Chapter 2: Problem 18
\(3-26=\) Differentiate. $$y=\frac{\sqrt{x}-1}{\sqrt{x}+1}$$
Short Answer
Expert verified
The derivative is \( \frac{1}{x (\sqrt{x} + 1)^2} \).
Step by step solution
01
Identify the Function Composition for Differentiation
The function given is a quotient: \( y = \frac{\sqrt{x} - 1}{\sqrt{x} + 1} \). We need to differentiate this using the quotient rule.
02
Recall the Quotient Rule Formula
The quotient rule formula for differentiation is \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \), where \( u \) is the numerator \( \sqrt{x} - 1 \) and \( v \) is the denominator \( \sqrt{x} + 1 \).
03
Differentiate the Numerator (u)
\( u = \sqrt{x} - 1 \). Differentiating \( u \) with respect to \( x \), we get \( \frac{du}{dx} = \frac{1}{2\sqrt{x}} \).
04
Differentiate the Denominator (v)
\( v = \sqrt{x} + 1 \). Differentiating \( v \) with respect to \( x \), we get \( \frac{dv}{dx} = \frac{1}{2\sqrt{x}} \).
05
Apply the Quotient Rule
Substitute \( u \), \( v \), \( \frac{du}{dx} \), and \( \frac{dv}{dx} \) into the quotient rule formula. Therefore, we have:\[\frac{d}{dx}\left(\frac{\sqrt{x} - 1}{\sqrt{x} + 1}\right) = \frac{(\sqrt{x} + 1) \cdot \frac{1}{2\sqrt{x}} - (\sqrt{x} - 1) \cdot \frac{1}{2\sqrt{x}}}{(\sqrt{x} + 1)^2}\]
06
Simplify the Expression
Simplify the numerator:\[ (\sqrt{x} + 1) \cdot \frac{1}{2\sqrt{x}} - (\sqrt{x} - 1) \cdot \frac{1}{2\sqrt{x}} = \frac{\sqrt{x} + 1 - \sqrt{x} + 1}{2\sqrt{x}} = \frac{2}{2\sqrt{x}} = \frac{1}{\sqrt{x}}\]Thus, the derivative is:\[\frac{1}{\sqrt{x}(\sqrt{x} + 1)^2}\]
07
Final Simplification
The simplified final form of the derivative is:\[\frac{1}{x (\sqrt{x} + 1)^2}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
The quotient rule is a technique used in calculus to differentiate functions that are represented as a ratio of two functions. If you have a function \( y = \frac{u}{v} \), where both \( u \) and \( v \) are differentiable functions, the quotient rule can find the derivative of \( y \) with respect to \( x \). Here's how it works:
- You differentiate the numerator \( u \), giving \( \frac{du}{dx} \).
- You differentiate the denominator \( v \), giving \( \frac{dv}{dx} \).
- Plug these derivatives into the following formula:\[\frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}\]
Function Composition
Function composition involves combining two functions where the output of one becomes the input of another. When differentiating a function like \( y = \frac{\sqrt{x} - 1}{\sqrt{x} + 1} \), you are essentially dealing with composition because the functions \( \sqrt{x} - 1 \) and \( \sqrt{x} + 1 \) are inside the fraction format. Understanding the foundation of each component is essential.
- The numerator, \( \sqrt{x} - 1 \), represents a basic composition of a root function and a linear term.
- The denominator, \( \sqrt{x} + 1 \), similarly contains a root and a linear term.
- Both parts contain \( \sqrt{x} \), which is a function of \( x \), contained within another operation (addition/subtraction here).
Simplification in Calculus
Simplification is the process of making an expression more straightforward or easier to manipulate. It's especially useful in calculus to avoid errors and clarify results - as seen in the derivative of \( y = \frac{\sqrt{x} - 1}{\sqrt{x} + 1} \). After applying the quotient rule, the expression may look complicated, but simplification helps reach a clear final form.
- Focus first on simplifying the parts inside the differentiation formula before worrying about combining them.
- In this example, simplifying the expression after applying the quotient rule involved eliminating terms and fractions.
- The goal was to transform the complex numerator/denominator relation into a much simpler form: \( \frac{1}{x (\sqrt{x} + 1)^2} \).