Chapter 3: Problem 45
If an initial amount \(A_{0}\) of money is invested at an interest rate \(r\) compounded \(n\) times a year, the value of the investment after \(t\) years is $$A=A_{0}\left(1+\frac{r}{n}\right)^{n t}$$ If we let \(n \rightarrow \infty,\) we refer to the continuous compounding of interest. Use l'Hospital's Rule to show that if interest is compounded continuously, then the amount after \(t\) years is $$A=A_{0} e^{r t}$$
Short Answer
Step by step solution
Understanding the Limit
Setting Up the Expression to L'Hospital's Rule
Rewriting the Logarithm Expression
Applying L'Hospital's Rule
Exponentiating the Result
Final Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
l'Hospital's Rule
In the case of continuous compounding, the expression \( \lim_{n \to \infty} \frac{t \ln \left(1 + \frac{r}{n}\right)}{1/n} \) simplifies by applying L'Hospital's Rule. Both the numerator and denominator approach zero, thus creating an indeterminate form.
Upon applying l'Hospital's Rule, we differentiate the numerator \( t \ln \left(1 + \frac{r}{n}\right) \) with respect to \( n \), obtaining \( \frac{-t \cdot r}{n^2 (1 + \frac{r}{n})} \), and differentiate the denominator \( 1/n \) as \( -1/n^2 \). The limit then simplifies to \( t \cdot r \), leading us towards the formula for exponential growth under continuous compounding.
Limit of a Function
In the context of continuous compounding, we seek the limit of \( \left(1 + \frac{r}{n}\right)^{nt} \) as \( n \) approaches infinity. This forms the basis for deriving the exponential expression \( e^{rt} \) used in the formula for continuous compounding.
To solve such a limit, it’s common to manipulate the expression, such as using logarithms to transform it into a more manageable form, as was done with \( \ln \left(1 + \frac{r}{n}\right)^{nt} = n t \ln \left(1 + \frac{r}{n}\right) \). This simplifies the process of evaluation using calculus techniques like series expansion and L'Hospital's Rule.
Exponential Growth
Continuous compounding is a classic example of exponential growth. With continuous compounding, as the compounding frequency tends to infinity, the formula for future value simplifies from \( A = A_0 \left(1 + \frac{r}{n}\right)^{nt} \) to \( A = A_0 e^{rt} \).
This formula illustrates how money grows over time when interest is added continuously. The base of the natural logarithm, \( e \), represents the limiting value achieved as the number of compounding periods becomes infinitely large, capturing the essence of exponential growth.
Calculus Techniques
- Natural Logarithms: Taking natural logarithms helps transform and simplify expressions, making it easier to evaluate limits through calculus.
- Series Expansion: This technique approximates complex functions using polynomials. For our problem, using the series expansion of the logarithm \( \ln(1 + x) \approx x - \frac{x^2}{2} + \ldots \) aids in simplifying the expression.
- Indeterminate Forms: Recognizing and addressing indeterminate forms like \( \frac{0}{0} \) using tools such as l'Hospital's Rule is crucial in determining limits that are not immediately solvable.