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Use the Quotient Rule to differentiate the function. $$ g(t)=\frac{t^{2}+2}{2 t-7} $$

Short Answer

Expert verified
The derivative of the function \( g(t) = \frac{t^{2}+2}{2t-7} \) is \(g'(t) = \frac{2t^{2}-14t-4}{(2t-7)^2}\).

Step by step solution

01

Identify the numerator and the denominator

The numerator of the fraction is \(u(t) = t^{2}+2\) and the denominator is \(v(t) = 2t-7\).
02

Find the derivative of the numerator and the denominator

The derivative of the numerator \(\frac{du}{dt} = 2t\) and the derivative of the denominator \(\frac{dv}{dt} = 2\).
03

Apply the Quotient Rule

By the Quotient Rule, the derivative of the function \(g(t)\) is given by \(\frac{dv/dt \cdot du/dt - u \cdot dv/dt}{(v(t))^2}\), which simplifies to \(\frac{(2t-7) \cdot 2t - (t^{2}+2) \cdot 2}{(2t-7)^2}\).
04

Simplify the Expression

Simplify the expression to get the derivative, \(g'(t) = \frac{4t^{2}-14t-2t^{2}-4}{4t^{2}-28t+49}\), which simplify further to \(g'(t) = \frac{2t^{2}-14t-4}{(2t-7)^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus. It's all about finding how a function changes as its input changes. It's the process of calculating a derivative. When you differentiate a function, you determine the rate at which the function's value changes with respect to changes in its input or variable. This rate of change is called a derivative.

In simpler terms, differentiation helps you answer how fast something is changing at a given point. For example, if you have the position of a car over time, differentiation lets you find the car's speed (its change in position) at any given moment. It's like zooming in on a curve of a graph to see its slope, which represents the rate of change.

Applying differentiation through rules like the Quotient Rule allows you to work with more complex functions, yielding the derivative that tells you how the function behaves at various points.
Calculus
Calculus is the branch of mathematics that studies how things change. It's focused on limits, functions, derivatives, integrals, and infinite series. The two main branches of calculus are differential calculus and integral calculus.

Differential calculus, which includes differentiation, helps us understand how small changes in a variable can affect the function. This is incredibly useful in real-life scenarios where you need to calculate speed, acceleration, or the rate of change in economies and physics.

To perform differentiation, calculus provides tools like the Quotient Rule, which is useful when you have a function represented as a fraction. It helps in differentiating by handling numerators and denominators separately, then applying a specific formula to get the result. With tools like these, calculus allows us to navigate complex scenarios by breaking them down into simpler problems.
Derivatives
Derivatives are the outcomes of differentiation. They give us precise descriptions of how a function changes. Specifically, a derivative at a point provides the slope of the tangent line to the graph of the function at that point.

This concept is crucial because it turns vague ideas of speed, growth, or loss into concrete numbers. For example, in a business context, derivatives can help understand how increasing marketing spend can affect sales growth rates. In calculus, finding a derivative involves following particular calculus rules, like power rules or the Quotient Rule when dealing with functions in fractional form.

In our original problem, we apply the Quotient Rule to find the derivative of the function \( g(t) = \frac{t^2 + 2}{2t - 7} \). This rule systematically breaks down the function into two parts (numerator and denominator), finds their individual derivatives, and combines them according to the Quotient Rule formula. This process provides us with \( g'(t) \), the derivative that explains how \( g(t) \) changes with \( t \). By understanding these derivatives, we can interpret and predict the behavior of functions under various conditions.

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Most popular questions from this chapter

True or False? In Exercises 137-139, determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(y=(1-x)^{1 / 2},\) then \(y^{\prime}=\frac{1}{2}(1-x)^{-1 / 2}\)

If the annual rate of inflation averages \(5 \%\) over the next 10 years, the approximate cost \(C\) of goods or services during any year in that decade is \(C(t)=P(1.05)^{t},\) where \(t\) is the time in years and \(P\) is the present cost. (a) If the price of an oil change for your car is presently \(\$ 24.95,\) estimate the price 10 years from now. (b) Find the rate of change of \(C\) with respect to \(t\) when \(t=1\) and \(t=8\) (c) Verify that the rate of change of \(C\) is proportional to \(C\). What is the constant of proportionality?

In Exercises 107-110, (a) use a graphing utility to find the derivative of the function at the given point, (b) find an equation of the tangent line to the graph of the function at the given point, and (c) use the utility to graph the function and its tangent line in the same viewing window. \(y=\left(t^{2}-9\right) \sqrt{t+2}, \quad(2,-10)\)

Use the position function \(s(t)=-16 t^{2}+v_{0} t+s_{0}\) for free-falling objects. A ball is thrown straight down from the top of a 220 -foot building with an initial velocity of -22 feet per second. What is its velocity after 3 seconds? What is its velocity after falling 108 feet?

Linear and Quadratic Approximations The linear and quadratic approximations of a function \(f\) at \(x=a\) are \(P_{1}(x)=f^{\prime}(a)(x-a)+f(a)\) and \(P_{2}(x)=\frac{1}{2} f^{\prime \prime}(a)(x-a)^{2}+f^{\prime}(a)(x-a)+f(a)\) \(\begin{array}{llll}\text { In Exercises } & 133-136, & \text { (a) find the specified linear and }\end{array}\) quadratic approximations of \(f,\) (b) use a graphing utility to graph \(f\) and the approximations, (c) determine whether \(P_{1}\) or \(P_{2}\) is the better approximation, and (d) state how the accuracy changes as you move farther from \(x=a\). \(f(x)=\tan \frac{\pi x}{4}\) \(a=1\)

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