Chapter 7: Problem 1
\(1-8=\) Solve the differential equation. $$\frac{d y}{d x}=x y^{2}$$
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Chapter 7: Problem 1
\(1-8=\) Solve the differential equation. $$\frac{d y}{d x}=x y^{2}$$
These are the key concepts you need to understand to accurately answer the question.
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\(1-8=\) Solve the differential equation. $$\frac{d p}{d t}=t^{2} p-p+t^{2}-1$$
Suppose that 2 \(\mathrm{J}\) of work is needed to stretch a spring from its natural length of 30 \(\mathrm{cm}\) to a length of 42 \(\mathrm{cm} .\) (a) How much work is needed to stretch the spring from 35 \(\mathrm{cm}\) to 40 \(\mathrm{cm}?\) (b) How far beyond its natural length will a force of 30 \(\mathrm{N}\) keep the spring stretched?
(a) Newton's Law of Gravitation states that two bodies with masses \(m_{1}\) and \(m_{2}\) attract each other with a force $$F=G \frac{m_{1} m_{2}}{r^{2}}$$ where \(r\) is the distance between the bodies and \(G\) is the gravitational constant. If one of the bodies is fixed, find the work needed to move the other from \(r=a\) to \(r=b\). (b) Compute the work required to launch a 1000-kg satellite vertically to a height of 1000 \(\mathrm{km} .\) You may assume that the earth's mass is \(5.98 \times 10^{24} \mathrm{kg}\) and is concentrated at its center. Take the radius of the earth to be \(6.37 \times 10^{6} \mathrm{m}\) and \(G=6.67 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}\).
Use Simpson's Rule with \(n=10\) to estimate the arc length of the curve. Compare your answer with the value of the integral produced by your calculator. $$y=e^{-x^{2}}, \quad 0 \leqslant x \leqslant 2$$
\(1-8=\) Solve the differential equation. $$\frac{d y}{d \theta}=\frac{e^{y} \sin ^{2} \theta}{y \sec \theta}$$
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