Chapter 6: Problem 21
Find the integral involving secant and tangent. $$ \int \sec ^{3} \pi x d x $$
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Chapter 6: Problem 21
Find the integral involving secant and tangent. $$ \int \sec ^{3} \pi x d x $$
These are the key concepts you need to understand to accurately answer the question.
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Prove that \(I_{n}=\left(\frac{n-1}{n+2}\right) I_{n-1},\) where \(I_{n}=\int_{0}^{\infty} \frac{x^{2 n-1}}{\left(x^{2}+1\right)^{n+3}} d x, \quad n \geq 1 .\) Then evaluate each integral. (a) \(\int_{0}^{\infty} \frac{x}{\left(x^{2}+1\right)^{4}} d x\) (b) \(\int_{0}^{\infty} \frac{x^{3}}{\left(x^{2}+1\right)^{5}} d x\) (c) \(\int_{0}^{\infty} \frac{x^{5}}{\left(x^{2}+1\right)^{6}} d x\)
Use a computer algebra system to evaluate the definite integral. $$ \int_{0}^{\pi / 4} \sin 2 \theta \sin 3 \theta d \theta $$
Find the integral. Use a computer algebra system to confirm your result. $$ \int \tan ^{4} \frac{x}{2} \sec ^{4} \frac{x}{2} d x $$
Think About It In Exercises 55-58, L'Hopital's Rule is used incorrectly. Describe the error. \(\lim _{x \rightarrow 0} \frac{e^{2 x}-1}{e^{x}}=\lim _{x \rightarrow 0} \frac{2 e^{2 x}}{e^{x}}=\lim _{x \rightarrow 0} 2 e^{x}=2\)
In Exercises 59 and \(60,\) (a) explain why L'Hôpital's Rule cannot be used to find the limit, (b) find the limit analytically, and (c) use a graphing utility to graph the function and approximate the limit from the graph. Compare the result with that in part (b). \(\lim _{x \rightarrow \infty} \frac{x}{\sqrt{x^{2}+1}}\)
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