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Find the derivative of the function. \(g(t)=\frac{\ln t}{t^{2}}\)

Short Answer

Expert verified
The derivative of the function \(g(t)=\frac{\ln t}{{t^{2}}}\) is \(g'(t)=\frac{t - 2\ln t}{{t^{3}}}\).

Step by step solution

01

Identify the given function

The given function is \(g(t)=\frac{\ln t}{{t^{2}}}\). In this case, \(u(t)=\ln t\) is the numerator and \(v(t)=t^{2}\) is the denominator.
02

Differentiate u(t) and v(t)

Find \(u'(t)\) and \(v'(t)\), the derivatives of \(u(t)\) and \(v(t)\) respectively. The derivative of \(\ln t\) is \(\frac{1}{t}\), so \(u'(t)= \frac{1}{t}\). The derivative of \(t^{2}\) is \(2t\), so \(v'(t)= 2t\).
03

Apply the quotient rule

The derivative of the given function \(g(t)\) can be found using the quotient rule for derivatives, which states: \((\frac{u}{v})' = \frac{u'v - uv'}{{v^{2}}}\). Substituting the functions and their derivatives into this formula gives \(g'(t) = \frac{u'(t)v(t) - u(t)v'(t)}{{v(t)^{2}}}=\frac{(\frac{1}{t})*(t^{2}) - (\ln t)*(2t)}{(t^{2})^{2}}\)
04

Simplify the function

Now simplify the derivative function to get the final solution: \(g'(t)=\frac{t - 2\ln t}{{t^{3}}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule for Derivatives
Understanding the quotient rule for derivatives is essential when dealing with ratios of functions, as often seen with rational expressions. The quotient rule is applicable when you have a function that is the quotient of two other functions, say \( u(t) \) and \( v(t) \). The rule states that the derivative of such a function \( g(t) = u(t) / v(t) \) is given by \( g'(t) = (u'v - uv') / v^{2} \), where \( u' \) and \( v' \) symbolize the derivatives of \( u(t) \) and \( v(t) \) respectively.

Applying this to a real case, if you need to differentiate \( g(t)=\frac{\text{ln t}}{t^{2}} \) you would first calculate the derivatives of the numerator and the denominator, then apply the quotient rule. This approach systematically breaks down complex expressions, allowing them to be handled in a stepwise manner, simplifying the differentiation process of rational functions.

Remember to always square the denominator, \( v(t) \) as part of the final step in executing the quotient rule. This common mistake can drastically change the outcome of the problem if overlooked.
Derivative of Natural Logarithm
The derivative of the natural logarithm (ln) is unique compared to other functions and is fundamental in calculus. Given a natural logarithmic function \( u(t) = \text{ln }t \) where \( t > 0 \), the derivative \( u'(t) \) is \( 1/t \).

This relatively simple derivative comes from the deep relationship between exponentials and logarithms. When you are working with logarithmic functions, remembering this derivative can make complex problems much simpler, as it frequently appears in various forms like chain rules or when integrating.

When the natural logarithm is part of a larger expression, such as in a quotient, it’s crucial to apply this derivative correctly. In our problem, the presence of the natural log in the numerator plays a part in the application of the quotient rule, leading to the expression \( (1/t) \). This straightforward differentiation reflects the elegance and simplicity of natural logarithms when performing calculus operations.
Simplifying Derivative Expressions
After applying rules such as the derivative of the natural logarithm and the quotient rule, simplifying the resulting expression is a key final step to reveal the most straightforward form of the derivative. Simplification can involve combining like terms, factoring, and canceling out common factors.

Combining Like Terms: Often, after applying derivative rules, you are left with terms that can be added or subtracted due to their like variables and exponents.
Factoring: Look for common factors in the numerator and denominator which can sometimes be factored out to simplify the expression further.
Canceling Out: In rational expressions, if the numerator and denominator share common terms, you may be able to reduce the expression.

In our given exercise, once the quotient rule is applied to \( g(t)=\frac{\text{ln t}}{t^{2}} \), we simplify the derivative to \( g'(t)=\frac{t - 2\text{ln }t}{{t^{3}}} \), which makes it more understandable and neater, allowing students and mathematicians alike to easily analyze or plug in further values for \( t \). Simplification not only aids in comprehension but is a crucial skill for correctly solving calculus problems.

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Most popular questions from this chapter

True or False? In Exercises 137-139, determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(y\) is a differentiable function of \(u, u\) is a differentiable function of \(v,\) and \(v\) is a differentiable function of \(x,\) then \(\frac{d y}{d x}=\frac{d y}{d u} \frac{d u}{d v} \frac{d v}{d x}\)

In Exercises \(81-88\), (a) find an equation of the tangent line to the graph of \(f\) at the indicated point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the derivative feature of a graphing utility to confirm your results. \(\frac{\text { Function }}{y=4-x^{2}-\ln \left(\frac{1}{2} x+1\right)} \quad \frac{\text { Point }}{\left(0,4\right)}\)

Evaluate the second derivative of the function at the given point. Use a computer algebra system to verify your result. \(f(x)=\cos \left(x^{2}\right), \quad(0,1)\)

Consider the function \(f(x)=\sin \beta x\), where \(\beta\) is a constant. (a) Find the first-, second-, third-, and fourth-order derivatives of the function. (b) Verify that the function and its second derivative satisfy the equation \(f^{\prime \prime}(x)+\beta^{2} f(x)=0\) (c) Use the results in part (a) to write general rules for the even- and odd- order derivatives \(f^{(2 k)}(x)\) and \(f^{(2 k-1)}(x)\) [Hint: \((-1)^{k}\) is positive if \(k\) is even and negative if \(k\) is odd.]

Think About It \(\quad\) Describe the relationship between the rate of change of \(y\) and the rate of change of \(x\) in each expression. Assume all variables and derivatives are positive. (a) \(\frac{d y}{d t}=3 \frac{d x}{d t}\) (b) \(\frac{d y}{d t}=x(L-x) \frac{d x}{d t}, \quad 0 \leq x \leq L\)

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