Chapter 2: Problem 19
\(3-26=\) Differentiate. $$y=\frac{x}{2-\tan x}$$
Short Answer
Expert verified
The derivative is \( y' = \frac{2 - \tan x + x \sec^2 x}{(2 - \tan x)^2} \).
Step by step solution
01
Identify the Rule to Use
To differentiate the function \( y = \frac{x}{2 - \tan x} \), recognize that it is a quotient of two functions. Thus, we will use the Quotient Rule for differentiation.
02
Apply the Quotient Rule
Recall the Quotient Rule: if \( y = \frac{u}{v} \), then \( y' = \frac{u'v - uv'}{v^2} \). Here, \( u = x \) and \( v = 2 - \tan x \).
03
Differentiate the Numerator \( u \)
The numerator function \( u = x \) is simple. Its derivative is \( u' = \frac{d}{dx} (x) = 1 \).
04
Differentiate the Denominator \( v \)
The denominator function \( v = 2 - \tan x \). Differentiate this using the fact that the derivative of \( \tan x \) is \( \sec^2 x \), so \( v' = 0 - \sec^2 x = -\sec^2 x \).
05
Substitute into the Quotient Rule Formula
Substitute \( u, u', v, \) and \( v' \) into the Quotient Rule: \( y' = \frac{(1)(2 - \tan x) - (x)(-\sec^2 x)}{(2 - \tan x)^2} \).
06
Simplify the Expression
Simplify the expression obtained: \( y' = \frac{2 - \tan x + x \sec^2 x}{(2 - \tan x)^2} \). Each term in the numerator is now clear, and no further simplification is necessary if the expression is left in a clean form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation steps
Differentiating functions is a key skill in calculus. When given a function to differentiate, we need to carefully follow certain steps. In the case of quotient functions, which are of the form \( y = \frac{u}{v} \), where both \( u \) and \( v \) are functions of \( x \), we use the Quotient Rule. This involves several clear steps:
- Identify the numerator function \( u \) and denominator function \( v \).
- Find the derivative of \( u \), noted as \( u' \).
- Find the derivative of \( v \), noted as \( v' \).
- Substitute everything into the Quotient Rule formula: \( y' = \frac{u'v - uv'}{v^2} \).
- Simplify the expression to get the differentiated form of the function.
Derivative of tangent
The tangent function, \( \tan x \), is a trigonometric function whose derivative is important in calculus problems involving trigonometry. The derivative of the tangent function is expressed in terms of another trigonometric function, secant:\[ \frac{d}{dx}(\tan x) = \sec^2 x \]Understanding this derivative is crucial when working on more complex functions, such as the denominator in our problem. Here, the presence of \( \tan x \) in \( v = 2 - \tan x \) means we must take account of this derivative. Recall that \( \sec x \) is the reciprocal of \( \cos x \), which helps in visualizing and calculating the derivative during problem-solving. Knowing this derivative, \( v' = 0 - \sec^2 x = -\sec^2 x \), ensures you accurately apply the Quotient Rule and get to the correct derivative of a function.
Calculus problem solving
Solving calculus problems often feels like unraveling a puzzle, and using the correct techniques is essential. Let's consider some general tips to improve your calculus problem-solving skills:
- Understand the Problem: Break it down into smaller parts and know which differentiation rules apply.
- Use the Right Rules: Ensure that you're familiar with differentiation rules like the Quotient Rule and derivatives of basic functions.
- Keep it Organized: Write each step clearly, so you can see how each part contributes to the solution.
- Check Your Work: After solving, review each step to make sure calculations were done correctly.
- Practice Regularly: The more you practice various types of problems, the more familiar you'll become with different techniques and solutions.