Chapter 13: Problem 7
Find \((\) a) the curl and (b) the divergence of the vector field. $$\mathbf{F}(x, y, z)=\left\langle e^{x} \sin y, e^{y} \sin z, e^{z} \sin x\right\rangle$$
Short Answer
Expert verified
Curl: \(\langle -e^y \cos z, -e^z \cos x, -e^x \cos y \rangle\); Divergence: \(e^x \sin y + e^y \sin z + e^z \sin x\).
Step by step solution
01
Define the Curl Formula
The curl of a vector field \( \mathbf{F}(x, y, z) = \langle P, Q, R \rangle \) is given by the formula: \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \). Here, \( P = e^x \sin y \), \( Q = e^y \sin z \), \( R = e^z \sin x \).
02
Compute Partial Derivatives for the Curl
Calculate the required partial derivatives:- \( \frac{\partial R}{\partial y} = 0 \),- \( \frac{\partial Q}{\partial z} = e^y \cos z \),- \( \frac{\partial P}{\partial z} = 0 \),- \( \frac{\partial R}{\partial x} = e^z \cos x \),- \( \frac{\partial Q}{\partial x} = 0 \),- \( \frac{\partial P}{\partial y} = e^x \cos y \).
03
Calculate the Components of the Curl
Using the partial derivatives, calculate each component of the curl:- First component: \( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} = 0 - e^y \cos z = -e^y \cos z \),- Second component: \( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} = 0 - e^z \cos x = -e^z \cos x \),- Third component: \( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} = 0 - e^x \cos y = -e^x \cos y \).
04
Express the Curl
The curl is given by \( abla \times \mathbf{F} = \langle -e^y \cos z, -e^z \cos x, -e^x \cos y \rangle \).
05
Define the Divergence Formula
The divergence of a vector field \( \mathbf{F}(x, y, z) = \langle P, Q, R \rangle \) is given by the formula: \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \).
06
Compute Partial Derivatives for the Divergence
Compute each partial derivative:- \( \frac{\partial P}{\partial x} = e^x \sin y \),- \( \frac{\partial Q}{\partial y} = e^y \sin z \),- \( \frac{\partial R}{\partial z} = e^z \sin x \).
07
Calculate the Divergence
The divergence is calculated as follows:\( abla \cdot \mathbf{F} = e^x \sin y + e^y \sin z + e^z \sin x \).
08
Express the Divergence
Therefore, the divergence of the vector field is \( abla \cdot \mathbf{F} = e^x \sin y + e^y \sin z + e^z \sin x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
In vector calculus, understanding the curl of a vector field is essential. It measures the rotation or twist of a vector field at a certain point. To compute the curl, you use the formula: \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \). This formula involves finding derivatives of each component of the vector field.For our exercise, the vector field given is \( \mathbf{F}(x, y, z)=\left\langle e^{x} \sin y, e^{y} \sin z, e^{z} \sin x\right\rangle \).
- First, identify \( P, Q, R \) as \( e^x \sin y, e^y \sin z, e^z \sin x \) respectively.
- Compute each partial derivative as seen in the step-by-step solution, like \( \frac{\partial R}{\partial y} = 0 \).
- Calculate the resulting vector components of the curl: \( \langle -e^y \cos z, -e^z \cos x, -e^x \cos y \rangle \).
Divergence of a Vector Field
The divergence of a vector field is another crucial concept. It measures the rate at which "stuff" is expanding or converging at a point. To find divergence, apply the formula: \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \).The divergence of our specified vector field is calculated by determining the partial derivatives:
- The partial derivative of \( P \) with respect to \( x \) is \( e^x \sin y \).
- The partial derivative of \( Q \) with respect to \( y \) is \( e^y \sin z \).
- The partial derivative of \( R \) with respect to \( z \) is \( e^z \sin x \).
Partial Derivatives
Partial derivatives are central in the calculation of both curl and divergence. They represent the derivative of a function concerning one variable while keeping others constant. This concept is pivotal in handling multi-variable functions like those encountered in vector calculus.In our example, to find the curl and divergence, we dealt with partial derivatives such as:
- \( \frac{\partial R}{\partial y} \), which was \(0\) because the function \(R\) \( (e^z \sin x) \) does not depend on \(y\).
- \( \frac{\partial P}{\partial x} \), computed as \(e^x \sin y\), illustrating how to differentiate with respect to a specific variable.