/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Evaluate the integral. \(\int_... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integral. \(\int_{0}^{\pi / 2} \cos ^{2} \theta d \theta\)

Short Answer

Expert verified
\(\frac{\pi}{4}\)

Step by step solution

01

Apply the Power-Reduction Formula

To evaluate the integral \( \int_{0}^{\pi / 2} \cos^{2} \theta \, d\theta \), we first use the power-reduction identity for cosine. The formula is: \( \cos^2 \theta = \frac{1 + \cos 2\theta}{2} \). Substitute this identity into the integral:\[ \int_{0}^{\pi / 2} \cos^{2} \theta \, d\theta = \int_{0}^{\pi / 2} \frac{1 + \cos 2\theta}{2} \, d\theta \]
02

Split the Integral

Split the integral into two separate integrals:\[ \int_{0}^{\pi / 2} \frac{1}{2} \, d\theta + \int_{0}^{\pi / 2} \frac{\cos 2\theta}{2} \, d\theta \]
03

Evaluate the First Integral

Evaluate the first integral, which is simple since it involves a constant:\[ \int_{0}^{\pi / 2} \frac{1}{2} \, d\theta = \left[ \frac{\theta}{2} \right]_{0}^{\pi / 2} = \frac{\pi}{4} \]
04

Evaluate the Second Integral

Evaluate the second integral. We use substitution. Let \( u = 2\theta \) then \( du = 2 \, d\theta \), which means \( d\theta = \frac{du}{2} \). Change the limits of integration accordingly; when \( \theta = 0 \), \( u = 0 \) and when \( \theta = \frac{\pi}{2} \), \( u = \pi \).The integral becomes:\[ \int_{0}^{\pi / 2} \frac{\cos 2\theta}{2} \, d\theta = \int_{0}^{\pi} \frac{\cos u}{4} \, du \]Evaluate the integral:\[ \int_{0}^{\pi} \frac{\cos u}{4} \, du = \frac{1}{4} \left[ \sin u \right]_{0}^{\pi} = \frac{1}{4} (\sin \pi - \sin 0) = \frac{1}{4} (0 - 0) = 0 \]
05

Combine the Results

Combine the results from Steps 3 and 4:\[ \int_{0}^{\pi / 2} \cos^{2} \theta \, d\theta = \frac{\pi}{4} + 0 = \frac{\pi}{4} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power-Reduction Formula
In trigonometric integration, especially when dealing with powers of sine and cosine, the power-reduction formulas are incredibly useful. For cosine, the power-reduction formula is given as \( \cos^2 \theta = \frac{1 + \cos 2\theta}{2} \). This transforms the integral of \( \cos^2 \theta \) into a simpler form that involves linear trigonometric functions.

By using this formula, we can break down complex trigonometric expressions into forms that are easier to integrate. This is because integrating a sinusoidal function directly is often simpler than working with their squares or higher powers. When you see \( \cos^2 \theta \) or \( \sin^2 \theta \) in an integral, think of applying the power-reduction formula as your tool to simplify the expression.

Remember these key points:
  • The power-reduction formulas are essential for simplifying integrals with power terms
  • Using these formulas can help avoid more complicated integration techniques
  • This method is especially helpful in definite integrals where the limits remain the same even after substitution
Definite Integral
A definite integral calculates the area under a curve between two points, providing a specific numerical value rather than a general function. In this example, the definite integral \( \int_{0}^{\pi / 2} \cos^{2} \theta \, d\theta \) calculates the area under the curve of \( \cos^2 \theta \) from \(0\) to \(\pi/2\).

When solving a definite integral:
  • Identify the function and the limits of integration
  • To solve, you can split the integral into simpler parts, as was done by rewriting using the power-reduction formula first
  • Calculate each part separately and make sure to adjust the limits of integration if substitution is employed
  • Finally, combine the results of each section to find the total area
Understanding definite integrals is crucial because they allow for precise calculations in areas such as physics and engineering, where determining exact quantities of areas or other metrics is necessary.
Trigonometric Integration
Trigonometric integration involves integrating functions that consist of trigonometric expressions. They often employ identities and formulas to simplify the integration process. In our example, the integration of \( \cos^2 \theta \) initially uses the power-reduction identity, turning the problem into a more manageable task.

This simplification is emblematic of trigonometric integration, where breaking down complex trigonometric terms into simpler parts or other recognizable integrals makes the integration possible.

Key strategies when performing trigonometric integration include:
  • Using identities to reduce powers or simplify expressions
  • Splitting integrals into sum or difference of simpler integrals
  • Recognizing standard integrals (e.g., integrals of \( \sin x \) or \( \cos x \))
When mastering trigonometric integration, practice is crucial. Familiarize yourself with different identities and remember that the goal is to translate a complex function into something more straightforward that can be easily integrated.
Substitution Method
The substitution method, also known as \( u \)-substitution, is a technique used to simplify integrals by changing variables. It's akin to reverse differentiation and is particularly helpful in evaluating integrals involving composite functions. In the given example, substitution is employed when integrating \( \cos 2\theta \).

Here’s how it works:
  • Choose a new variable \( u \) that ultimately simplifies the integral
  • Relate \( u \) to the original variable; for instance, let \( u = 2\theta \)
  • Determine \( du \), which involves differentiating \( u \) with respect to the original variable
  • Substitute \( u \) and \( du \) into the integral, converting the entire expression to terms of \( u \)
  • Adjust the limits of integration if dealing with a definite integral
Once you have evaluated the new integral in terms of \( u \), return to the original variable if needed.

The substitution method is powerful because it streamlines complex integrals, making them more straightforward to solve. It requires recognizing patterns and understanding how different parts of the integral relate to one another.

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Most popular questions from this chapter

(a) A table of values of a function \(g\) is given. Use Simpson's Rule to estimate \(\int_{0}^{1.6} g(x) d x\) (b) If \(-5 \leqslant g^{(4)}(x) \leqslant 2\) for \(0 \leqslant x \leqslant 1.6,\) estimate the error involved in the approximation in part (a).

Sketch the graph of a continuous function on \([0,2]\) for which the right endpoint approximation with \(n=2\) is more accurate than Simpson's Rule.

Use a computer algebra system to evaluate the integral. Compare the answer with the result of using tables. If the answers are not the same, show that they are equivalent. $$\int x^{2} \sqrt{1-x^{2}} d x$$

Computer algebra systems sometimes need a helping hand from human beings. Try to evaluate $$\int(1+\ln x) \sqrt{1+(x \ln x)^{2}} d x$$ with a computer algebra system. If it doesn't return an answer, make a substitution that changes the integral into one that the CAS can evaluate.

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number of sterile males that mate with fertile females but produce no offspring. If \(P\) represents the number of female insects in a population, \(S\) the number of sterile males introduced each generation, and \(r\) the population's natural growth rate, then the female population is related to time \(t\) by $$t=\int \frac{P+S}{P[(r-1) P-S]} d P$$ Suppose an insect population with \(10,000\) females grows at a rate of \(r=0.10\) and 900 sterile males are added. Evaluate the integral to give an equation relating the female population to time. (Note that the resulting equation can't be solved explicitly for P.)

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