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A model for the length of daylight (in hours) in Philadelphia on the \(t\) h day of the vear is given by the function $$L(t)=12+2.8 \sin \left[\frac{2 \pi}{365}(t-80)\right]$$ Use this model to compare how the number of hours of daylight is increasing in Philadelphia on March 21 and May \(21 .\)

Short Answer

Expert verified
Daylight increases by 2.74 hours from March 21 to May 21.

Step by step solution

01

Understand the Problem

We are given a function \(L(t)\) that models the length of daylight in hours for any day \(t\) of the year. We need to find out how the length of daylight increases from March 21 to May 21 in Philadelphia.
02

Calculate Day of Year for March 21

March 21 is the 80th day of the year. We need this to plug into the function to find the daylight length on March 21.
03

Calculate Day of Year for May 21

May 21 is the 141st day of the year. We convert the date into a numerical day of the year to use in the function. This helps us plug it into the function for precise calculation.
04

Compute Length of Daylight on March 21

Substitute \(t = 80\) into the function: \[ L(80) = 12 + 2.8 \sin \left(\frac{2\pi}{365}(80-80)\right) = 12 + 2.8 \times 0 = 12 \text{ hours} \] This reveals the length of daylight on March 21 is 12 hours.
05

Compute Length of Daylight on May 21

Substitute \(t = 141\) into the function: \[ L(141) = 12 + 2.8 \sin \left(\frac{2\pi}{365}(141-80)\right) \] \[ = 12 + 2.8 \sin \left(\frac{122\pi}{365}\right) \approx 12 + 2.8 \times 0.978 = 14.74 \] The length of daylight on May 21 is approximately 14.74 hours.
06

Determine the Increase in Daylight

Now, subtract the daylight on March 21 from that on May 21: \[ 14.74 - 12 = 2.74 \text{ hours} \] The number of hours of daylight increased by 2.74 hours between March 21 and May 21.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Daylight Modeling
Daylight modeling is a crucial part of understanding how the length of day varies throughout the year in different locations. In this exercise, we used a mathematical function to model daylight in Philadelphia. This approach allows us to predict and analyze daylight changes each day. The model given in the exercise, \[ L(t) = 12 + 2.8 \sin \left(\frac{2\pi}{365}(t-80)\right), \]is a harmonic function that simulates the natural fluctuations of daylight due to the Earth's tilt and orbit around the sun. By using this model, we can calculate daylight hours for any given day of the year. This kind of modeling helps in planning activities, agriculture schedules, and optimizing energy consumption, as natural light availability influences a lot of human activities and natural processes.
Sine Function
The sine function plays a significant role in the modeling of cyclic phenomena, such as daylight variations. The equation \[ L(t) = 12 + 2.8 \sin \left(\frac{2\pi}{365}(t-80)\right) \]is based on a concrete mathematical property: that the sine function oscillates between -1 and 1. This function is perfect for modeling situations that repeat in regular cycles, like the changing length of daylight through the year.
  • The amplitude of the sine wave (2.8 hours) represents the maximum increase or decrease in daylight above or below 12 hours.
  • The horizontal shift indicated by \((t - 80)\)' adjusts the peak daylight to fit the yearly daylight pattern, aligning with pivotal days such as equinoxes.
Understanding these components of the sine function helps interpret how the day length changes predictably across the year.
Calculus Applications
Calculus is used in various fields, and it's particularly useful in analyzing functions that model real-world phenomena, like the length of daylight function. In this context, calculus techniques can help us understand the rate of change of daylight length. The derivative of a function gives us information about the slope of the function at any point, indicating whether daylight is increasing or decreasing at a specific time. For instance, to find how rapidly the daylight length is changing on a particular day, one could differentiate \[ L(t) = 12 + 2.8 \sin \left(\frac{2\pi}{365}(t-80)\right) \]with respect to \(t\). The result will show the sensitivity of changes in daylight hours relative to changes in the day of the year. Calculus not only aids in understanding seasonal changes but is critical in fields like astronomy, physics, and even economics, where change over time is an essential consideration.

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