Chapter 13: Problem 3
Determine whether or not \(\mathbf{F}\) is a conservative vector field. If it is, find a function \(f\) such that \(\mathbf{F}=\nabla f\). \(\mathbf{F}(x, y)=(2 x-3 y) \mathbf{i}+(-3 x+4 y-8) \mathbf{j}\)
Short Answer
Expert verified
\(\mathbf{F}\) is conservative; \(f(x, y) = x^2 - 3xy + 2y^2 - 8y + C\).
Step by step solution
01
Check Conditions for a Conservative Vector Field
A vector field \( \mathbf{F}(x, y) = P(x, y)\mathbf{i} + Q(x, y)\mathbf{j} \) is conservative if its curl is zero (in two dimensions) or equivalently, if \( \frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x} \). Here, \( P(x, y) = 2x - 3y \) and \( Q(x, y) = -3x + 4y - 8 \). Calculate the partial derivatives:- \( \frac{\partial P}{\partial y} = \frac{\partial}{\partial y}(2x - 3y) = -3 \).- \( \frac{\partial Q}{\partial x} = \frac{\partial}{\partial x}(-3x + 4y - 8) = -3 \).Since \( \frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x} = -3 \), \( \mathbf{F} \) is conservative.
02
Find the Potential Function f
Since \( \mathbf{F} \) is conservative, there exists a potential function \( f \) such that \( \mathbf{F} = abla f \), meaning \( \frac{\partial f}{\partial x} = P(x, y) = 2x - 3y \) and \( \frac{\partial f}{\partial y} = Q(x, y) = -3x + 4y - 8 \).
03
Integrate to Find f(x, y)
First, find \( f \) by integrating \( P \) with respect to \( x \):\[ f(x, y) = \int (2x - 3y) \, dx = x^2 - 3xy + g(y) \]where \( g(y) \) is an arbitrary function of \( y \).
04
Determine g(y) by Matching Terms
To find \( g(y) \), take the derivative \( \frac{\partial f}{\partial y} \) and set it equal to \( Q(x, y) = -3x + 4y - 8 \):\[ \frac{\partial}{\partial y}(x^2 - 3xy + g(y)) = -3x + g'(y) = -3x + 4y - 8 \].Equating terms, \( g'(y) = 4y - 8 \). Integrate this to find \( g(y) \):\[ g(y) = \int (4y - 8) \, dy = 2y^2 - 8y + C \]where \( C \) is a constant.
05
Construct the Full Potential Function
Substitute \( g(y) \) back into \( f(x, y) \):\[ f(x, y) = x^2 - 3xy + 2y^2 - 8y + C \].This is the potential function \( f \) such that \( \mathbf{F} = abla f \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potential Function
A potential function is a critical concept when dealing with conservative vector fields. It is a scalar function, usually denoted by \( f(x, y) \), which helps us understand the properties of the vector field. If a vector field \( \mathbf{F}(x, y) = P(x, y)\mathbf{i} + Q(x, y)\mathbf{j} \) is conservative, there exists a potential function \( f \) such that \( \mathbf{F} = abla f \) (the gradient of \( f \)). This means:
- \( \frac{\partial f}{\partial x} = P(x, y) \)
- \( \frac{\partial f}{\partial y} = Q(x, y) \)
Curl of a Vector Field
The curl of a vector field, particularly in two dimensions, is a simple yet crucial tool in verifying whether a vector field is conservative. For a vector field \( \mathbf{F} = P(x, y)\mathbf{i} + Q(x, y)\mathbf{j} \), in two dimensions, the curl \( \text{curl } \mathbf{F} \) reduces to a straightforward condition:
- \( \frac{\partial P}{\partial y} \)
- \( \frac{\partial Q}{\partial x} \)
Partial Derivatives
Partial derivatives are a foundational tool in multivariable calculus, allowing us to understand how a function changes with respect to one of its variables while holding the others constant. When dealing with vector fields, partial derivatives are used to:
- Find the conditions for a field being conservative.
- Calculate the components of the curl.
- Derive the potential function from the components \( P(x, y) \) and \( Q(x, y) \).