Chapter 13: Problem 17
Is there a vector field G on \(\mathbb{R}^{3}\) such that curl \(\mathbf{G}=\langle x \sin y, \cos y, z-x y\rangle\) ? Explain.
Short Answer
Expert verified
No, such a vector field \( \mathbf{G} \) does not exist, as the given field is not divergence-free.
Step by step solution
01
Define the Curl
The curl of a vector field \( \mathbf{G} = \langle P, Q, R \rangle \) is given by \( abla \times \mathbf{G} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \).
02
Apply Divergence to the Given Curl Vector Field
To determine if a vector field \( \mathbf{G} \) exists, apply the condition that the curl is divergence-free. Compute the divergence of the vector field \( \langle x \sin y, \cos y, z - x y \rangle \) as \( \frac{\partial}{\partial x}(x \sin y) + \frac{\partial}{\partial y}(\cos y) + \frac{\partial}{\partial z}(z - xy) \).
03
Compute the Partial Derivatives
Calculate the partial derivatives: \( \frac{\partial}{\partial x}(x \sin y) = \sin y \), \( \frac{\partial}{\partial y}(\cos y) = -\sin y \), and \( \frac{\partial}{\partial z}(z - x y) = 1 \).
04
Calculate the Divergence
Add the partial derivatives obtained: \( \sin y - \sin y + 1 = 1 \).
05
Check Divergence-Free Condition
The divergence of the vector field is 1, indicating the field is not divergence-free. As a result, there is no vector field \( \mathbf{G} \) on \( \mathbb{R}^{3} \) with the given curl.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
When working with vector fields, the curl is a useful operation that measures the rotation of a vector at any given point. If you imagine a tiny wheel spinning at a point in the vector field, the curl tells us how much and in what direction that wheel would rotate. For a vector field \( \mathbf{G} = \langle P, Q, R \rangle \), the curl is calculated using the mathematical expression:
- \( abla \times \mathbf{G} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \)
Divergence
Divergence is a measure of how much a vector field spreads out or converges at a given point. It's a scalar quantity that provides insight into whether the vector field is acting as a source or a sink at a particular location. For a vector field \( \mathbf{F} = \langle F_1, F_2, F_3 \rangle \), the divergence is calculated as follows:
In the exercise, we computed the divergence of the curl vector field as \( 1 \), showing an outflow at every point, implying non-zero divergence.
- \( abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \)
In the exercise, we computed the divergence of the curl vector field as \( 1 \), showing an outflow at every point, implying non-zero divergence.
Divergence-Free Condition
The divergence-free condition implies that a vector field has no net flux out of any volume in space, meaning no sources or sinks exist within it. Mathematically, a vector field \( \mathbf{H} \) is divergence-free if:
In our original problem, we explored whether a vector field \( \mathbf{G} \) could exist such that its curl matched a given vector. By calculating the divergence of the given curl, we found that it equaled \( 1 \), meaning it was not divergence-free. Therefore, no such vector field \( \mathbf{G} \) can exist because the divergence-free condition is not satisfied.
To determine potential vector fields from a curl, a zero divergence is essential.
- \( abla \cdot \mathbf{H} = 0 \)
In our original problem, we explored whether a vector field \( \mathbf{G} \) could exist such that its curl matched a given vector. By calculating the divergence of the given curl, we found that it equaled \( 1 \), meaning it was not divergence-free. Therefore, no such vector field \( \mathbf{G} \) can exist because the divergence-free condition is not satisfied.
To determine potential vector fields from a curl, a zero divergence is essential.