Chapter 11: Problem 12
\(7-30\) Find the first partial derivatives of the function. $$f(x, y)=\frac{x}{(x+y)^{2}}$$
Short Answer
Expert verified
The first partial derivatives are \( \frac{\partial f}{\partial x} = \frac{-x^2 + y^2}{(x+y)^4} \) and \( \frac{\partial f}{\partial y} = \frac{-2x^2 - 2xy}{(x+y)^4} \).
Step by step solution
01
Recognize the Function
We are given the function \( f(x, y) = \frac{x}{(x+y)^2} \). It is a function of two variables \( x \) and \( y \), and we need to find the first partial derivatives with respect to both variables.
02
Find the Partial Derivative with respect to x
To find \( \frac{\partial f}{\partial x} \), we use the quotient rule for differentiation, which is given by \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot \frac{d u}{dx} - u \cdot \frac{d v}{dx}}{v^2} \). Here, \( u = x \) and \( v = (x+y)^2 \). The derivatives are \( \frac{d u}{dx} = 1 \) and \( \frac{d v}{dx} = 2(x+y) \). Applying the quotient rule gives:\[ \frac{\partial f}{\partial x} = \frac{(x+y)^2 \cdot 1 - x \cdot 2(x+y)}{((x+y)^2)^2} = \frac{(x+y)^2 - 2x(x+y)}{(x+y)^4} \]Simplify:\[ \frac{\partial f}{\partial x} = \frac{(x+y)^2 - 2x^2 - 2xy}{(x+y)^4} \]\[ \frac{\partial f}{\partial x} = \frac{x^2 + 2xy + y^2 - 2x^2 - 2xy}{(x+y)^4} \]\[ \frac{\partial f}{\partial x} = \frac{-x^2 + y^2}{(x+y)^4} \]
03
Find the Partial Derivative with respect to y
To find \( \frac{\partial f}{\partial y} \), again use the quotient rule with \( u = x \) and \( v = (x+y)^2 \). The derivatives are \( \frac{d u}{dy} = 0 \) and \( \frac{d v}{dy} = 2(x+y) \). Apply the quotient rule:\[ \frac{\partial f}{\partial y} = \frac{(x+y)^2 \cdot 0 - x \cdot 2(x+y)}{((x+y)^2)^2} = \frac{-2x(x+y)}{(x+y)^4} \]Simplify:\[ \frac{\partial f}{\partial y} = \frac{-2x(x+y)}{(x+y)^4} \]\[ \frac{\partial f}{\partial y} = \frac{-2x^2 - 2xy}{(x+y)^4} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
When you're faced with differentiating a function expressed as a fraction, like turning those fractions into partial derivatives, the quotient rule is your best friend.
It's like a recipe ensuring a smooth differentiation of functions where one part is divided by another. The general formula is:\[ \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot \frac{du}{dx} - u \cdot \frac{dv}{dx}}{v^2}.\]Keep in mind these points when using the quotient rule:
It's like a recipe ensuring a smooth differentiation of functions where one part is divided by another. The general formula is:\[ \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot \frac{du}{dx} - u \cdot \frac{dv}{dx}}{v^2}.\]Keep in mind these points when using the quotient rule:
- Identify the numerator as \( u \) and the denominator as \( v \).
- Differentiating \( u \) and \( v \) separately is crucial.
- Substitute these derivatives into the formula above.
Multivariable Calculus
Moving beyond single-variable calculus, multivariable calculus opens up avenues for exploring functions in two or more dimensions. It's like adding dimensions to a painting, where every axis carries its own exploration challenges.
When dealing with functions of multiple variables, instead of a simple incline or decline, think of it as navigating a complex landscape with valleys and peaks.Understanding its core:
When dealing with functions of multiple variables, instead of a simple incline or decline, think of it as navigating a complex landscape with valleys and peaks.Understanding its core:
- Functions are often written in terms of two variables, such as \( f(x, y) \).
- Each variable influences the function individually and collectively.
- Partial differentiation becomes key, isolating how one variable affects the function while considering others as constants.
Function of Two Variables
Functions of two variables, like \( f(x, y) = \frac{x}{(x+y)^2} \), are foundational in understanding multi-dimensional phenomena. They allow us to study how two separate inputs influence one output.Here's what makes them so valuable:
- They provide a way to model scenarios where effects don't rely on a single input.
- Think about topographic maps, heat distribution, or profit models where both price and quantity interact.
- Such functions are defined over domains in the \(xy\)-plane, functioning like a sheet across this plane representing every possible \(x\) and \(y\) pair.