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A binomial probability distribution has \(p=.20\) and \(n=100\) a. What are the mean and standard deviation? b. Is this situation one in which binomial probabilities can be approximated by the normal probability distribution? Explain. c. What is the probability of exactly 24 successes? d. What is the probability of 18 to 22 successes? e. What is the probability of 15 or fewer successes?

Short Answer

Expert verified
a) Mean = 20, Standard deviation = 4. b) Yes; both np and n(1-p) are > 5. c) ≈ 0.0691. d) ≈ 0.4681. e) ≈ 0.1303.

Step by step solution

01

Calculate the Mean

For a binomial distribution, the mean \(\mu\) is calculated using the formula \(\mu = n \times p\). Here, \(n = 100\) and \(p = 0.20\). Thus, \(\mu = 100 \times 0.20 = 20\). The mean of the distribution is 20.
02

Calculate the Standard Deviation

The standard deviation \(\sigma\) of a binomial distribution is calculated using the formula \(\sigma = \sqrt{n \times p \times (1-p)}\). Substituting the given values, \(\sigma = \sqrt{100 \times 0.20 \times 0.80} = \sqrt{16} = 4\). The standard deviation is 4.
03

Check if Normal Approximation is Suitable

To use the normal approximation, \(np\) and \(n(1-p)\) must both be greater than 5. Here, \(np = 100 \times 0.20 = 20\) and \(n(1-p) = 100 \times 0.80 = 80\), both are greater than 5. Therefore, the normal approximation is suitable.
04

Calculate Probability of Exactly 24 Successes

Using the normal approximation, convert 24 to a z-score with continuity correction: \(z = \frac{24 + 0.5 - 20}{4} = \frac{4.5}{4} = 1.125\). \(P(X = 24) \approx P(23.5 < X < 24.5)\). Find the probability using \(P(X < 24.5) - P(X < 23.5)\). Refer to z-tables or technology: \(P(X < 24.5) = 0.8699\) and \(P(X < 23.5) = 0.8008\). The probability is approximately \(0.0691\).
05

Calculate Probability of 18 to 22 Successes

Using the normal approximation with continuity correction, calculate two z-scores:\[\frac{17.5 - 20}{4} = -0.625\] and \[\frac{22.5 - 20}{4} = 0.625\]. Find \(P(18 \leq X \leq 22) = P(17.5 < X < 22.5)\). From z-tables or technology: \(P(X < 22.5) = 0.7340\) and \(P(X < 17.5) = 0.2659\). The probability is \(0.7340 - 0.2659 = 0.4681\).
06

Calculate Probability of 15 or Fewer Successes

Convert to a z-score using continuity correction for 15: \(z = \frac{15 + 0.5 - 20}{4} = \frac{-4.5}{4} = -1.125\). Find \(P(X \leq 15) \approx P(X < 15.5)\). Use z-tables or technology to find \(P(X < 15.5) = 0.1303\). The probability is approximately \(0.1303\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Probability
Binomial probability is a fundamental concept in statistics used to determine the likelihood of a particular number of successes in a sequence of independent experiments. Each experiment, called a trial, has only two possible outcomes: success or failure. The probability of success in each trial is denoted by \( p \), while the probability of failure is \( 1 - p \).

The binomial distribution formula evaluates the probability of achieving exactly \( k \) successes in \( n \) trials:
  • The formula is: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \)
  • \( \binom{n}{k} \) represents "n choose k" combinations, calculating the different ways \( k \) successes can occur within \( n \) trials.
Using this distribution, we can solve problems involving scenarios like flipping a coin, passing/failing a test, or product defects. By understanding the probabilities of different outcomes, one can make informed decisions and predictions based on past data.
Normal Approximation
Sometimes, calculating binomial probabilities manually becomes cumbersome. This is where normal approximation comes in handy. It's an approach that simplifies these calculations, especially when \( n \), the number of trials, is large.

The approximation requires the conditions that both \( np \) and \( n(1-p) \) are greater than 5. When these conditions are met, the shape of the binomial distribution resembles a normal curve, allowing us to use z-scores for our calculations.

By applying this method, probabilities are calculated using the z-score formula:
  • Calculate \( z = \frac{x + 0.5 - \mu}{\sigma} \), using the continuity correction.
  • \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
The normal approximation simplifies tasks, offering a practical way of dealing with numerous trials without lengthy computations.
Statistical Mean
The statistical mean, often referred to as the average, summarizes a set of numbers by using their central value. In a binomial distribution, it represents the expected number of successes within the trials.

To find the mean of a binomial distribution, use the formula:
  • \( \mu = n \times p \) where \( n \) is the number of trials, and \( p \) is the probability of success in each trial.
For example, if we have a hoped-for 20% success rate in 100 trials, we'd expect to see 20 successes (as calculated with \( \mu = 100 \times 0.20 \)).

This mean value provides insight into the behavior of data sets and is essential for making predictions about outcomes in various statistical analyses.
Standard Deviation
Standard deviation quantifies the amount of variation or dispersion in a set of values. In a binomial distribution, it reflects the degree to which each outcome deviates from the mean. A smaller standard deviation points to outcomes clustering closely around the mean, while a larger value indicates more spread out results.

Calculating the standard deviation for a binomial distribution involves:
  • Using the formula: \( \sigma = \sqrt{n \times p \times (1-p)} \).
  • This considers both the probability of success and failure in each trial.
For instance, with 100 trials and a success probability of 0.20, the standard deviation is \( \sqrt{100 \times 0.20 \times 0.80} = 4 \).

Understanding standard deviation helps gauge the spread of potential outcomes, allowing for better risk assessment and decision making in statistical studies.

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