Chapter 5: Problem 47
Use the properties of integrals to verify that $$0\leqslant \int_{1}^{3} \ln x d x \leqslant 2 \ln 3$$ without evaluating the integral.
Short Answer
Expert verified
The inequality holds: \( 0 \leq \int_{1}^{3} \ln x \, dx \leq 2 \ln 3 \).
Step by step solution
01
Understand the Integral Properties
We need to verify the given inequality without solving the integral. The properties of integrals that can be useful are: (1) if a function \( f(x) \) is non-negative on the interval \([a, b]\), then \( \int_{a}^{b} f(x) \, dx \geq 0 \), and (2) if \( f(x) \) is less than or equal to some constant \( M \) on the interval \([a, b]\), then \( \int_{a}^{b} f(x) \, dx \leq M(b-a) \).
02
Analyze the Function \( \ln x \)
The natural logarithm function \( \ln x \) is increasing on its domain and non-negative for \( x \geq 1 \). Thus on the interval \([1, 3]\), \( \ln x \geq 0 \). This verifies the first part of the inequality: \( 0 \leq \int_{1}^{3} \ln x \, dx \).
03
Establish an Upper Bound for \( \ln x \)
On the interval \([1, 3]\), the maximum value of \( \ln x \) occurs at \( x = 3 \). Therefore, \( \ln x \leq \ln 3 \) for all \( x \in [1, 3] \).
04
Apply the Integral Properties for the Upper Bound
Using the upper bound \( \ln x \leq \ln 3 \), apply the integral property: \( \int_{1}^{3} \ln x \, dx \leq \int_{1}^{3} \ln 3 \, dx \). Since \( \ln 3 \) is a constant, this integral simplifies to \( \ln 3 \cdot (3-1) = 2 \ln 3 \).
05
Conclude the Inequality Verification
By combining the results from Steps 2 and 4, the integral inequality \( 0 \leq \int_{1}^{3} \ln x \, dx \leq 2 \ln 3 \) is verified without evaluating the integral.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Natural Logarithm
The natural logarithm, denoted as \( \ln x \), is a mathematical function with several notable properties. It is the logarithm to the base \( e \), where \( e \) is an irrational and transcendental number approximately equal to 2.718. The natural logarithm has a domain for all positive real numbers, meaning you can only plug in positive numbers, and its range spans all real numbers.
Key characteristics of the natural logarithm \( \ln x \):
Key characteristics of the natural logarithm \( \ln x \):
- It is continuous for all \( x > 0 \), meaning there are no jumps or breaks in the function.
- On its domain, \( \ln x \) is an increasing function. This means as \( x \) increases, \( \ln x \) also increases.
- The function is non-negative for values of \( x \geq 1 \). This can help establish lower bounds when integrated.
- For integration purposes, the properties of \( \ln x \) allow us to evaluate or estimate integrals over certain intervals as seen in inequalities.
Grasping Integral Inequality
Integral inequalities involve comparing the integral of a function to a constant or another integral. They are useful in estimating or bounding the values of integrals without computing the exact integral. Here, we focus on bounding the integral of \( \ln x \) over the interval \([1, 3]\) by using properties of inequalities.
To prove \( 0 \leq \int_{1}^{3} \ln x \, dx \leq 2 \ln 3 \) without solving, follow these steps:
To prove \( 0 \leq \int_{1}^{3} \ln x \, dx \leq 2 \ln 3 \) without solving, follow these steps:
- If a function \( f(x) \) is non-negative on an interval \([a, b]\), then \( \int_{a}^{b} f(x) \, dx \geq 0 \). Given \( \ln x \) is non-negative for \( x \geq 1 \), establishing the lower bound is straightforward.
- Find an upper bound by ensuring \( f(x) \leq M \) on \([a, b]\). If \( \ln x \leq \ln 3 \) on \([1, 3]\), then \( \int_{1}^{3} \ln x \, dx \leq \int_{1}^{3} \ln 3 \, dx \).
- The integral of a constant \( \ln 3 \) over \([1, 3]\) is simply \( (3-1) \cdot \ln 3 = 2 \ln 3 \), justifying the upper bound of the original inequality.
Exploring Function Analysis
Function analysis involves dissecting the function's behavior over a given domain. For the function \( \ln x \), this means understanding how it acts over the specified interval \([1, 3]\). This analysis not only supports the inequality assessment but also broadens your mathematical perspective.
Key considerations in function analysis:
Key considerations in function analysis:
- Monotonicity: As an increasing function, \( \ln x \) ensures continuity and predictability over the interval \([1, 3]\). This trait aids in finding bounds for integrals.
- Critical Points: Although \( \ln x \) doesn't have critical points where \( x \in (1,3) \) (where its derivative changes sign), its continuous increase makes \( x=3 \) its maximum on the closed interval.
- Function Boundaries: Setting realistic upper limits, such as \( \ln 3 \), helps contextualize the function's behavior while strengthening understanding of how it integrates over the interval.