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\(45-50\) Find all the second partial derivatives. $$f(x, y)=x^{3} y^{5}+2 x^{4} y$$

Short Answer

Expert verified
The second partial derivatives are: \(6xy^5 + 24x^2y\), \(20x^3y^3\), \(15x^2y^4 + 8x^3\).

Step by step solution

01

Understanding the Problem

We are given the function \( f(x, y) = x^3 y^5 + 2x^4 y \). The task is to find all the second partial derivatives of this function. This means calculating \( \frac{\partial^2 f}{\partial x^2} \), \( \frac{\partial^2 f}{\partial y^2} \), \( \frac{\partial^2 f}{\partial x \partial y} \), and \( \frac{\partial^2 f}{\partial y \partial x} \).
02

Find the First Partial Derivatives

To find the second partial derivatives, we first find the first derivatives with respect to \( x \) and \( y \).- \( \frac{\partial f}{\partial x} = 3x^2y^5 + 8x^3y \)- \( \frac{\partial f}{\partial y} = 5x^3y^4 + 2x^4 \)
03

Compute Second Partial Derivative with Respect to x

Now, compute the second derivative with respect to \( x \), or \( \frac{\partial^2 f}{\partial x^2} \). For this, we differentiate \( \frac{\partial f}{\partial x} \) with respect to \( x \) again:- \( \frac{\partial^2 f}{\partial x^2} = \frac{\partial}{\partial x}(3x^2y^5 + 8x^3y) = 6xy^5 + 24x^2y \)
04

Compute Second Partial Derivative with Respect to y

Next, compute the second derivative with respect to \( y \), or \( \frac{\partial^2 f}{\partial y^2} \). Differentiate \( \frac{\partial f}{\partial y} \) with respect to \( y \):- \( \frac{\partial^2 f}{\partial y^2} = \frac{\partial}{\partial y}(5x^3y^4 + 2x^4) = 20x^3y^3 \)
05

Mixed Partial Derivatives

For mixed partial derivatives, compute both \( \frac{\partial^2 f}{\partial x \partial y} \) and \( \frac{\partial^2 f}{\partial y \partial x} \):- \( \frac{\partial^2 f}{\partial x \partial y} = \frac{\partial}{\partial y}(3x^2y^5 + 8x^3y) = 15x^2y^4 + 8x^3 \)- \( \frac{\partial^2 f}{\partial y \partial x} = \frac{\partial}{\partial x}(5x^3y^4 + 2x^4) = 15x^2y^4 + 8x^3 \)Notice that \( \frac{\partial^2 f}{\partial x \partial y} = \frac{\partial^2 f}{\partial y \partial x} \), which is expected due to Clairaut's theorem, assuming the necessary conditions are met.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a fundamental concept in calculus, especially useful when dealing with functions of multiple variables. They represent the rate at which the function changes as one variable changes, while all other variables are held constant. In simpler terms, if you have a function like \[ f(x, y) = x^3 y^5 + 2x^4 y \]you can explore how it behaves if you alter just one of the variables at a time.
Partial derivatives focus on these individual changes:
  • \( \frac{\partial f}{\partial x} \) for changes in the \( x \) direction, while \( y \) is held constant.
  • \( \frac{\partial f}{\partial y} \) for changes in the \( y \) direction, while \( x \) is held constant.
Evaluating partial derivatives involves treating all other variables as constants and applying the usual rules of differentiation. This can be particularly handy in optimization problems or in understanding the behavior of multi-variable functions.
Mixed Partial Derivatives
Mixed partial derivatives involve taking partial derivatives with respect to different variables. For instance, while dealing with a function \( f(x, y) \), one might be interested in how the function changes first with respect to \( x \) and then \( y \), or vice versa.
For the given function, the mixed partial derivatives are:
  • \( \frac{\partial^2 f}{\partial x \partial y} \), which means first taking the derivative with respect to \( x \) and then \( y \).
  • \( \frac{\partial^2 f}{\partial y \partial x} \), which means first with respect to \( y \) and then \( x \).
These derivatives are particularly useful in physics and engineering, where processes often depend on changes across multiple variables or axes.
Clairaut's Theorem
Clairaut's theorem is a helpful result when working with second partial derivatives. It states that, under certain conditions, mixed partial derivatives are equal.
For a function \( f(x, y) \), this means:
  • \( \frac{\partial^2 f}{\partial x \partial y} = \frac{\partial^2 f}{\partial y \partial x} \)
This interchangeability requires that the function meets certain conditions, specifically that both mixed partial derivatives are continuous at the point of interest. This theorem simplifies calculations significantly, ensuring that the order in which you take derivatives does not affect the result.

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Most popular questions from this chapter

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