Chapter 6: Problem 34
The figure shows a pendulum with length \(L\) that makes a maximum angle \(\theta_{0}\) with the vertical. Using Newton's Second Law, it can be shown that the period \(T\) (the time for one complete swing) is given by $$T=4 \sqrt{\frac{L}{g}} \int_{0}^{\pi / 2} \frac{d x}{\sqrt{1-k^{2} \sin ^{2} x}}$$ where \(k=\sin \left(\frac{1}{2} \theta_{0}\right)\) and \(g\) is the acceleration due to gravity. If \(L=1 \mathrm{m}\) and \(\theta_{0}=42^{\circ},\) use Simpson's Rule with \(n=10\) to find the period.
Short Answer
Step by step solution
Convert Angle to Radians
Calculate k
Setup Simpson's Rule
Evaluate Function at the Endpoints
Evaluate Function at Subinterval Points
Apply Simpson's Rule Formula
Calculate Final Integration Result
Find Period T
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