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Find a power series representation for the function and determine the interval of convergence. $$ f(x)=\frac{1}{1+x} $$

Short Answer

Expert verified
Power series: \( \sum_{n=0}^{\infty} (-1)^n x^n \), interval: \(-1 < x < 1\).

Step by step solution

01

Identify the Base Series

Recognize that the function \( f(x) = \frac{1}{1+x} \) is similar to the geometric series \( \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n \) for \( |x| < 1 \). Rewrite \( f(x) \) in a similar form as \( \frac{1}{1-(-x)} \).
02

Write the Power Series Representation

Substitute \( x \) with \(-x\) in the geometric series representation. Thus, \( \frac{1}{1+x} = \sum_{n=0}^{\infty} (-x)^n = \sum_{n=0}^{\infty} (-1)^n x^n \).
03

Determine the Interval of Convergence

The series \( \sum_{n=0}^{\infty} (-1)^n x^n \) is derived from the geometric series and converges when \( |-x| < 1 \), which simplifies to \( |x| < 1 \). Thus, the interval of convergence for the function is \(-1 < x < 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
A geometric series is a sequence of numbers where each term is obtained by multiplying the previous term by a constant factor, known as the common ratio. In mathematical terms, a geometric series can be represented as follows:
  • \sum_{n=0}^{\infty} ar^n \ where "a" is the first term and "r" is the common ratio.
The geometric series is a powerful tool in calculus and analysis because its sum can be easily determined when the series converges. The most well-known geometric series is \( \sum_{n=0}^{\infty} x^n = \frac{1}{1-x} \)\ when \(|x| < 1\). If we alter this series by substituting \( x \) with \( -x \), it transforms into the power series representation of the function described in the original exercise. This change showcases the flexibility of the geometric series as a foundation for constructing other series.
Interval of Convergence
The interval of convergence is crucial when dealing with power series, as it specifies the range of x-values for which the series converges to a sum. For a standard geometric series with terms \( \sum_{n=0}^{\infty} x^n \), the series converges when the absolute value of the common ratio, \( |x| \), is less than 1.
  • Expressed differently, the series converges within the open interval \( (-1, 1) \).
When dealing specifically with the altered series \( \sum_{n=0}^{\infty} (-x)^n \), convergence is determined in the same manner as the regular geometric series. Here, \(|-x| < 1\) simplifies back to \(|x| < 1\), confirming that the interval is \(-1 < x < 1\). Understanding this concept ensures one uses the power series accurately, only within its interval of convergence.
Convergence
Convergence is a fundamental concept in the study of series. It describes whether a series approaches a finite limit as the number of terms increases indefinitely. A series "converges" if this sum becomes infinitely close to a specific value.Using the geometric series from the exercise, convergence was assessed by checking the condition \( |x| < 1 \). This absolute value condition ensures that each index term diminishes in size, allowing the overall series to settle toward a finite number. If \( |x| \) equals or exceeds 1, terms do not shrink appropriately, and the series diverges, meaning it doesn't approach any particular number.
  • The series \( \frac{1}{1+x} = \sum_{n=0}^{\infty} (-1)^n x^n \) converges in the interval \(-1 < x < 1\), ensuring it accurately portrays the function within this range.
Understanding where and why a series converges helps in effectively leveraging series representations for functions in calculus and applied mathematics.

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