Chapter 5: Problem 41
\(41-42=\) Find the general indefinite integral. Mlustrate by graphing several members of the family on the same screen. $$\int x \sqrt{x} d x$$
Short Answer
Expert verified
The integral is \( \int x \sqrt{x} \, dx = \frac{2}{5} x^{5/2} + C \). Graphs vary with different \( C \) values.
Step by step solution
01
Simplify the Integrand
To solve the integral \( \int x \sqrt{x} \, dx \), first express \( \sqrt{x} \) using exponent notation. Since \( \sqrt{x} = x^{1/2} \), we rewrite the integrand as \( x \cdot x^{1/2} = x^{3/2} \). Thus, the integral becomes \( \int x^{3/2} \, dx \).
02
Apply the Power Rule for Integration
The power rule for integration states \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration. Applying this rule with \( n = \frac{3}{2} \), we get:\[ \int x^{3/2} \, dx = \frac{x^{5/2}}{5/2} + C \]This simplifies to \( \frac{2}{5} x^{5/2} + C \).
03
Final Integral Expression
The indefinite integral of the function is:\[ \int x \sqrt{x} \, dx = \frac{2}{5} x^{5/2} + C \]This represents a family of functions depending on the constant \( C \).
04
Graph Several Members of the Family
To graph members of the family of the indefinite integral, we select different values for \( C \). For example, calculate and plot the functions \( y = \frac{2}{5} x^{5/2} \), \( y = \frac{2}{5} x^{5/2} + 1 \), and \( y = \frac{2}{5} x^{5/2} - 1 \). These graphs will all be vertically shifted versions of the base function \( \frac{2}{5} x^{5/2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
In calculus, the power rule for integration is a fundamental technique used to integrate polynomial expressions. It simplifies the process of finding antiderivatives for functions of the form \( x^n \). The rule states that for any real number \( n \), the integral of \( x^n \) with respect to \( x \) is given by:
To apply this rule, a critical step is ensuring that the function is in the appropriate form. For example, when integrating an expression like \( x\sqrt{x} \), you must first simplify it to \( x^{3/2} \). Then, applying the power rule becomes a straightforward task:
- \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \)
To apply this rule, a critical step is ensuring that the function is in the appropriate form. For example, when integrating an expression like \( x\sqrt{x} \), you must first simplify it to \( x^{3/2} \). Then, applying the power rule becomes a straightforward task:
- Add 1 to the exponent: \( 3/2 + 1 = 5/2 \)
- Divide by the new exponent: \( \frac{x^{5/2}}{5/2} = \frac{2}{5}x^{5/2} \)
Family of Functions
The concept of a family of functions is intriguing because it highlights the idea that an indefinite integral does not yield a single function but a set of possible functions. This is due to the constant of integration, \( C \), included in the general solution of an indefinite integral.
When you integrate a function, you're essentially reversing differentiation. However, since the derivative of a constant is zero, there's no way to discern what constant was originally present; hence, we include \( C \).
Consider the integral \( \int x\sqrt{x} \, dx = \frac{2}{5}x^{5/2} + C \). By choosing different values for \( C \), we obtain different functions, such as:
When you integrate a function, you're essentially reversing differentiation. However, since the derivative of a constant is zero, there's no way to discern what constant was originally present; hence, we include \( C \).
Consider the integral \( \int x\sqrt{x} \, dx = \frac{2}{5}x^{5/2} + C \). By choosing different values for \( C \), we obtain different functions, such as:
- \( y = \frac{2}{5}x^{5/2} \)
- \( y = \frac{2}{5}x^{5/2} + 1 \)
- \( y = \frac{2}{5}x^{5/2} - 1 \)
Constant of Integration
When integrating, the constant of integration, \( C \), is essential. It accounts for the fact that there are infinitely many antiderivatives for a given function. This constant ensures that the results comprise a comprehensive family of solutions.
The inclusion of \( C \) is a reflection of the historical fact that differentiating any number of constant functions \( C \) returns zero. Thus, when reversing this process—integrating—you need to account for all possibilities:
The inclusion of \( C \) is a reflection of the historical fact that differentiating any number of constant functions \( C \) returns zero. Thus, when reversing this process—integrating—you need to account for all possibilities:
- Without \( C \), the function lacks the generality required to describe all potential antiderivatives.
- With \( C \), you're acknowledging the existence of infinite vertical translations of the curve represented by the integral.