/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Find the centroid of the region ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the centroid of the region bounded by the given curves. \(y=2-x^{2}, \quad y=x\)

Short Answer

Expert verified
The centroid of the region is \(\left(\frac{-1}{3}, \frac{-1}{18}\right)\).

Step by step solution

01

Sketch the Region

First, graph the given equations: \(y = 2 - x^2\) is a downward-opening parabola with a vertex at \((0, 2)\), and \(y = x\) is a straight line passing through the origin. Plot these curves to understand the region they enclose.
02

Determine Points of Intersection

Set the equations equal to each other to find their points of intersection: \(2 - x^2 = x\). Rearrange to get \(x^2 + x - 2 = 0\). Solving this quadratic using the formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), you find the solutions: \(x = 1\) and \(x = -2\). Thus, the curves intersect at \((1, 1)\) and \((-2, -2)\).
03

Setup the Integral for the Area

The centroid formula requires the area of the region \(A\). For the area between the curves, calculate \(A = \int_{-2}^{1} ((2-x^2) - x) \, dx\). This simplifies to \(A = \int_{-2}^{1} (2 - x^2 - x) \, dx\).
04

Calculate the Area

Compute the integral from Step 3: \(A = \int_{-2}^{1} (2 - x^2 - x) \, dx = \left[2x - \frac{x^3}{3} - \frac{x^2}{2}\right]_{-2}^{1}\). Evaluate at the bounds to find \(A = \left(2(1) - \frac{1^3}{3} - \frac{1^2}{2}\right) - \left(2(-2) - \frac{(-2)^3}{3} - \frac{(-2)^2}{2}\right)\), which simplifies to \(\frac{9}{2}\).
05

Set-up Centroids' x-Coordinate Integral

For the centroid \((\bar{x}, \bar{y})\), we find \(\bar{x} = \frac{1}{A} \int_{-2}^{1} x((2-x^2) - x) \, dx\). Simplify this to \(\int_{-2}^{1} x(2 - x^2 - x) \, dx\).
06

Calculate Centroids' x-Coordinate

Compute \(\int x(2 - x^2 - x) \), giving \( \frac{1}{A} \left[ x^2 - \frac{x^4}{4} - \frac{x^3}{3} \right]_{-2}^{1}\). Evaluate to get \(\bar{x} = \frac{-1.5}{\frac{9}{2}} = \frac{-1}{3}\).
07

Set-up Centroids' y-Coordinate Integral

Next, \(\bar{y} = \frac{1}{2A} \int_{-2}^{1} ((2-x^2)^2 - x^2)x \, dx \). This results from the formula for the centroid's y-coordinate.
08

Calculate Centroids' y-Coordinate

Further simplify \(\bar{y} = \frac{1}{2 \times \frac{9}{2}} \left[ \frac{x^3}{3} - \frac{x^5}{5} \right]_{-2}^{1} = \frac{-1}{18}\).
09

Write the Centroid Coordinates

Thus, the coordinates of the centroid are \((\bar{x}, \bar{y}) = \left(\frac{-1}{3}, \frac{-1}{18}\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centroid
The concept of the centroid is crucial in geometry and physics as it represents the "center of mass" of a region. For two-dimensional shapes, the centroid is a point where the entire area could be theoretically balanced. Calculating the centroid involves determining its coordinates, usually noted as \( (\bar{x}, \bar{y}) \). This is done by integrating across the region to account for its geometry and distribution.

To find the \( \bar{x} \) coordinate, one must integrate the product of \(x\) and the difference of the top and bottom functions over the interval of interest, and then divide by the total area of the region. For the \( \bar{y} \) coordinate, the process is similar but involves integrating the square of the difference of the functions, multiplied by \(x\).

The centroid's coordinates provide an insightful geometric interpretation, highlighting the point at which the shape's mass is evenly distributed, or in simpler terms, its balancing point.
Integrals
Integrals are fundamental in calculus, often used to calculate areas under curves, among many other applications. In this context, they help determine the area of regions enclosed between curves.

For the given problem, integrals allow us to express the area between two curves, \( y = 2 - x^2 \) and \( y = x \), by setting up an integral from the leftmost intersection point to the rightmost one. The difference between the top function and the bottom function over this range provides the height of an infinitesimally small strip of area, which we sum (integrate) across the entire region.

The integral used to calculate the area also forms the basis for computing the centroid coordinates. By integrating further products and transformations of these functions, we can find \( \bar{x} \) and \( \bar{y} \), as described in centroid calculations.
Quadratic Equations
Quadratic equations play a pivotal role in this problem by describing one of the bounding curves, namely the parabola \( y = 2 - x^2 \). Such equations are generally in the form \( ax^2 + bx + c = 0 \) and represent conic sections like ellipses, parabolas, and hyperbolas.

To find the points where the curves intersect, we set the quadratic equation equal to the linear one, \( y = x \), leading to \( x^2 + x - 2 = 0 \). Solving this quadratic equation gives the intersection points, which are critical in determining the region's extent for integration.

The quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) is used here to find these vital points. Understanding quadratic equations is essential for anyone studying calculus, as they frequently appear in scenarios requiring intersection points or analysis of motion.
Area of Regions
Calculating the area of regions bounded by curves integrates several key calculus concepts. Here, the task is to find the area enclosed by two curves, which requires identifying their intersection points and using them as limits of integration.

The definite integral \( \int_{a}^{b} (f(x) - g(x)) \, dx \) is used to find the area between two functions \( f(x) \) and \( g(x) \) over an interval \([a, b]\). For the specific region between \( y = 2 - x^2 \) and \( y = x \), the correct setup is crucial to ensure we subtract the lower function from the upper one correctly.

These calculations can become more complex if the curves intersect more than once or have multiple regions, but the foundational approach remains the same. Practicing these concepts builds a solid understanding of area computation, which is widely applied in sciences and engineering.

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Most popular questions from this chapter

One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction \(y\) of the population who have heard the rumor and the fraction who have not heard the rumor. (a) Write a differential equation that is satisfied by y. (b) Solve the differential equation. (c) A small town has 1000 inhabitants. At 8 AM, 80 people have heard a rumor. By noon half the town has heard it. At what time will 90 \(\%\) of the population have heard the rumor?

Use Simpson's Rule with \(n=10\) to estimate the arc length of the curve. Compare your answer with the value of the integral produced by your calculator. $$y=\ln \left(1+x^{3}\right), \quad 0 \leqslant x \leqslant 5$$

Find the volume common to two circular cylinders, each with radius \(r,\) if the axes of the cylinders intersect at right angles.

Use either a computer algebra system or a table of integrals to find the exact length of the arc of the curve \(y=x^{4 / 3}\) that lies between the points \((0,0)\) and \((1,1) .\) If your CAS has trouble evaluating the integral, make a substitution that changes the integral into one that the CAS can evaluate.

A metal plate was found submerged vertically in sea water, which has density 64 lb/ft \(^{3}\) . Measurements of the width of the plate were taken at the indicated depths. Use Simpson's Rule to estimate the force of the water against the plate. $$\begin{array}{|c|c|c|c|c|c|c|}\hline \text { Depth (m) } & {7.0} & {7.4} & {7.8} & {8.2} & {8.6} & {9.0} & {9.4} \\ \hline \text { Plate width (m) } & {1.2} & {1.8} & {2.9} & {3.8} & {3.6} & {4.2} & {4.4} \\ \hline\end{array}$$

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