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\(3-7=\) Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the \(y\) -axis. $$y=\sqrt[3]{x}, \quad y=0, \quad x=1$$

Short Answer

Expert verified
\(\frac{6\pi}{7}\).

Step by step solution

01

Understanding the Problem

We are given the curves \(y = \sqrt[3]{x}\), \(y = 0\), and \(x = 1\), and we need to find the volume of the solid generated by rotating the region bounded by these curves about the \(y\)-axis. The cylindrical shells method is suitable for finding this volume.
02

Shell Method Formula

The formula for the volume of a solid of revolution using the cylindrical shell method is: \[ V = 2\pi \int_{a}^{b} (radius)(height)\,dx \]For this particular problem, the radius of each shell is \(x\) and the height is \(y = \sqrt[3]{x}\).
03

Setting Up the Integral

Substitute the values for radius and height into the shell method formula. The bounds \(a = 0\) and \(b = 1\) come from the given limits of \(x\). \[ V = 2\pi \int_{0}^{1} x(\sqrt[3]{x})\,dx \] This simplifies to: \[ V = 2\pi \int_{0}^{1} x^{4/3}\,dx \]
04

Integrating the Function

Integrate the function \(x^{4/3}\): \[ \int x^{4/3}\,dx = \frac{x^{7/3}}{7/3} = \frac{3}{7}x^{7/3} \]
05

Calculating the Volume

Evaluate the integrated function from \(x = 0\) to \(x = 1\): \[ V = 2\pi \left[ \frac{3}{7}x^{7/3} \right]_{0}^{1} \] This gives: \[ V = 2\pi \left( \frac{3}{7}(1) - \frac{3}{7}(0) \right) = 2\pi \cdot \frac{3}{7} = \frac{6\pi}{7} \]
06

Final Answer

The volume of the solid formed by rotating the region about the \(y\)-axis is \(\frac{6\pi}{7}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume of Revolution
The Volume of Revolution refers to the volume of a 3D shape created when a 2D area is revolved around an axis. Imagine you have a flat shape like a piece of paper. If you spin this shape around a line, it becomes a solid object, just like twirling a piece of dough into a donut! To calculate this volume, mathematicians often use methods like the Disk Method, Washer Method, or Cylindrical Shells Method.

These methods rely on integration techniques to add up infinitely many infinitesimally small slices or shells of the solid. Using the Cylindrical Shells Method, we calculate the volume by integrating along the axis we rotate around and considering each tiny infinitely thin cylindrical shell that forms as a piece of the solid.

In the exercise, the given curves are spun around the y-axis, creating a solid of revolution shaped like a horn, wide at the base and tapering off to a point. Understanding this concept is crucial for modeling and solving real-world problems involving rotational shapes, such as engineering and physics applications.
Integration Techniques
Integration Techniques involve a variety of strategies to solve integrals, which are essential for calculating areas, volumes, and other quantities. The integral used in the Cyndrical Shells Method requires finding the sum of an infinite series of small quantities to obtain the total volume.

In the provided solution steps, the shell method is used to integrate the function representing a solid's volume generated by rotating a curve about the y-axis. The function given to us is \(x^{4/3}\), and we integrate it with respect to \(x\) from the lower limit 0 to the upper limit 1.

The integral expression is \[2\pi \int_{0}^{1} x^{4/3}\,dx\]. To solve this, we use the power rule for integration, which involves increasing the power of \(x\) by one and dividing by the new power. This converts \(x^{4/3}\) into \(\frac{x^{7/3}}{7/3}\).

Integrating each step by working through the mathematical process is fundamental in reaching the correct final answer.
Solid of Revolution
A Solid of Revolution is a 3D object made by spinning a 2D area around an axis. Think of it like spinning a curved line on a piece of paper around a pencil to form an object like a vase or a cone. This creates a solid shape whose volume we can calculate using calculus methods.

There are various techniques to do this: cylindrical shells, disks, or washers. By choosing cylindrical shells, we can simplify finding the volume of a solid formed around the y-axis. This is particularly useful for regions bounded by curves that are better suited to shell integration.

The exercise involves finding the volume created by revolving the curve \(y = \sqrt[3]{x}\), bounded by \(y = 0\) and \(x = 1\), about the y-axis. Each cylindrical shell has a height determined by the curve and a radius depending on the position horizontally (\(x\)-value).

This method offers an alternative, often simpler approach when the shape is more naturally described by vertical slices rather than horizontal ones, effectively transforming the problem-solving process.

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Most popular questions from this chapter

A wedge is cut out of a circular cylinder of radius 4 by two planes. One plane is perpendicular to the axis of the cylinder. The other intersects the first at an angle of \(30^{\circ}\) along a diameter of the cylinder. Find the volume of the wedge.

Find the function \(f\) such that \(f^{\prime}(x)=f(x)(1-f(x))\) and \(f(0)=\frac{1}{2} .\)

Some of the pioneers of calculus, such as Kepler and Newton, were inspired by the problem of finding the volumes of wine barrels. (In fact Kepler published a book Stereometria doliorum in 1715 devoted to methods for finding the volumes of barrels.) They often approximated the shape of the sides by parabolas. (a) A barrel with height \(h\) and maximum radius \(R\) is constructed by rotating about the \(x\) -axis the parabola \(y=R-c x^{2},-h / 2 \leqslant x \leqslant h / 2,\) where \(c\) is a positive constant. Show that the radius of each end of the barrel is \(r=R-d,\) where \(d=c h^{2} / 4\) (b) Show that the volume enclosed by the barrel is $$ V=\frac{1}{3} \pi h\left(2 R^{2}+r^{2}-\frac{2}{5} d^{2}\right) $$

Find the arc length function for the curve \(y=2 x^{3 / 2}\) with starting point \(P_{0}(1,2)\) .

The air in a room with volume 180 \(\mathrm{m}^{3}\) contains \(0.15 \%\) carbon dioxide initially. Fresher air with only 0.05\(\%\) carbon dioxide flows into the room at a rate of 2 \(\mathrm{m}^{3} / \mathrm{min}\) and the mixed air flows out at the same rate. Find the percentage of carbon dioxide in the room as a function of time. What happens in the long run?

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