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Graph the surface and the tangent plane at the given point. (Choose the domain and viewpoint so that you get a good view of both the surface and the tangent plane.) Then zoom in until the surface and the tangent plane become indistinguishable. $$ z=x^{2}+x y+3 y^{2}, \quad(1,1,5) $$

Short Answer

Expert verified
The tangent plane at \((1,1,5)\) is \(z = 3x + 7y - 5\).

Step by step solution

01

Define the Surface Function

The given surface is defined by the function \( z = f(x, y) = x^2 + xy + 3y^2 \). This function describes the height \( z \) for any point \( (x, y) \) on the xy-plane.
02

Calculate Partial Derivatives

To find the tangent plane, we first need the partial derivatives \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \).1. \( \frac{\partial z}{\partial x} = 2x + y \)2. \( \frac{\partial z}{\partial y} = x + 6y \)
03

Evaluate Partial Derivatives at the Given Point

Evaluate these partial derivatives at the point \((1, 1)\):1. \( \frac{\partial z}{\partial x}(1, 1) = 2 \cdot 1 + 1 = 3 \)2. \( \frac{\partial z}{\partial y}(1, 1) = 1 + 6 \cdot 1 = 7 \)
04

Write the Equation of the Tangent Plane

Using the point \((1, 1, 5)\) and the evaluated partial derivatives, the equation of the tangent plane is:\[ z = 5 + 3(x - 1) + 7(y - 1) \]Simplify this equation to:\[ z = 3x + 7y - 5 \]
05

Choose a Domain and Viewpoint for Graphing

Select a domain for \(x\) and \(y\) around the point \((1, 1)\), such as \([-2, 4]\) for both \(x\) and \(y\). Choose a viewpoint where you can clearly see both the surface and the tangent plane, typically a 3D perspective.
06

Graph the Surface and Tangent Plane

Use a graphing tool to plot both \(z = x^2 + xy + 3y^2\) and the tangent plane \(z = 3x + 7y - 5\) over the domain \([-2, 4]\). Ensure that the graphs accurately represent the surface and plane.
07

Zoom In Until Indistinguishable

Zoom in on the graph around the point \((1, 1, 5)\) until the surface and the tangent plane appear as one. This might require setting the domain to a smaller range, like \([0.8, 1.2]\) for \(x\) and \(y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Plane
In calculus, the concept of the tangent plane is an extension of the idea of a tangent line in two dimensions to three dimensions. Imagine you have a surface, like a hill, in 3D space. At any given point on this hill, the tangent plane is the flat surface that just "kisses" the hill at that spot. It's the best linear approximation of the surface at that small section; similar to how if you zoom in enough on a curve, a line can approximate it.
This plane is a critical tool because understanding the local behavior of a surface can help identify slopes, gradients, and can aid in optimization problems.To determine the tangent plane's equation at a point on a surface given by a function like \[ z = f(x, y) = x^2 + xy + 3y^2 \]we use the partial derivatives of the function at that point to define the plane's slope in both the x and y direction. For example, \[ z = 5 + 3(x - 1) + 7(y - 1) \]represents the tangent plane to our surface at the point (1, 1, 5). This equation is built using the constants we obtain from the partial derivatives.
Partial Derivatives
Partial derivatives are a fundamental concept in multivariable calculus. When a function depends on two or more variables, a partial derivative measures how the function changes as one of the variables changes, with all others held constant.
To find a tangent plane, we compute these derivatives for a function of two variables, like \[ z = x^2 + xy + 3y^2 \]. Understanding each derivative gives us insight into how steep the function is along two perpendicular directions.
  • The partial derivative with respect to x, denoted as \( \frac{\partial z}{\partial x} \), measures how z changes when x changes, holding y constant. In our exercise, we compute \( \frac{\partial z}{\partial x} = 2x + y \).
  • Similarly, the partial derivative with respect to y, \( \frac{\partial z}{\partial y} \), shows how z changes when y changes, with x constant. For this function, we found \( \frac{\partial z}{\partial y} = x + 6y \).
Evaluating these derivatives at a specific point provides the necessary slopes to define the tangent plane. In our context, at the point (1, 1), these derivatives result in the values 3 and 7, respectively, guiding the plane’s orientation.
3D Graphing
3D Graphing is a technique to visualize functions of two variables, creating a three-dimensional plot over an xy-plane. It allows us to see how changes in x and y affect the value of a function z.To effectively graph both a complex surface and its tangent plane, choose an appropriate domain and viewpoint through which both can be clearly observed.
For instance, taking the domain \([-2, 4] \) for both x and y, allows you to see sufficient spread around a point of interest, such as (1, 1), to capture the behavior of the surface and plane.Graphing the original function \[ z = x^2 + xy + 3y^2 \]and the tangent plane \[ z = 3x + 7y - 5 \]side by side helps in understanding their relationship. As you zoom into the graph near point (1, 1, 5), both the surface and plane start to look very similar, demonstrating the plane's role as a local approximation of the surface.Using 3D plots can bridge the gap between theoretical calculations and spatial understanding, making abstract calculus concepts more tangible.

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Most popular questions from this chapter

(a) Find the maximum value of $$ f\left(x_{1}, x_{2}, \ldots, x_{n}\right)=\sqrt[n]{x_{1} x_{2} \cdots x_{n}} $$ given that \(x_{1}, x_{2}, \ldots, x_{n}\) are positive numbers and \(x_{1}+x_{2}+\cdots+x_{n}=c,\) where \(c\) is a constant. (b) Deduce from part (a) that if \(x_{1}, x_{2}, \ldots, x_{n}\) are positive numbers, then $$ \sqrt[n]{x_{1} x_{2} \cdots x_{n}} \leqslant \frac{x_{1}+x_{2}+\cdots+x_{n}}{n} $$ This inequality says that the geometric mean of \(n\) numbers is no larger than the arithmetic mean of the numbers. Under what circumstances are these two means equal?

Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. $$f(x, y)=y^{3}+3 x^{2} y-6 x^{2}-6 y^{2}+2$$

Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. $$f(x, y)=x y(1-x-y)$$

Find three positive numbers whose sum is 100 and whose product is a maximum.

The temperature at a point \((x, y)\) is \(T(x, y),\) measured in degrees Celsius. A bug crawls so that its position after \(t\) seconds is given by \(x=\sqrt{1+t}, y=2+\frac{1}{3} t,\) where \(x\) and \(y\) are measured in centimeters. The temperature function satisfies \(T_{x}(2,3)=4\) and \(T_{y}(2,3)=3 .\) How fast is the temperature rising on the bug's path after 3 seconds?

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