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Use the Product Rule to differentiate the function. $$ g(x)=\sqrt{x} \sin x $$

Short Answer

Expert verified
The derivative of the function \(g(x) = \sqrt{x}\sin{x}\) is \(g'(x) = \frac{\sin{x}}{2\sqrt{x}} + \sqrt{x} \cdot \cos{x}\).

Step by step solution

01

Apply the Product Rule

We start by applying the Product Rule, which states that the derivative of \(f(x) \cdot g(x)\) is \(f'(x) \cdot g(x) + f(x) \cdot g'(x)\). In this case, \(f(x) = \sqrt{x} = x^{1/2}\) and \(g(x) = \sin{x}\). So we need to first compute \(f'(x)\) and \(g'(x)\), and then use them in the Product Rule formula.
02

Compute the Derivatives of \(f(x)\) and \(g(x)\)

First, the derivative of \(f(x) = x^{1/2}\) is obtained using the power rule. So, \(f'(x) = \frac{1}{2}x^{-1/2}\). And the derivative of \(g(x) = \sin{x}\) is simply \(g'(x) = \cos{x}\). We can now substitute these derivatives back into the Product Rule formula.
03

Substitute Back into the Product Rule Formula

Substituting these values into our formula, we get: \(g'(x) = f'(x) \cdot g(x) + f(x) \cdot g'(x) = \frac{1}{2}x^{-1/2} \cdot \sin{x} + x^{1/2} \cdot \cos{x}\).
04

Simplify the Result

Our result can be simplified by writing \(x^{-1/2}\) as \(1/\sqrt{x}\), yielding the final answer \(g'(x) = \frac{\sin{x}}{2\sqrt{x}} + \sqrt{x} \cdot \cos{x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus. It involves finding the rate at which a function is changing at any given point. This is especially useful when dealing with functions of one variable. By finding the derivative of a function, we learn how the function behaves around that point, such as its increasing or decreasing trends and any points of inflection.

The derivative is often denoted by a prime symbol, like "f'(x)", or by the notation \( \frac{df}{dx} \), which reads "the derivative of \( f \) with respect to \( x \)". When differentiating, it's vital to identify the "inner" and "outer" components of compound functions, which is crucial when applying rules like the Product Rule.

The Product Rule is used when differentiating products of two functions, which helps us uncover the derivative of a multiplied function without distributing it first. Understanding differentiation is key to progressing in mathematical topics that involve calculus.
Trigonometric Functions
Trigonometric functions, like sine and cosine, play a crucial role in calculus and differentiation. They describe the properties of triangles and oscillations, like waves, making them essential in fields ranging from engineering to physics.
  • \( \sin(x) \): Represents the y-coordinate of a unit circle at angle \( x \).
  • \( \cos(x) \): Represents the x-coordinate of a unit circle at angle \( x \).

When differentiating trigonometric functions, there are some specific rules to follow. For example:
  • The derivative of \( \sin(x) \) is \( \cos(x) \).
  • The derivative of \( \cos(x) \) is \( -\sin(x) \).

These transformations are regularly used in calculus problems. Understanding these derivatives allows us to handle more complex problems that involve trigonometric functions as part of larger equations.
Power Rule
The Power Rule is a basic differentiation rule used to find the derivative of functions in the form of \( x^n \). This rule is straightforward: it involves multiplying the power by the coefficient and subtracting one from the power.

For a function \( f(x) = x^n \), the derivative \( f'(x) \) is found using:
  • \( f'(x) = n \cdot x^{n-1} \)

In the context of the given solution, the Power Rule comes into play when differentiating \( \sqrt{x} \). This is equivalent to \( x^{1/2} \), and the Power Rule helps simplify finding \( f'(x) \). The derivative becomes \( \frac{1}{2} x^{-1/2} \), which is simplified further using algebraic manipulations.

Mastering the Power Rule is an essential step in differentiation, as it forms the foundation for dealing with polynomial expressions, making calculus much more approachable for students.

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Most popular questions from this chapter

Let \((a, b)\) be an arbitrary point on the graph of \(y=1 / x, x>0\). Prove that the area of the triangle formed by the tangent line through \((a, b)\) and the coordinate axes is 2.

Find the average rate of change of the function over the given interval. Compare this average rate of change with the instantaneous rates of change at the endpoints of the interval. $$ g(x)=x^{2}+e^{x}, \quad[0,1] $$

Use the position func\(\operatorname{tion} s(t)=-4.9 t^{2}+v_{0} t+s_{0}\) for free-falling objects. To estimate the height of a building, a stone is dropped from the top of the building into a pool of water at ground level. How high is the building if the splash is seen 6.8 seconds after the stone is dropped?

The displacement from equilibrium of an object in harmonic motion on the end of a spring is \(y=\frac{1}{3} \cos 12 t-\frac{1}{4} \sin 12 t\) where \(y\) is measured in feet and \(t\) is the time in seconds. Determine the position and velocity of the object when \(t=\pi / 8\).

If the annual rate of inflation averages \(5 \%\) over the next 10 years, the approximate cost \(C\) of goods or services during any year in that decade is \(C(t)=P(1.05)^{t},\) where \(t\) is the time in years and \(P\) is the present cost. (a) If the price of an oil change for your car is presently \(\$ 24.95,\) estimate the price 10 years from now. (b) Find the rate of change of \(C\) with respect to \(t\) when \(t=1\) and \(t=8\) (c) Verify that the rate of change of \(C\) is proportional to \(C\). What is the constant of proportionality?

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