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A psychologist determined that the number of sessions required to obtain the trust of a new patient is either \(1,2,\) or \(3 .\) Let \(x\) be a random variable indicating the number of sessions required to gain the patient's trust. The following probability function has been proposed. \\[ f(x)=\frac{x}{6} \quad \text { for } x=1,2, \text { or } 3 \\] a. Is this probability function valid? Explain. b. What is the probability that it takes exactly 2 sessions to gain the patient's trust? c. What is the probability that it takes at least 2 sessions to gain the patient's trust?

Short Answer

Expert verified
a. Yes, it's valid; b. \(\frac{1}{3}\); c. \(\frac{5}{6}\).

Step by step solution

01

Define a valid probability function

For a function to be a valid probability function, the sum of all probabilities for the possible outcomes must equal 1. Also, each probability must be between 0 and 1, inclusive.
02

Calculate probabilities for each outcome

Using the given function \(f(x) = \frac{x}{6}\), calculate the probabilities for each possible outcome: \(f(1) = \frac{1}{6}, f(2) = \frac{2}{6}, f(3) = \frac{3}{6}\).
03

Validate the probability function

Add the probabilities from Step 2: \(\frac{1}{6} + \frac{2}{6} + \frac{3}{6} = 1\). Since the sum equals 1 and all probabilities are between 0 and 1, the probability function is valid.
04

Find probability of exactly 2 sessions

The probability that it takes exactly 2 sessions to gain the patient's trust is calculated as \(f(2) = \frac{2}{6} = \frac{1}{3}\).
05

Find probability of at least 2 sessions

To find the probability of requiring at least 2 sessions, sum the probabilities of 2 or 3 sessions: \(P(x \geq 2) = f(2) + f(3) = \frac{2}{6} + \frac{3}{6} = \frac{5}{6}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Random Variables
In probability and statistics, a random variable is a fundamental concept used to quantify the outcomes of a random phenomenon. It's essentially a variable that can take on different values, each with an assigned probability. In the context of the exercise, the random variable \(x\) represents the number of sessions required to gain a patient's trust, which can be 1, 2, or 3. These varying possible values are the outcomes we're interested in.
  • Random variables can be discrete (like here, with specific values) or continuous, depending on whether they include countable or uncountable values, respectively.
  • The probabilities assigned to each value of a random variable describe the likelihood of each outcome occurring.
The role of a random variable is to provide a structured approach to predict probabilities, helping facilitate further analysis or research.
Criteria for a Valid Probability
A valid probability function must meet certain criteria to ensure its accuracy and reliability when predicting outcomes.
For a probability function \(f(x)\) to be valid:
  • The sum of all possible probabilities must be 1, expressed mathematically as \(\sum_{x} f(x) = 1\). This requirement ensures that the function accounts for all possible outcomes.
  • Each individual probability \(f(x)\) must be between 0 and 1, inclusive, meaning each outcome is possible and properly constrained within the limits of 0% to 100% probability.
Applying these criteria to our exercise, we calculated each probability using the given function, \(f(x) = \frac{x}{6}\), where \(f(1) = \frac{1}{6}\), \(f(2) = \frac{2}{6}\), and \(f(3) = \frac{3}{6}\).
Checking the sum of these probabilities – \(\frac{1}{6} + \frac{2}{6} + \frac{3}{6} = 1\) – confirms the function is valid.
Understanding Probability Distributions
A probability distribution is a comprehensive explanation or visualization of all potential values of a random variable and their associated probabilities. It is an essential tool to understand the likelihood of various outcomes.
  • Discrete probability distributions, like in this exercise, involve specific, countable outcomes, such as the number of sessions here.
  • Key to these distributions is the probability function that predicts the chance of each specific outcome.
In our given scenario, the distribution is defined by the function \(f(x) = \frac{x}{6}\) for \(x = 1, 2,\) or \(3\). This function gives us a discrete probability distribution by detailing probabilities like \(P(x=2) = \frac{1}{3}\) and \(P(x \geq 2) = \frac{5}{6}\).
Understanding how the outcomes are distributed helps us grasp how likely different scenarios are when working to gain a patient's trust, thus aiding psychologists in managing expectations and planning their sessions.

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