Chapter 13: Problem 3
Find \((\) a) the curl and (b) the divergence of the vector field. $$\mathbf{F}(x, y, z)=x y e^{z} \mathbf{i}+y z e^{x} \mathbf{k}$$
Short Answer
Expert verified
Curl: \( z e^{x} \mathbf{i} + (xy e^{z} - yz e^{x}) \mathbf{j} - x e^{z} \mathbf{k} \); Divergence: \( y(e^{z} + e^{x}) \)."
Step by step solution
01
Understanding the Curl
The curl of a vector field \( \mathbf{F}(x, y, z) = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) is defined as: \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right)\mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right)\mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\mathbf{k} \). Identify \( P = xy e^{z} \), \( Q = 0 \), and \( R = yz e^{x} \).
02
Calculate the Components of the Curl
Compute each term in the curl formula:1. For \( \mathbf{i} \): \( \frac{\partial R}{\partial y} = z e^{x} \) and \( \frac{\partial Q}{\partial z} = 0 \). Thus, the \( \mathbf{i} \) component is \( z e^{x} \).2. For \( \mathbf{j} \): \( \frac{\partial P}{\partial z} = xy e^{z} \) and \( \frac{\partial R}{\partial x} = yz e^{x} \). Thus, the \( \mathbf{j} \) component is \( xy e^{z} - yz e^{x} \).3. For \( \mathbf{k} \): \( \frac{\partial Q}{\partial x} = 0 \) and \( \frac{\partial P}{\partial y} = x e^{z} \). Thus, the \( \mathbf{k} \) component is \( -x e^{z} \).
03
Write the Curl of the Vector Field
The curl is therefore: \( abla \times \mathbf{F} = z e^{x} \mathbf{i} + (xy e^{z} - yz e^{x}) \mathbf{j} - x e^{z} \mathbf{k} \).
04
Understanding the Divergence
The divergence of a vector field \( \mathbf{F}(x, y, z) = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) is defined as: \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \). Identify \( P = xy e^{z} \), \( Q = 0 \), and \( R = yz e^{x} \).
05
Calculate the Divergence
Compute each partial derivative:1. \( \frac{\partial P}{\partial x} = y e^{z} \)2. \( \frac{\partial Q}{\partial y} = 0 \)3. \( \frac{\partial R}{\partial z} = y e^{x} \)Add them together to get: \( abla \cdot \mathbf{F} = y e^{z} + y e^{x} \).
06
Write the Divergence of the Vector Field
The divergence is therefore: \( abla \cdot \mathbf{F} = y(e^{z} + e^{x}) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
In vector calculus, the curl of a vector field provides information about the rotational properties of the field. Imagine a tiny paddlewheel placed in the vector field; the curl tells you how likely it is to spin. For a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), the curl is calculated as:\[abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right)\mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right)\mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\mathbf{k}\]In this exercise, we consider \( \mathbf{F}(x, y, z) = xy e^{z} \mathbf{i} + 0\mathbf{j} + yz e^{x} \mathbf{k} \)
- The \( \mathbf{i} \) component, \( \frac{\partial R}{\partial y} \), gives \( z e^{x} \) because \( R = yz e^{x} \) when differentiated with respect to \( y \).
- The \( \mathbf{j} \) component emerges from \( \frac{\partial P}{\partial z} \) which gives \( xy e^{z} \) minus \( \frac{\partial R}{\partial x} \) which is \( yz e^{x} \).
- The \( \mathbf{k} \) component simply becomes \( -x e^{z} \) as \( \frac{\partial P}{\partial y} = x e^{z} \) and the other term is zero.
Divergence of a Vector Field
The divergence of a vector field is a measure of how much the field spreads out from a point, like how water might diverge from a source. For a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), the divergence is found by summing these partial derivatives:\[abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\]In our exercise with \( \mathbf{F}(x, y, z) = xy e^{z} \mathbf{i} + 0\mathbf{j} + yz e^{x} \mathbf{k} \), we observe:
- \( \frac{\partial P}{\partial x} = y e^{z} \), due to the linear term in \( x \) in \( P = xy e^{z} \).
- \( \frac{\partial Q}{\partial y} = 0 \) since \( Q = 0 \) in the field.
- \( \frac{\partial R}{\partial z} = y e^{x} \) results from \( R = yz e^{x} \).
Partial Derivatives
Partial derivatives are fundamental in vector calculus, especially when dealing with functions of multiple variables. They represent the rate of change of a function in one variable while keeping other variables constant. For a multivariable function \( f(x, y, z) \), the partial derivative with respect to \( x \), denoted \( \frac{\partial f}{\partial x} \), measures how \( f \) changes as \( x \) changes, while \( y \) and \( z \) remain unchanged.
In the context of vector fields, partial derivatives are used to compute both curl and divergence. Each component of the vector field is treated as a function of spatial variables, and partial derivatives help establish how these components interact over small changes in space:
In the context of vector fields, partial derivatives are used to compute both curl and divergence. Each component of the vector field is treated as a function of spatial variables, and partial derivatives help establish how these components interact over small changes in space:
- For the curl, we differentiate with respect to different pairs of variables to measure the rotation effects.
- For the divergence, partial derivatives allow us to assess how the vector field behaves as it diverges from or converges towards a point.