 \) using:\[ Z = \frac{\hat{p} - \mu_{\hat{p}}}{\sigma_{\hat{p}}} \] Calculate the probabilities using standard normal distribution tables or software.
05

Calculate Z-scores for ±0.02

For \( \hat{p} = 0.54 \):\[ Z = \frac{0.54 - 0.56}{0.0248} \approx -0.81 \]For \( \hat{p} = 0.58 \):\[ Z = \frac{0.58 - 0.56}{0.0248} \approx 0.81 \]
06

Probability Within ±0.02 using Z-scores

Using a standard normal distribution table or calculator, find the probability for Z between -0.81 and 0.81. This value represents the probability that the sample proportion is within ±0.02 of the population proportion.\[ P(-0.81 \leq Z \leq 0.81) \approx 0.5788 \]
07

Find Probability Within ±0.04

Now find the probability that \( \hat{p} \) is within ±0.04 of \( p \). This corresponds to \( 0.52 \leq \hat{p} \leq 0.60 \). Find the Z-scores for \( \hat{p} = 0.52 \) and \( \hat{p} = 0.60 \).
08

Calculate Z-scores for ±0.04

For \( \hat{p} = 0.52 \):\[ Z = \frac{0.52 - 0.56}{0.0248} \approx -1.61 \]For \( \hat{p} = 0.60 \):\[ Z = \frac{0.60 - 0.56}{0.0248} \approx 1.61 \]
09

Probability Within ±0.04 using Z-scores

Find the probability for Z between -1.61 and 1.61 using a standard normal distribution table or calculator:\[ P(-1.61 \leq Z \leq 1.61) \approx 0.8907 \]
10

Summarize Findings

The sampling distribution of the proportion of adults who balance their checkbook at least once a month has a mean of 0.56 and a standard deviation of approximately 0.0248. The probability that the sample proportion is within ±0.02 of the population proportion is approximately 0.5788, while the probability for ±0.04 is approximately 0.8907.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a fundamental concept in statistics, often represented by the symbol \( p \). It refers to the fraction or percentage of the entire population that possesses a certain characteristic. In our example, the population proportion is 56%, which indicates that 56% of American adults balance their checkbook at least once a month.

To understand population proportion in the context of a survey, imagine taking a snapshot of the entire group you're interested in. The proportion is essentially the ratio of the feature of interest (i.e., balancing checkbooks) present in this group. It serves as a benchmark when comparing samples taken from the population. The goal is to determine how likely our sample data will mirror this population standard.
Normal Distribution
A normal distribution is a continuous probability distribution that is symmetrical around its mean, depicting a bell-shaped curve. The characteristic of this distribution is significant because many statistical tests and procedures are based on the assumption of normality.

In this exercise, we are assuming our sample proportion follows a normal distribution. When the sample size is large, the central limit theorem enables us to approximate the sample distribution of the proportion as normal. For a sample size of 400, the distribution of our sample proportion of people who balance their checkbook at least once a month turns into a standard normal curve, making it easier to calculate probabilities of interest using standard statistical methods.
  • The mean of this normal distribution is the population proportion \( p \).
  • The standard deviation is derived using the formula for sampling distributions.
Standard Deviation
Standard deviation is a measure that is used to quantify the amount of variation or dispersion in a set of data values. In the context of a sampling distribution of a proportion, standard deviation tells us about the spread of the sample proportions we might obtain for a given sample size if we repeatedly surveyed samples from our population.

For our exercise, the standard deviation is calculated using the formula:\[\sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}}\]
The calculated standard deviation, approximately 0.0248, reflects the variability we expect in our sample proportion (of the survey respondents who balance their checkbooks) around the true population proportion of 56% as we conduct similar studies multiple times. A smaller standard deviation indicates that most sample proportions will be very close to the actual population proportion.
Z-scores
Z-scores are a statistical measurement that describe a value's relationship to the mean of a group of values. When dealing with sample proportions, Z-scores help standardize the outcome, allowing us to relate different probability see what percentage of the data falls within certain bounds.

To calculate the Z-score for a specific sample proportion \( \hat{p} \), use the formula:\[Z = \frac{\hat{p} - \mu_{\hat{p}}}{\sigma_{\hat{p}}}\]
In this scenario, we calculated Z-scores to determine the probability of finding a sample proportion within a specified range (for example, ±0.02 or ±0.04 from the population proportion). By finding the Z-scores and using a standard normal distribution table or calculator, we can assess the likelihood of our sample's estimate falling close to the truth, providing us with valuable insights into the reliability of our sample data.

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