/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Find the indefinite integral. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indefinite integral. $$ \int x \sin x^{2} d x $$

Short Answer

Expert verified
The indefinite integral of \(x \sin(x^{2}) dx\) is \(-\frac12 \cos(x^{2}) + C\).

Step by step solution

01

Identifying the Function to Substitute

Looking at the integral, it is seen that \(x^2\) is the function of \(x\) inside the sine function. By setting \(u = x^{2}\), we allow for substitution.
02

Compute Derivative of Substitution Variable

Take the derivative of \(u\) with respect to \(x\). We find that \(du/dx = 2x\). To clear the derivative, we have to solve for \(dx\), which yields \(dx = du/(2x)\).
03

Substitute Identified Function and Its Derivative into the Integral

Replace \(x^{2}\) with \(u\) and \(dx\) with \(du/(2x)\) in the integral. After performing these substitutions, the integral becomes: \(\int \sin(u) du/2\).
04

Evaluate the Integral

The integral of \(\sin(u)\) is \(-\cos(u)\). Therefore, the result of the integral is \(-\cos(u) / 2 + C\), where \(C\) is the constant of integration.
05

Use the Original Variable

Replace \(u\) with \(x^2\). This final substitution gives us \(-\frac12 \cos(x^{2}) + C\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.