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Determine whether each integral is convergent or divergent. Evaluate those that are convergent. $$\int_{2}^{3} \frac{1}{\sqrt{3-x}} d x$$

Short Answer

Expert verified
The integral is convergent and evaluates to 2.

Step by step solution

01

Identify Integral and Limits

We are given the integral \( \int_{2}^{3} \frac{1}{\sqrt{3-x}} \, dx \). This is a definite integral with limits from 2 to 3. We need to determine if it's convergent or divergent and evaluate it if convergent.
02

Recognize Type of Improper Integral

Notice the integrand \( \frac{1}{\sqrt{3-x}} \). As \( x \to 3^- \), the expression \( \sqrt{3-x} \to 0 \), leading the integrand to become unbounded. This makes it an improper integral of the second kind.
03

Set Up and Analyze Limit

To handle the improper nature, evaluate the limit approaching 3 from the left. Define the integral as \( \lim_{b \to 3^-} \int_{2}^{b} \frac{1}{\sqrt{3-x}} \, dx \).
04

Perform Substitution

Use the substitution \( u = 3 - x \), which implies \( du = -dx \). Changing the limits, when \( x = 2 \), \( u = 1 \), and when \( x = b \), \( u = 3 - b \). The integral becomes \( \lim_{b \to 3^-} \int_{1}^{3-b} \frac{-1}{\sqrt{u}} \, du \).
05

Solve the Integral

The integral \( \int \frac{1}{\sqrt{u}} \, du = 2 \sqrt{u} \). Thus, \( \lim_{b \to 3^-} \left[-2\sqrt{u}\right]_{1}^{3-b} = \lim_{b \to 3^-} \left(-2\sqrt{3-b} + 2\right) \).
06

Evaluate the Limit

Compute the limit \( \lim_{b \to 3^-} \left(-2\sqrt{3-b} + 2\right). \) As \( b \to 3 \), \( \sqrt{3-b} \to 0 \), so the limit evaluates to 2.
07

Conclusion

The original integral is convergent, and the evaluated integral value is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Integrals
When we talk about the convergence of integrals, we're exploring whether a particular integral has a finite value. This is especially important for improper integrals, which involve infinite or undefined behavior. In the case of the integral \( \int_{2}^{3} \frac{1}{\sqrt{3-x}} \, dx \), the improper nature arises because the integrand becomes unbounded as \( x \) approaches 3. To determine convergence, we carefully analyze the limit of the integral as it approaches the troublesome point. If this limit evaluates to a finite number, the integral is said to be convergent. In our example, we set up the limit \( \lim_{b \to 3^-} \int_{2}^{b} \frac{1}{\sqrt{3-x}} \, dx \), which transforms the problem into something manageable. For students, understanding convergence is crucial because it determines whether the integral expressions they work with will yield meaningful results. Whenever you encounter an unbounded behavior, always remember to examine it with a limit to address the improperness.
Definite Integrals
Definite integrals are mathematical expressions representing the accumulation of quantities, generally over a specific interval. In the integral \( \int_{2}^{3} \frac{1}{\sqrt{3-x}} \, dx \), the bounds of 2 and 3 denote the interval over which you're summing the function values. This is different from an indefinite integral, which results in a general form without specific boundaries. The limits on a definite integral turn it into a concrete number, assuming convergence, reflecting the total accumulated quantity across the interval. For definite integrals:
  • The lower limit is where you start the calculation.
  • The upper limit is where you end the calculation.
  • It's essential to assess the behavior of the function across these bounds.
In our exercise, though the upper limit presents a problem point, once we handle the improper nature, it evaluates to an exact number: 2.
Substitution Method
The substitution method is a clever technique used to simplify integrals by re-defining variables. It works much like a change of variables in algebra. For the integral \( \int_{2}^{3} \frac{1}{\sqrt{3-x}} \, dx \), we use substitution to make solving easier.Consider substituting \( u = 3 - x \). This substitution simplifies the expression under the radical and requires adjusting the differential as well: \( du = -dx \). This makes the integral change from \( \int_{2}^{b} \frac{1}{\sqrt{3-x}} \, dx \) to \( \int_{1}^{3-b} \frac{-1}{\sqrt{u}} \, du \). When changing variables:
  • Ensure all instances of the original variable are replaced.
  • Adjust the limits of integration to match your new variable.
  • Don’t forget the factor from the derivative of your substitution.
This simplifies not only the computation but also helps in dealing with any boundary points or limits, making the integral more straightforward to evaluate. After substitution, the resulting integral is easier, often leading to an accessible closed-form solution or further simplification.

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Most popular questions from this chapter

Find the approximations \(T_{n}, M_{n},\) and \(S_{n}\) to the integral \(\int_{1}^{4} 1 / \sqrt{x} d x\) for \(n=6\) and \(12 .\) Then compute the corresponding errors \(E_{T}, E_{M},\) and \(E_{S}\) . (Round your answers to six decimal places. You may wish to use the sum command on a computer algebra system.) What observations can you make? In particular, what happens to the errors when \(n\) is doubled?

Sketch the graph of a continuous function on \([0,2]\) for which the Trapezoidal Rule with \(n=2\) is more accurate than the Midpoint Rule.

Determine whether each integral is convergent or divergent. Evaluate those that are convergent. $$\int_{-\infty}^{\infty} x^{2} e^{-x^{3}} d x$$

Use the Trapezoidal Rule with \(n=10\) to approximate \(\int_{0}^{20} \cos (\pi x) d x\) . Compare your result to the actual value. Can you explain the discrepancy?

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number of sterile males that mate with fertile females but produce no offspring. If \(P\) represents the number of female insects in a population, \(S\) the number of sterile males introduced each generation, and \(r\) the population's natural growth rate, then the female population is related to time \(t\) by $$t=\int \frac{P+S}{P[(r-1) P-S]} d P$$ Suppose an insect population with \(10,000\) females grows at a rate of \(r=0.10\) and 900 sterile males are added. Evaluate the integral to give an equation relating the female population to time. (Note that the resulting equation can't be solved explicitly for P.)

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