/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find the derivative of the algeb... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the derivative of the algebraic function. $$ f(x)=\frac{3-2 x-x^{2}}{x^{2}-1} $$

Short Answer

Expert verified
The derivative of the function \(f(x)=\frac{3-2x-x^2}{x^{2}-1}\) is \(f'(x) = \frac{(x^{2} - 1)*(-2 -2x) - (3-2x-x^2)*(2x)}{(x^{2}-1)^2}\).

Step by step solution

01

Identify the functions

For the given function \(f(x)=\frac{3-2x-x^2}{x^{2}-1}\), identify the numerator as Function1(\(f_1\)) and the denominator as Function2(\(f_2\)). So, \(f_1(x) = 3-2x-x^2\) and \(f_2(x) = x^{2}-1\).
02

Find derivatives of the constituent functions

Find the derivatives of the individual functions. The derivative of \(f_1(x) = 3-2x-x^2\) is \(f_1'(x) = -2 -2x\). The derivative of \(f_2(x) = x^{2}-1\) is \(f_2'(x) = 2x\).
03

Apply the Quotient Rule

Apply the quotient rule \((f/g)' = (g*f' - f*g')/g^2\). Substitute \(f_1, f_1', f_2, f_2'\) into the quotient rule equation to obtain the derivative of the function \(f(x) = \frac{f_2(x)*f_1'(x) - f_1(x)*f_2'(x)}{f_2(x)^2}\). This gives us \(f'(x) = \frac{(x^{2} - 1)*(-2 -2x) - (3-2x-x^2)*(2x)}{(x^{2}-1)^2}\). Simplify the equation to obtain the final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
When dealing with derivatives of rational functions, the Quotient Rule becomes a necessary tool. A rational function is structured as a fraction of two polynomial expressions. To differentiate such a function, the Quotient Rule formula is used. It can be remembered with the saying "low d high minus high d low, over the square of the bottom we go." This means if you have a function \( f(x) = \frac{u(x)}{v(x)} \), the derivative \( f'(x) \) is given by:
  • Numerator: Multiply the denominator \( v(x) \) by the derivative of the numerator \( u'(x) \) (low d high).
  • Subtract the product of the numerator \( u(x) \) and the derivative of the denominator \( v'(x) \) (high d low).
The complete expression under the Quotient Rule becomes: \[ f'(x) = \frac{v(x) u'(x) - u(x) v'(x)}{[v(x)]^2} \] Remember that although the steps might seem complex, each component follows specific differentiation rules. This approach helps ensure no errors in calculations, preserving the order of operations accurately.
Algebraic Functions
Algebraic functions, like the one in our exercise, are formed from algebraic expressions using operations such as addition, subtraction, multiplication, and division. They often involve polynomials, which are expressions consisting of variables raised to integer powers and multiplied by coefficients. For the function \( f(x) = \frac{3-2x-x^{2}}{x^{2}-1} \), the numerator \( 3-2x-x^{2} \) and the denominator \( x^{2}-1 \) are both polynomial expressions.
  • The numerator is a quadratic polynomial, structured as \( ax^2 + bx + c \), where \( a = -1 \), \( b = -2 \), and \( c = 3 \).
  • The denominator is also a quadratic polynomial but has no constant term, appearing as \( x^2 - 1 \).
Each polynomial's simplicity allows us to find derivatives using straightforward differentiation rules, such as the power rule. Understanding these basic algebraic structures is vital, as they form the backbone of more complex mathematical functions.
Calculus Basics
Calculus provides the fundamental language for understanding changes in mathematics. The two main branches are differential calculus and integral calculus. Differential calculus is primarily concerned with finding the derivative of a function, which represents the rate at which the function's value changes with respect to its independent variable. This is essential for understanding the slopes of tangent lines, optimizing functions, and predicting behavior in dynamic systems.
  • The derivative gives insights into how "sensitive" a function is to changes in its input.
  • It offers a way to identify increasing or decreasing trends as well as points of inflection.
For any rational function, employing the derivatives of its polynomial components is crucial. Mastery of basic rules like the power rule, the product rule, and of course, the quotient rule, is needed to handle differentiation of more complex expressions. Calculus is not just about finding derivatives but understanding their applications in real-world problems and abstract mathematics.

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Most popular questions from this chapter

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In Exercises 107-110, (a) use a graphing utility to find the derivative of the function at the given point, (b) find an equation of the tangent line to the graph of the function at the given point, and (c) use the utility to graph the function and its tangent line in the same viewing window. \(f(x)=\sqrt{x}(2-x)^{2}, \quad(4,8)\)

Linear and Quadratic Approximations The linear and quadratic approximations of a function \(f\) at \(x=a\) are \(P_{1}(x)=f^{\prime}(a)(x-a)+f(a)\) and \(P_{2}(x)=\frac{1}{2} f^{\prime \prime}(a)(x-a)^{2}+f^{\prime}(a)(x-a)+f(a)\) \(\begin{array}{llll}\text { In Exercises } & 133-136, & \text { (a) find the specified linear and }\end{array}\) quadratic approximations of \(f,\) (b) use a graphing utility to graph \(f\) and the approximations, (c) determine whether \(P_{1}\) or \(P_{2}\) is the better approximation, and (d) state how the accuracy changes as you move farther from \(x=a\). $$ \begin{array}{l} f(x)=x \ln x \\ a=1 \end{array} $$

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