/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find the integral. $$ \int(x... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the integral. $$ \int(x+1) \sqrt{x^{2}+2 x+2} d x $$

Short Answer

Expert verified
The integral of \((x+1) \sqrt{x^{2}+2x+2}\) with respect to \(x\) is \(\frac{1}{3}(x^2 + 2x + 2)^{3/2} + C.\)

Step by step solution

01

Substitute

Let \(u = x^2 + 2x + 2\). Calculate the derivative \(du = (2x+2)dx = 2(x+1)dx\). From here, we can express \(dx = du/(2(x+1))\). Replace \(x+1\) and \(dx\) in the integral, resulting in the following formula: \(\int u^{1/2} * du/2 = 0.5 \int u^{1/2} du.\)
02

Integrate

Now perform the integration of \(0.5 \int u^{1/2} du\), which results in \( \frac{1}{3} u^{3/2}\)
03

Back Substitute

Replace \(u\) with \(x^2 + 2x + 2\), resulting in \(\frac{1}{3}(x^2 + 2x + 2)^{3/2}.\) Add the constant of integration, \(C\).

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