Chapter 10: Problem 22
Show that \((\mathbf{a} \times \mathbf{b}) \cdot \mathbf{b}=0\) for all vectors a and \(\mathbf{b}\) in \(V_{3}\).
Short Answer
Expert verified
The cross product \\(\\mathbf{a} \\times \\mathbf{b}\\) is perpendicular to \\mathbf{b}\\, making their dot product zero.
Step by step solution
01
Understanding Cross and Dot Product Basics
The expression \(\mathbf{a} \times \mathbf{b}\) denotes the cross product of two vectors \mathbf{a}\ and \mathbf{b}\. The cross product results in a vector that is perpendicular to both \mathbf{a}\ and \mathbf{b}\. The dot product of two vectors results in a scalar (a single number). To show that \(\mathbf{a} \times \mathbf{b}\) \cdot \mathbf{b} = 0\, we must demonstrate that the vector from the cross product is perpendicular to \mathbf{b}\.
02
Applying the Perpendicularity Concept
For two vectors \mathbf{c}\ and \mathbf{d}\, if \mathbf{c} \cdot \mathbf{d} = 0\, then \mathbf{c}\ is perpendicular to \mathbf{d}\. By the definition of the cross product, \(\mathbf{a} \times \mathbf{b}\)\ is perpendicular to both \mathbf{a}\ and \mathbf{b}\. Therefore, the dot product of \mathbf{b}\ with any vector perpendicular to it, such as \(\mathbf{a} \times \mathbf{b}\)\, must be zero.
03
Validation through Mathematical Definition
The mathematical definition of the cross product states that the magnitude of \(\mathbf{a} \times \mathbf{b}\)\ is \left|\mathbf{a}\right| \left|\mathbf{b}\right|\sin(\theta)\, where \(\theta\) is the angle between \mathbf{a}\ and \mathbf{b}\. The direction of this vector is perpendicular to both. Since the dot product of a vector with another vector perpendicular to it is always zero, \(\mathbf{a} \times \mathbf{b}\) \cdot \mathbf{b} = 0\.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is an essential operation involving two vectors in three-dimensional space. When you take the cross product of vectors \(\mathbf{a}\) and \(\mathbf{b}\), the result is another vector. The unique characteristic of this new vector is that it is perpendicular to both \(\mathbf{a}\) and \(\mathbf{b}\). To compute the cross product \(\mathbf{a} \times \mathbf{b}\), you can use the determinant of a matrix that involves the unit vectors \(\mathbf{i}, \mathbf{j}, \mathbf{k}\), and the components of \(\mathbf{a}\) and \(\mathbf{b}\).
- The formula for the cross product is:\[\mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\]
- This expands to:\[(a_2 b_3 - a_3 b_2) \mathbf{i} - (a_1 b_3 - a_3 b_1) \mathbf{j} + (a_1 b_2 - a_2 b_1) \mathbf{k}\]
Dot Product
The dot product is a basic and widely used operation on two vectors yielding a scalar. If you have vectors \(\mathbf{a}\) and \(\mathbf{b}\), the dot product \(\mathbf{a} \cdot \mathbf{b}\) communicates the extent to which two vectors are aligned. The resulting scalar gives a measure of this alignment.
- The formula for the dot product is:\[\mathbf{a} \cdot \mathbf{b} = a_1 b_1 + a_2 b_2 + a_3 b_3\]
- An alternative expression relates it to the cosine of the angle \(\theta\) between the vectors:\[\mathbf{a} \cdot \mathbf{b} = \left|\mathbf{a}\right| \left|\mathbf{b}\right| \cos(\theta)\]
Perpendicular Vectors
Perpendicular vectors occur frequently in vector calculus and indicate a special relationship between two vectors: they meet at a right angle. When vectors \(\mathbf{a}\) and \(\mathbf{b}\) are perpendicular (orthogonal), their dot product is zero: \(\mathbf{a} \cdot \mathbf{b} = 0\) because the cosine of a 90-degree angle is zero.
- This characteristic has practical implications:
- In geometry, it defines orthogonal systems.
- In physics, it underpins analyses where forces or movements are independent.