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\(31-34\) Find the indicated partial derivative. $$f(x, y, z)=\frac{y}{x+y+z} ; f_{y}(2,1,-1)$$

Short Answer

Expert verified
The partial derivative is \(\frac{1}{4}\) at the point \((2, 1, -1)\).

Step by step solution

01

Understanding the Function

The function given is \(f(x, y, z) = \frac{y}{x+y+z}\). We need to find the partial derivative of \(f\) with respect to \(y\) and evaluate it at the point \(x = 2, y=1, z=-1\).
02

Setting up the Partial Derivative

To find the partial derivative \(\frac{\partial f}{\partial y}\), treat \(x\) and \(z\) as constants and differentiate \(f(x, y, z) = \frac{y}{x+y+z}\) with respect to \(y\).
03

Applying the Quotient Rule

The quotient rule states if you have a function \(u/v\), its derivative is \((v \cdot u' - u \cdot v')/v^2\). Here \(u = y\) and \(v = x+y+z\). Compute \(u' = 1\) and \(v' = 1\) as derivatives with respect to \(y\).
04

Deriving using the Quotient Rule

Apply the quotient rule: \(\frac{\partial f}{\partial y} = \frac{(x+y+z) \cdot 1 - y \cdot 1}{(x+y+z)^2} = \frac{x + z}{(x+y+z)^2}\).
05

Evaluating the Partial Derivative at the Given Point

Substitute \(x = 2\), \(y = 1\), \(z = -1\) into \(\frac{\partial f}{\partial y}\): \(\frac{2 - 1}{(2+1-1)^2} = \frac{1}{2^2} = \frac{1}{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multivariable Calculus
Multivariable calculus is an extension of calculus to functions with more than one variable.
It involves differentiating and integrating functions that depend on several variables, like in our example where the function f depends on x, y, and z.
In contrast to single-variable calculus, operations in multivariable calculus allow us to explore a broader range of mathematical, physical, and engineering applications.
An intuitive way to understand multivariable functions is to think of each variable as representing a dimension in space.
For instance, a function might represent the temperature at each point in a room (a three-dimensional space), with x, y, and z as the spatial coordinates. Working with functions of several variables requires understanding concepts like **gradients**, **curls**, and **divergences**, which describe how functions change across space.
  • **Gradients** provide the direction of greatest change of a function.
  • **Curls** give information about the rotation or swirliness of the field.
  • **Divergences** measure how much a field spreads out from a point.
Partial derivatives, like the one in this exercise, are foundational components in this broader study, contributing to the calculation of these concepts.
Quotient Rule
The quotient rule is a handy tool in calculus for finding the derivative of a ratio of two differentiable functions.
For a function \(f(u, v) = \frac{u}{v}\), the derivative \(f'\) is given by: \[\frac{v \cdot u' - u \cdot v'}{v^2}\]This formula shows how the top and bottom parts of a fraction are handled differently during differentiation.
In our case, we apply the quotient rule to the function \(f(x, y, z) = \frac{y}{x+y+z}\), with \(u = y\) and \(v = x+y+z\).To break it down:
  • The **numerator** is \(u'v - uv'\). Here, \(u'\) (the derivative of \(u\) with respect to \(y\)) is 1, and \(v'\) (the derivative of \(v\) with respect to \(y\)) is also 1.
  • The **denominator** is \(v^2\), which gives us the square of the original denominator \((x+y+z)^2\).
Using this technique, we can find the partial derivative efficiently, which is vital for tackling more complex problems in calculus.
Partial Differentiation
Partial differentiation allows us to differentiate a function with respect to one variable while keeping other variables constant.
This is crucial in multivariable calculus because it helps us understand how a function changes along one particular direction.In our task of finding the partial derivative \(\frac{\partial f}{\partial y}\) of the function \(f(x, y, z) = \frac{y}{x+y+z}\), we treated \(x\) and \(z\) as constant values while differentiating with respect to \(y\).
This reflects only how changes in \(y\) affect the function, assuming \(x\) and \(z\) remain the same.The steps generally involved in the process are:
  • Identify the variable you wish to differentiate concerning.
  • Keep all other variables constant during the differentiation process.
  • Apply relevant differentiation rules, like the quotient rule if the function is a fraction.
This method of differentiation has practical applications in optimization problems and can be applied in fields such as economics, physics, and engineering, where understanding the effect of one variable is essential for planning and design.

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Most popular questions from this chapter

Three alleles (alternative versions of a gene) \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{O}\) determine the four blood types \(\mathrm{A}(\mathrm{AA}\) or \(\mathrm{AO}), \mathrm{B}\) (BB or \(\mathrm{BO} ), \mathrm{O}(\mathrm{OO}),\) and \(\mathrm{AB} .\) The Hardy- Weinberg Law states that the proportion of individuals in a population who carry two different alleles is $$P=2 p q+2 p r+2 r q$$ where \(p, q,\) and \(r\) are the proportions of \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{O}\) in the population. Use the fact that \(p+q+r=1\) to show that \(P\) is at most \(\frac{2}{3}\)

Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. $$f(x, y)=x^{2}+x y+y^{2}+y$$

(a) Find the maximum value of $$ f\left(x_{1}, x_{2}, \ldots, x_{n}\right)=\sqrt[n]{x_{1} x_{2} \cdots x_{n}} $$ given that \(x_{1}, x_{2}, \ldots, x_{n}\) are positive numbers and \(x_{1}+x_{2}+\cdots+x_{n}=c,\) where \(c\) is a constant. (b) Deduce from part (a) that if \(x_{1}, x_{2}, \ldots, x_{n}\) are positive numbers, then $$ \sqrt[n]{x_{1} x_{2} \cdots x_{n}} \leqslant \frac{x_{1}+x_{2}+\cdots+x_{n}}{n} $$ This inequality says that the geometric mean of \(n\) numbers is no larger than the arithmetic mean of the numbers. Under what circumstances are these two means equal?

Find the extreme values of \(f\) on the region described by the inequality. $$ f(x, y)=x^{2}+y^{2}+4 x-4 y, \quad x^{2}+y^{2} \leqq 9 $$

Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. $$ f(x, y, z)=x^{2} y^{2} z^{2} ; \quad x^{2}+y^{2}+z^{2}=1 $$

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