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Use the Chain Rule to find \(\partial z / \partial s\) and \(\partial z / \partial t\) $$z=e^{r} \cos \theta, \quad r=s t, \quad \theta=\sqrt{s^{2}+t^{2}}$$

Short Answer

Expert verified
Apply the chain rule and differentiate with respect to each variable, then simplify the expressions.

Step by step solution

01

Identify the Composition Functions

We need to identify the functions that compose the equation for \(z\). The outer function is \(z(r, \theta) = e^r \cos \theta\). The inner functions are \(r(s,t) = s t\) and \(\theta(s,t) = \sqrt{s^2 + t^2}\).
02

Apply the Chain Rule Formulas

Using the chain rule, we have\[\frac{\partial z}{\partial s} = \frac{\partial z}{\partial r}\frac{\partial r}{\partial s} + \frac{\partial z}{\partial \theta}\frac{\partial \theta}{\partial s}\]and\[\frac{\partial z}{\partial t} = \frac{\partial z}{\partial r}\frac{\partial r}{\partial t} + \frac{\partial z}{\partial \theta}\frac{\partial \theta}{\partial t}\].
03

Differentiate with Respect to Intermediate Variables

Find the partial derivatives with respect to the intermediate variables:\- \(\frac{\partial z}{\partial r} = e^r \cos \theta\)- \(\frac{\partial z}{\partial \theta} = -e^r \sin \theta\)- \(\frac{\partial r}{\partial s} = t\)- \(\frac{\partial r}{\partial t} = s\)- \(\frac{\partial \theta}{\partial s} = \frac{s}{\sqrt{s^2 + t^2}}\)- \(\frac{\partial \theta}{\partial t} = \frac{t}{\sqrt{s^2 + t^2}}\).
04

Substitute into Chain Rule Equations

Substitute these derivatives into the chain rule equations:\[\frac{\partial z}{\partial s} = e^r \cos \theta \cdot t - e^r \sin \theta \cdot \frac{s}{\sqrt{s^2 + t^2}}\]\[\frac{\partial z}{\partial t} = e^r \cos \theta \cdot s - e^r \sin \theta \cdot \frac{t}{\sqrt{s^2 + t^2}}\].
05

Simplify Final Expressions

Finally, simplify the expressions for the partial derivatives:- \(\frac{\partial z}{\partial s} = t e^{st} \cos(\sqrt{s^2+t^2}) - \frac{se^{st}\sin(\sqrt{s^2+t^2})}{\sqrt{s^2+t^2}}\)- \(\frac{\partial z}{\partial t} = s e^{st} \cos(\sqrt{s^2+t^2}) - \frac{t e^{st}\sin(\sqrt{s^2+t^2})}{\sqrt{s^2+t^2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a key concept in calculus, especially when dealing with functions of multiple variables. They measure how a function changes as one variable is varied while keeping others constant. For instance, in the context of our exercise, the function \(z\) depends on two intermediate variables, \(r\) and \(\theta\), which themselves depend on \(s\) and \(t\). When finding \(\frac{\partial z}{\partial s}\), we are interested in how \(z\) changes as \(s\) changes, with \(t\) held constant, and similarly for \(\frac{\partial z}{\partial t}\).
  • Partial derivatives are written as \(\frac{\partial}{\partial x}\) notation, distinguishing them from ordinary derivatives.
  • They allow us to explore the sensitivity of the function to changes in each direction independently.
  • This technique is vital in optimization problems where extremal points need to be identified.
In this exercise, we used partial derivatives to understand how changes in \(s\) and \(t\) influence the result of the function \(z\). This sets the stage for solving more complex problems where variables interplay dynamically.
Composition Functions
Composition functions involve combining two or more functions where the output of one function becomes the input for another. In our exercise, the function for \(z\) is a composition of \(r\) and \(\theta\) functions. These, in turn, depend on the variables \(s\) and \(t\).
  • The outer function is \(z(r, \theta) = e^r \cos \theta\).
  • The inner functions are \(r(s,t) = st\) and \(\theta(s,t) = \sqrt{s^2 + t^2}\).
The chain rule is an essential tool when dealing with composition functions. It allows us to differentiate a composed function by considering its structure. Understanding the different layers of composition helps break down complex functions into more manageable pieces. By systematically identifying the outer and inner functions in our calculations, we can accurately apply differentiation techniques, evaluating how a small change in \(s\) or \(t\) affects the overall structure and output of \(z\). This skill is invaluable in advanced calculus and mathematical modeling.
Calc 3 Problems
Calc 3, or Calculus III, extends concepts from single-variable calculus into multivariable settings. This includes exploring partial derivatives, composition functions, and other advanced techniques. Employing the chain rule for partial derivatives is pivotal in Calc 3 problems like the one we have here, as it allows us to navigate the complexities of multivariable derivatives in an organized manner.
  • In Calc 3, we often deal with gradient vectors, divergence, curl, and more - each relying on partial derivatives.
  • Troubleshooting such problems requires clear identification of dependencies and function compositions, like in our exercise.
  • It's about extending intuitive understanding from 2D to 3D and beyond, enhancing spatial thinking abilities.
The practice of solving Calc 3 problems sharpens analytical skills and prepares students for real-world applications across physics, engineering, economics, and more.

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Most popular questions from this chapter

If a function of one variable is continuous on an interval and has only one critical number, then a local maximum has to be an absolute maximum. But this is not true for functions of two variables. Show that the function $$f(x, y)=3 x e^{y}-x^{3}-e^{3 y}$$ has exactly one critical point, and that \(f\) has a local maximum there that is not an absolute maximum. Then use a computer to produce a graph with a carefully chosen domain and viewpoint to see how this is possible.

Assume that all the given functions have continuous second-order partial derivatives. Suppose \(z=f(x, y),\) where \(x=g(s, t)\) and \(y=h(s, t)\) (a) Show that $$\frac{\partial^{2} z}{\partial t^{2}}=\frac{\partial^{2} z}{\partial x^{2}}\left(\frac{\partial x}{\partial t}\right)^{2}+2 \frac{\partial^{2} z}{\partial x \partial y} \frac{\partial x}{\partial t} \frac{\partial y}{\partial t}+\frac{\partial^{2} z}{\partial y^{2}}\left(\frac{\partial y}{\partial t}\right)^{2}$$ $$+\frac{\partial z}{\partial x} \frac{\partial^{2} x}{\partial t^{2}}+\frac{\partial z}{\partial y} \frac{\partial^{2} y}{\partial t^{2}}$$ (b) Find a similar formula for \(\partial^{2} z / \partial s \partial t\)

Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. $$ f(x, y, z)=x y z ; \quad x^{2}+2 y^{2}+3 z^{2}=6 $$

Find three positive numbers whose sum is 12 and the sum of whose squares is as small as possible.

Find the maximum volume of a rectangular box that is inscribed in a sphere of radius \(r .\)

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