/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Use the shell method to set up a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the \(y\) -axis. $$ y=x^{2}, \quad y=4 x-x^{2} $$

Short Answer

Expert verified
The volume of the solid generated by revolving the given region about the \(y\)-axis is \(16\pi/3\) cubic units.

Step by step solution

01

Find intersection points

First, find the intersection points of the two curves by setting the functions equal to each other: \(x^2 = 4x - x^2\). Solving this, we find that \(2x^2 = 4x\), So \(x = 0\) and \(x = 2\). Thus, the limits of integration are \(0\) and \(2\).
02

Visualize and set up Integral

Visualize the region between these curves as a series of vertical strips with width \(dx\) extending from the curve \(y = x^{2}\) to the curve \(y = 4x - x^{2}\). When we revolve this strip about the \(y\)-axis, we get a cylindrical shell with radius \(x\), height given by \((4x - x^{2}) - x^{2} = 4x - 2x^{2}\), and thickness \(dx\). The volume \(dV\) of a thin cylindrical shell is given by \(dV = 2\pi xy \, dx\), where \(x\) is the radius of the shell and \(y\) is the height. Plugging in our values yields \(dV = 2\pi x (4x - 2x^{2}) dx\). The total volume is then obtained by integrating this expression from \(x = 0\) to \(x = 2\).
03

Evaluate the Integral

Now evaluate the integral: \(\int_{0}^{2} 2\pi x(4x - 2x^{2}) dx = 2\pi \int_{0}^{2} (4x^{2} - 2x^{3}) dx = 2\pi \left[ \frac{4}{3}x^{3} - \frac{1}{2}x^{4}\right]_{0}^{2} = 2\pi \left[ \frac{4}{3}(2)^{3} - \frac{1}{2}(2)^{4}\right]\).
04

Simplify the result

Simplify the above expression to get the volume : \(2\pi \left[ \frac{4}{3}(8) - \frac{1}{2}(16)\right] = 2\pi [32/3 - 8 ] = 2\pi × 32/3 - 16\pi = \(16\pi/3\) cubic units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume of Revolution
Understanding the volume of revolution is key to visualizing how a two-dimensional region transforms into a three-dimensional object when rotated around an axis. In calculus, this process is used to calculate the volume of solids with symmetrical properties. By rotating a shape around a chosen axis (in this case, the y-axis), every point of the shape traces a circular path, forming a solid with volume.

The shell method is one such technique for finding the volume of these types of solids. To apply this method, imagine slicing the two-dimensional region into vertical strips. Each thin strip rotates around the y-axis, forming a cylindrical shell. The sum of the volumes of all these 'shells' gives us the total volume of the solid.
Definite Integral Evaluation
Evaluating a definite integral means finding the net area under a curve between two points, which correspond to the limits of integration. In the context of the shell method, the definite integral calculates the total volume by adding up the volumes of infinitely many thin cylindrical shells.

To evaluate the integral, we first identify the integrand, which in this case is the formula for the volume of an individual shell. Then, we use the fundamental theorem of calculus to compute the integral between the lower and upper limits of integration. The result is a numerical value that represents the volume of the solid.
Integration Limits
Integration limits are boundaries within which we evaluate an integral. These limits are essential because they define the region whose volume we're calculating when using the shell method. In our example, the integration limits are the x-values where the curves intersect, which defines the range of the solid created after the revolution.

Choosing the correct limits is crucial for an accurate calculation. In our exercise, we determined the limits to be 0 and 2 by solving the equation where both functions of y equate to each other. Remember that incorrect limits can lead to a wrong volume of the solid.
Cylindrical Shells
Cylindrical shells are the building blocks of the volume we calculate using the shell method. Each shell is a hollow cylinder without the tops or bottoms, like a label on a can. The volume of a single shell is given by the lateral surface area of the cylinder: \(V_{shell} = 2\pi rh\), where \(r\) is the radius (distance to the y-axis in our case), and \(h\) is the height of the shell.

When setting up the integral, each shell's radius is simply the x-value of the strip, and the height is the difference between the two y-values of the functions at that point. We integrate across all shells defined by the limits to find the total volume. A thorough understanding of cylindrical shells helps to grasp the foundations of the shell method.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the differential equation. $$ \frac{d y}{d x}=4-y $$

One hundred bacteria are started in a culture and the number \(N\) of bacteria is counted each hour for 5 hours. The results are shown in the table, where \(t\) is the time in hours. $$ \begin{array}{|l|c|c|c|c|c|c|}\hline t & 0 & 1 & 2 & 3 & 4 & 5 \\\\\hline N & 100 & 126 & 151 & 198 & 243 & 297 \\\\\hline\end{array}$$ (a) Use the regression capabilities of a graphing utility to find an exponential model for the data. (b) Use the model to estimate the time required for the population to quadruple in size.

Volume of a Storage Shed A storage shed has a circular base of diameter 80 feet (see figure). Starting at the center, the interior height is measured every 10 feet and recorded in the table. \begin{tabular}{|l|c|c|c|c|c|} \hline\(x\) & 0 & 10 & 20 & 30 & 40 \\ \hline Height & 50 & 45 & 40 & 20 & 0 \\ \hline \end{tabular} (a) Use Simpson's Rule to approximate the volume of the shed. (b) Note that the roof line consists of two line segments. Find the equations of the line segments and use integration to find the volume of the shed.

The area of the region bounded by the graphs of \(y=x^{3}\) and \(y=x\) cannot be found by the single integral \(\int_{-1}^{1}\left(x^{3}-x\right) d x\). Explain why this is so. Use symmetry to write a single integral that does represent the area.

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the given lines. \(y=2 x^{2}, \quad y=0, \quad x=2\) (a) the \(y\) -axis (b) the \(x\) -axis (c) the line \(y=8\) (d) the line \(x=2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.