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\(21-26=\) (a) Set up an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. (b) Use your calculator to evaluate the integral correct to five decimal places. $$y=x e^{-x}, y=0, x=2 ; \quad \text { about the } y$$

Short Answer

Expert verified
Integral: \(2\pi \int_{0}^{2} x^2 e^{-x} \, dx = 2.07899\)

Step by step solution

01

Identify the Functions and Bounds

We are given the functions \( y = x e^{-x} \) and \( y = 0 \), with \( x = 0 \) and \( x = 2 \). These define a region in the first quadrant bounded vertically by \( y = 0 \), horizontally by \( x = 0 \), \( x = 2 \), and above by \( y = x e^{-x} \).
02

Set Up the Integral Expression for Volume

The volume of the solid obtained by rotating this region about the \( y \)-axis can be found using the method of cylindrical shells. The formula for the volume \( V \) is given by: \[ V = 2\pi \int_{a}^{b} x \cdot f(x) \, dx \] where \( f(x) = x e^{-x} \), \( a = 0 \), and \( b = 2 \). So the integral becomes: \[ V = 2\pi \int_{0}^{2} x^2 e^{-x} \, dx \]
03

Evaluate the Integral with a Calculator

Use a calculator to evaluate the integral. Set the expression in the calculator as: \[ 2\pi \int_{0}^{2} x^2 e^{-x} \, dx \] This integral evaluates approximately to: 2.07899 after inputting the expression into a calculator and calculating the numerical integral to five decimal places.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Shells Method
The cylindrical shells method is a technique used in calculus to find the volume of a solid of revolution. This method is particularly useful when the axis of rotation is parallel to the axis of the function being integrated. In this method, we imagine wrapping the region around the axis into cylindrical shells.
Here's how it works:
  • We take a small vertical strip of the region, which becomes part of a cylindrical shell when the region is rotated.
  • This shell has a radius equal to the distance from the strip to the axis of rotation, and its height is given by the function value at that strip.
  • The volume of the shell is given by the lateral surface area, which is the circumference multiplied by the height, then by the thickness (or in our case, an infinitesimal width of the strip, denoted as \( dx \)).
The volume formula is expressed as:\[ V = 2\pi \int_{a}^{b} x \cdot f(x) \, dx \]where \( x \) is the radius of the shell and \( f(x) \) is the height. Then, we integrate over the entire region from \( a \) to \( b \). This method simplifies the calculation as it bends the problem into easily manageable parts.
Definite Integral
A definite integral is a type of integral that finds the exact area under a curve bounded by two points on the x-axis. This involves different techniques, one of them being the use of definite integrals to compute the volume of solids of revolution by employing methods like the cylindrical shells method.
The mathematical representation of a definite integral from \( a \) to \( b \) of a function \( f(x) \) is:\[ \int_{a}^{b} f(x) \, dx \]Definite integrals can be thought of as a limit of the approximate sums using infinitely many partitions or slices of the region under the curve. The result gives the accumulated total, which in the context of our problem refers to the entire volume of the solid.
For rotation problems, the definite integral helps in summing up areas or volumes, making exact calculations possible. The limits \( a \) and \( b \) are essential, marking the start and end of the calculation, encompassing all the area between these two boundaries.
Numerical Integration
Numerical integration is a technique used when an integral cannot be computed analytically, or to verify an analytical solution. Calculators or software are typically employed to estimate the value of complex integrals, especially when dealing with functions that lack a simple antiderivative.
There are several methods of numerical integration, such as
  • Simple Riemann sums,
  • Trapezoidal rule, and
  • Simpson’s rule.
These methods work by approximating the area under the curve or the volume of the solid by dividing the region into small, simple shapes (like rectangles or trapezoids), and then summing those areas.
In the context of our problem, a calculator is used to evaluate the integral numerically correct to five decimal places. This ensures precision, crucial when exact calculation is needed, as in different applications of engineering or physics.
Rotating Regions
Rotating regions is a primary concept in calculating the volume of solids of revolution. This involves taking a two-dimensional area and revolving it around an axis to create a three-dimensional object.
To achieve this:
  • The identified region has boundaries, established by curves or specific lines.
  • When this region revolves around an axis, it generates a solid whose volume can be computed using integration techniques.
Different axes of rotation, such as the x-axis or y-axis, affect the shape and resulting volume of the solid. It's important to identify the correct boundaries and rotation axis to apply the right formula and technique, such as using either the disk, washer, or cylindrical shells method.
The application of these concepts allows for a diverse range of practical uses, from designing objects to predicting the behavior of systems in motion. Understanding how to rotate regions helps in visualizing and solving complex real-world problems.

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Most popular questions from this chapter

Suppose you make napkin rings by drilling holes with different diameters through two wooden balls (which also have different diameters). You discover that both napkin rings have the same height \(h,\) as shown in the figure. (a) Guess which ring has more wood in it. (b) Check your guess: Use cylindrical shells to compute the volume of a napkin ring created by drilling a hole with radius \(r\) through the center of a sphere of radius \(R\) and express the answer in terms of \(h .\)

(a) Find the arc length function for the curve \(y=\ln (\sin x), 0

An object of mass \(m\) is moving horizontally through a medium which resists the motion with a force that is a function of the velocity; that is, $$m \frac{d^{2} s}{d t^{2}}=m \frac{d v}{d t}=f(v)$$ where \(v=v(t)\) and \(s=s(t)\) represent the velocity and position of the object at time \(t,\) respectively. For example, think of a boat moving through the water. (a) Suppose that the resisting force is proportional to the velocity, that is, \(f(v)=-k v, k\) a positive constant. (This model is appropriate for small values of v.) Let \(v(0)=v_{0}\) and \(s(0)=s_{0}\) be the initial values of \(v\) and \(s\) Determine \(v\) and \(s\) at any time \(t .\) What is the total distance that the object travels from time \(t=0 ?\) (b) For larger values of \(v\) a better model is obtained by supposing that the resisting force is proportional to the square of the velocity, that is, \(f(v)=-k v^{2}, k>0 .\) (This model was first proposed by Newton.) Let \(v_{0}\) and \(s_{0}\) be the initial values of \(v\) and \(s .\) Determine \(v\) and \(s\) at any time \(t .\) What is the total distance that the object travels in this case?

\(21-24=\) Match the differential equation with its direction field (labeled I-IV). Give reasons for your answer. $$y^{\prime}=2-y$$

Find the arc length function for the curve \(y=2 x^{3 / 2}\) with starting point \(P_{0}(1,2)\) .

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