/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Find the indefinite integral. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the indefinite integral. $$ \int \frac{x}{\sqrt{9-x^{2}}} d x $$

Short Answer

Expert verified
\(-\sqrt{9 - x^2} + C\)

Step by step solution

01

Set up the substitution

Identify the inner function which is more complicated and could simplify the integral when set as \(u\). The inner function here is \(9-x^2\). Therefore, let \(u = 9 - x^2\). Now, compute the derivative, \(du = -2xdx\). From this, solve for \(dx\), which will be used to substitute \(dx\) in the integral. Therefore, \(dx = - \frac{1}{2x} du\).
02

Substitute in the integral

Replace \(9 - x^2\) with \(u\) and \(dx\) with \(-\frac{1}{2x} du\) in the integral. This results in \(-\frac{1}{2} \int \frac{1}{\sqrt{u}} du\).
03

Evaluate the integral

Now, evaluate the integral. The integral of \(\frac{1}{\sqrt{u}}\) is \(2\sqrt{u}\). Therefore, the integral becomes -\(\sqrt{u}\).
04

Reverse the substitution

Substitute back \(u\) to bring the integral back in terms of \(x\). As we started with \(u = 9- x^2\), replacing gives \(-\sqrt{9 - x^2}\).
05

Add constant of integration

One thing to remember about indefinite integrals is to include the constant of integration, \(C\), at the end of the solution. This gives the final answer as \(-\sqrt{9 - x^2} + C\).

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Most popular questions from this chapter

Consider a particle moving along the \(x\) -axis where \(x(t)\) is the position of the particle at time \(t, x^{\prime}(t)\) is its velocity, and \(\int_{a}^{b}\left|x^{\prime}(t)\right| d t\) is the distance the particle travels in the interval of time. A particle moves along the \(x\) -axis with velocity \(v(t)=1 / \sqrt{t}\) \(t > 0\). At time \(t=1,\) its position is \(x=4\). Find the total distance traveled by the particle on the interval \(1 \leq t \leq 4\).

Use the Second Fundamental Theorem of Calculus to find \(F^{\prime}(x)\). $$ F(x)=\int_{1}^{x} \frac{t^{2}}{t^{2}+1} d t $$

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Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. $$ \int \frac{d x}{25+x^{2}}=\frac{1}{25} \arctan \frac{x}{25}+C $$

Consider the function \(F(x)=\frac{1}{2} \int_{x}^{x+2} \frac{2}{t^{2}+1} d t\) (a) Write a short paragraph giving a geometric interpretation of the function \(F(x)\) relative to the function \(f(x)=\frac{2}{x^{2}+1}\) Use what you have written to guess the value of \(x\) that will make \(F\) maximum. (b) Perform the specified integration to find an alternative form of \(F(x)\). Use calculus to locate the value of \(x\) that will make \(F\) maximum and compare the result with your guess in part (a).

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