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Write the next two apparent terms of the sequence. Describe the pattern you used to find these terms. \(\frac{7}{2}, 4, \frac{9}{2}, 5, \ldots\)

Short Answer

Expert verified
The next two terms in the sequence are: 5.5, 6

Step by step solution

01

Identifying the Pattern

First, rewrite the whole numbers as fractions: \(\frac{7}{2}, \frac{8}{2}, \frac{9}{2}, \frac{10}{2}\). Now, it becomes clear that the numerator of the fraction is incrementing by 1 for each subsequent term.
02

Finding the Next Term

To find the next term, we increase the numerator of the last known term (which is 10) by 1, making it 11. So, the next term would be \(\frac{11}{2}\) or 5.5 when written in decimal form.
03

Finding the Second Next Term

Following the same method, to find the term after \(\frac{11}{2}\), we will increase the numerator by 1, making it 12. So, the subsequent term will be \(\frac{12}{2}\), which simplifies to 6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arithmetic Progression
Sequences like the one in the exercise are often associated with arithmetic progression. In a typical arithmetic progression, each term is derived from the previous term by adding a constant difference. The sequence might not seem immediately like an arithmetic progression due to its fraction notation. However, once rewritten using a common format, it becomes evident that the sequence aligns with this concept.
For example, consider the sequence: \(\frac{7}{2}, \frac{8}{2}, \frac{9}{2}, \frac{10}{2}\). The constant difference here is \(\frac{1}{2}\). By recognizing this, you can correctly predict upcoming terms by simply continuing to add \(\frac{1}{2}\) to the numerator.
  • This approach emphasizes the pattern of evenly increasing numerators, typical of arithmetic progressions.
  • Even when numbers appear differently, reducing them to a common form can simplify the identification of such patterns.
Utilizing these principles makes it easier to continue a sequence efficiently.
Fraction Notation
Understanding fractions is crucial when dealing with sequences expressed in this form. Fraction notation helps represent numbers that are not whole, clearly demonstrating the relationships between parts and wholes.
In the given sequence, fractions are used to facilitate a straightforward comparison of each number's magnitude. By rewriting integers as fractions, such as 4 being represented as \(\frac{8}{2}\), analyzing the sequence becomes more accessible. This is because:
  • The numerators are emphasized, allowing a more comfortable visual understanding of the sequence's progression.
  • In cases like this, simplifying fractions can also help in linking them to their whole-number counterparts, thus enhancing comprehension.
Mastering fraction notation will improve problem-solving skills in a variety of mathematical scenarios.
Pattern Recognition
Recognizing patterns is the cornerstone of deciphering and predicting sequences. Pattern recognition involves observing regularities or trends in data. In sequences, recognizing such patterns enables you to anticipate future terms even with incomplete information.
In our sequence, identifying that the numerator is consistently progressing by one is key to predicting upcoming terms:
  • The exercise illustrates how breaking down elements into familiar forms can reveal the underlying structure, returning us to pattern recognition.
  • Upon spotting this, one can continuously forecast the sequence by applying the established pattern.
Pattern recognition skills not only help in mathematics but also in solving real-world problems, as they foster a structured approach to analysis.

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Most popular questions from this chapter

The ball in Exercise 95 takes the following times for each fall. $$ \begin{array}{ll} s_{1}=-16 t^{2}+16, & s_{1}=0 \text { if } t=1 \\ s_{2}=-16 t^{2}+16(0.81), & s_{2}=0 \text { if } t=0.9 \\ s_{3}=-16 t^{2}+16(0.81)^{2}, & s_{3}=0 \text { if } t=(0.9)^{2} \\ s_{4}=-16 t^{2}+16(0.81)^{3}, & s_{4}=0 \text { if } t=(0.9)^{3} \end{array} $$ \(\vdots\) $$ s_{n}=-16 t^{2}+16(0.81)^{n-1}, \quad s_{n}=0 \text { if } t=(0.9)^{n-1} $$ Beginning with \(s_{2}\), the ball takes the same amount of time to bounce up as it does to fall, and so the total time elapsed before it comes to rest is given by \(t=1+2 \sum_{n=1}^{\infty}(0.9)^{n}\) Find this total time.

Find the sum of the convergent series. $$ \sum_{n=0}^{\infty}\left(\frac{1}{2}\right)^{n} $$

The Fibonacci sequence is defined recursively by \(a_{n+2}=a_{n}+a_{n+1},\) where \(a_{1}=1\) and \(a_{2}=1\) (a) Show that \(\frac{1}{a_{n+1} a_{n+3}}=\frac{1}{a_{n+1} a_{n+2}}-\frac{1}{a_{n+2} a_{n+3}}\). (b) Show that \(\sum_{n=0}^{\infty} \frac{1}{a_{n+1} a_{n+3}}=1\).

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The annual spending by tourists in a resort city is \(\$ 100\) million. Approximately \(75 \%\) of that revenue is again spent in the resort city, and of that amount approximately \(75 \%\) is again spent in the same city, and so on. Write the geometric series that gives the total amount of spending generated by the \(\$ 100\) million and find the sum of the series.

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