Chapter 6: Problem 27
Use substitution to find the integral. $$ \int \frac{e^{x}}{\left(e^{x}-1\right)\left(e^{x}+4\right)} d x $$
Short Answer
Expert verified
The solution to the integral is \( \frac{1}{3} \log{|e^x-1|} - \frac{1}{3} \log{|e^x+4|} + C \)
Step by step solution
01
Substitution
We start by substituting \( e^x = u \). Thus, \( dx = du/u \) as \( du = e^x \, dx \). Therefore, the integral becomes \( \int \frac{u}{(u-1)(u+4)} \, du \)
02
Split into Partial Fractions
The integral now can be split into partial fractions. We would solve \(\frac{u}{(u-1)(u+4)} = \frac{A}{u-1} + \frac{B}{u+4}\) for the constants A and B. By solving this, we then find that A = 1/3 and B = -1/3. Thus, the integral becomes \( \int\frac{1}{3(u-1)} - \frac{1}{3(u+4)} \, du \)
03
Integrating the Partial Fractions
We can now integrate each of the fractions separately: \( \frac{1}{3} \, \int \frac{1}{u-1} \, du - \frac{1}{3} \, \int \frac{1}{u+4} \, du \). Solving these gives \( \frac{1}{3} \log{|u-1|} - \frac{1}{3} \log{|u+4|} + C \) where C is the constant of integration.
04
Back substitution
Substitute \( u = e^x \) back into the solution to get the final result in term of x: \( \frac{1}{3} \log{|e^x-1|} - \frac{1}{3} \log{|e^x+4|} + C \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Fraction Decomposition
Partial fraction decomposition is a powerful algebraic technique used in calculus to break down rational expressions into simpler fractions that are easier to integrate. In our given integral, \[\int \frac{u}{(u-1)(u+4)} \, du\]we notice that the denominator can be factored into two linear terms, \((u-1)(u+4)\). By using partial fraction decomposition, we attempt to express this fraction as:
- \(\frac{A}{u-1} + \frac{B}{u+4}\)
Integration Constants
When we calculate indefinite integrals, we include a term known as the "constant of integration," typically represented by the letter C. This constant accounts for any vertical shift in the antiderivative since differentiation eliminates constants.
- In our solution: \(\frac{1}{3} \log{|u-1|} - \frac{1}{3} \log{|u+4|} + C\), the term C represents all potential vertical shifts.
- This means that for any given x, there exist infinitely many antiderivatives corresponding to different values of C.
Natural Logarithm Properties
Natural logarithms, denoted as \(\ln(x)\) or \(\log_e{x}\), have several properties that simplify integration and algebraic manipulations:
- \(\ln(ab) = \ln(a) + \ln(b)\)
- \(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\)
- \(\ln(a^b) = b\ln(a)\)
Definite and Indefinite Integrals
In calculus, integrals are classified as definite or indefinite:
- Indefinite integrals, such as \(\int f(x) \, dx\), provide a family of functions (antiderivatives) and include a constant of integration, C.
- In our exercise, the substitution and subsequent integration with a constant is an example of an indefinite integral.
- Definite integrals, like \(\int_{a}^{b} f(x) \, dx\), calculate the signed area under the curve f(x) from a to b and provide a numerical result. They do not include a constant of integration because they represent a specific value.